|
It's pretty straightforward, what bit is worrying you ?
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
how xml and xslt work together?? how do they link to each other eg. codes that make them work together?? can someone provide a example??
Han
|
|
|
|
|
You'd probably be better off asking a question like this in the XML / XSL forum. 
Picture a huge catholic cathedral. In it there's many people, including a gregorian monk choir. You know, those who sing beautifully. Then they start singing, in latin, as they always do: "Ad hominem..."
-Jörgen Sigvardsson
|
|
|
|
|
Please do NOT post programming questions or ads to this forum
TOXCCT >>> GEII power
[toxcct][VisualCalc]
|
|
|
|
|
|
|
Ian Darling wrote:
Well whaddyaknow, it works
If you liked that, try using ![Good Stuff | [The good stuff]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/vegemite.gif) for VB and ![Green Alien | [Alien]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/alien.gif) for AJAX.
Jonathan Newman
blog.nonny.com [^]
|
|
|
|
|
A document in xslt language tells to an xslt prosessor how we want an xml document to be transformed. The output can be xml too.
The xslt documents are xml files, but restricted to the xslt schema.
At my article http://www.codeproject.com/aspnet/CXML.asp[^] i use xslt in the IIS/aspx. 
|
|
|
|
|
Hi friend,
I am developing a web application and using XML files to store data.
I want to display data of an xml file using XML stylesheet. I found tutorials regarding this but everywhere the extension of xml stylesheet is XSL. and in .net I found that file with .XSLT file.
I used that file but when I tried to view XML file in the browser it gives error that any html key word like "HTML","BODY","H1" may not be used here.
What does it mean?
Can any one tell me how to use xmlstylesheet to display xml file on browser other than the typical way?
thank u all in advance.
|
|
|
|
|
You can use the .xsl extension if that's what the browser reqires.
Christian Graus - Microsoft MVP - C++
|
|
|
|
|
I have a XML file:
<CARO_BOARD row=10 col=10>
<CHESS x=1 y=1 sign="X"/>
<CHESS x=1 y=2 sign="0"/>
<CHESS x=3 y=1 sign="X"/>
<CHESS x=4 y=4 sign="0"/>
</CARO_BOARD>
I want to use XSLT to show this file as table(rows=10 and cols=10) and the value in cell(1,1) is 'X',the value in cell(1,2) is '0'...Others cell is NULL.
Please tell me a solution.
Thanks.
-- modified at 2:30 Friday 23rd September, 2005
|
|
|
|
|
Hope this sample XSL file will work for you.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table border="2" rows="10" cols="10">
<xsl:for-each select="CARO_BOARD/CHESS">
<xsl:variable name="test_x" select="@x" />
<xsl:variable name="test_y" select="@y" />
<tr>
<xsl:if test="$test_x =1 and $test_y=1" >
<td><xsl:value-of select="@sign"/></td>
<td>NULL</td>
</xsl:if>
</tr>
<tr>
<xsl:if test="$test_x =1 and $test_y=2" >
<td>NULL</td>
<td><xsl:value-of select="@sign"/></td>
</xsl:if>
</tr>
<xsl:comment>You can include more if statements </xsl:comment>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
-- modified at 5:05 Tuesday 27th September, 2005
|
|
|
|
|
Thanks a lot!
But the number of rows(=10) and the number of cols(=10) can be changed.I don't want to hard code like "
"
So is there a solution?
|
|
|
|
|
Actually using DHTML it is possible to change velues of attributes in HTML tag but i think it'll be difficult to use in XSL file but i'll try to find out solution of this problem.
|
|
|
|
|
Finally i have done what u actually want
Let this is ur XML file in which u have defined row,col and border
<CARO_BOARD row="3" col="10" border="3">
<CHESS x="1" y="1" sign="X"/>
<CHESS x="1" y="2" sign="0"/>
<CHESS x="3" y="1" sign="X"/>
<CHESS x="4" y="4" sign="0"/>
</CARO_BOARD>
----------------------------------------
In this xsl we can use xsl:attribute-set to set attributes of table.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:attribute-set name="set_table">
<xsl:attribute name="border">
<xsl:variable name="chk_border" select="//@border" />
<xsl:value-of select="$chk_border"/>
</xsl:attribute>
<xsl:attribute name="cols">
<xsl:variable name="chk_cols" select="//@col" />
<xsl:value-of select="$chk_cols"/>
</xsl:attribute>
<xsl:attribute name="rows">
<xsl:variable name="chk_rows" select="//@row" />
<xsl:value-of select="$chk_rows"/>
</xsl:attribute>
</xsl:attribute-set>
<xsl:template match="/">
<html>
<body>
<table xsl:use-attribute-sets="set_table">
<xsl:for-each select="CARO_BOARD/CHESS">
<xsl:variable name="test_x" select="@x" />
<xsl:variable name="test_y" select="@y" />
<tr>
<xsl:if test="$test_x =1 and $test_y=1" >
<td><xsl:value-of select="@sign"/></td>
<td>NULL</td>
</xsl:if>
</tr>
<tr>
<xsl:if test="$test_x =1 and $test_y=2" >
<td>NULL</td>
<td><xsl:value-of select="@sign"/></td>
</xsl:if>
</tr>
<xsl:comment>You can include more if statements </xsl:comment>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
please let me know if u have any further query.
-- modified at 2:47 Monday 3rd October, 2005
|
|
|
|
|
Hi,
I was wondering whether with all these ASP.NET controls available, is XSLT still a good technology to persue? I know that its still the best way to transform XML into other formats, but if we are only interested in dragging data off a DB and displaying on web pages, wouldn't things like ASP.NET DataGrids/Lists etc. be a better choice?
We used to do a lot of XSLT trans when we were using classic ASP (we kindda hated the ASP Design Time Controls).
I kindda get the impression that ASP.NET Server controls wouldn't go well with XSL (e.g. you can't build a web page containing server controls through a XML->XHTML transform using XSL, right?).
Cheers,
Sameera
|
|
|
|
|
Hi Everyone,
I generate an xml file like:
<links><title>sth..
<desc>sth desc
<title>sth..
<desc>sth desc
and I use ASP to parse and display it in a webpage, my asp code works very well to most of the xml files, but there is one file it can not parse, and if I change the "sth desc" in the <desc> tag, it works fine.
Because the desc comes from database, I wonder if there are some limited (like length or special charaters)for the content in the tag?
Please help me!!
Thanks a lot in advance!
Alan
Alan Shen
MCAD for .NET Version
^~^~^~^~^~^~^~^~^~^~^
Great idea is the beginging of success!
|
|
|
|
|
this probably an easy question but i am new to xml. how do i use an xml document to store informatiion needed by my program? i know how to create the xml document itself but dont know how to do any thing with it after that (including opening it so the program can access it, compare strings to the data in the xml document, and write to the document from the program).
i hope this is an easy question for someone to answer. any help would be greatly apprectiated. examples of code would be extremely helpful.
 Kyle
|
|
|
|
|
Hi All,
How can I pass the value of an element to a Javascript function in an XSL file?
Here is a piece of my XSL file:
<xsl:for-each select="CALL-HISTORY/SEGMENT">
<tr onMouseOver="Over('MCF', 'DWS5',this)" onMouseOut="Out(this)">
<td> <NOBR><xsl:value-of select="TIME-RECORDED"/></NOBR> </td>
I need to replace the 'MCF' in the second line with the value of whatever is in:
<xsl:value-of select="OPERATOR"/>
I thought there might be a way to save off the value of the OPERATOR so that I can pass it to the Over() Javascript function.
Can anyone give me any guidance on this?
I hope this is clear, and appreciate any help.
Thanks,
Melena
|
|
|
|
|
Hi All,
I have found the resolution to my problem.
I used the same format as the xsl code below, which allowed me to pass
the <xsl:value-of...> values to my Javascript program.
<xsl:attribute name="onmouseover">
popUp('<xsl:value-of select="MENUNAME"/>',event)
</xsl:attribute>
<xsl:attribute name="onmouseout">
popDown('<xsl:value-of select="MENUNAME"/>')
</xsl:attribute>
Melena
-- modified at 19:18 Monday 19th September, 2005
|
|
|
|
|
my problem is that i have an excel sheet which should be converted into xsd,xmldoc,and stylesheet.please tell me the exact procedure to do the above explained task.
yeswanth reddy
|
|
|
|
|
Hi Friends,
I have one XML file with 4 tables in it and they r related with each other.
I want data from one table but the depending on the value of key in the other tabel.
It like we write queries for joins in sql or nested query in sql.
Is it possible?
If it is then plz tell me how to do that.
Thank u all in advance
|
|
|
|
|
Help...
I am after a way to display a DataGrid's xml (run through xls) and re-dislayed as html. I am getting the Datagrid xml using the underlying dataset's GetXML() method.
If I have 2 differing datagrids on the page, I want to be able to iteratively loop through each DG's xml via xsl, in each datagrid, and send the resulting html off in an email. Is ther esome way I can use the same template to loop through the 2 samples (and potentially others) below? These 2 xml blobs are part of 1 larger one.
2 xml samples from each data grid is below:
<NewDataSet> <person> <id>1</id> <firstName>Bob</firstName> <lastName>Smith</lastName> </person> <person> <id>2</id> <firstName>Tom</firstName> <lastName>Piper</lastName> </person> <person> <id>3</id> <firstName>Peter</firstName> <lastName>Piper</lastName> </person> </NewDataSet>
<NewDataSet> <Position> <KeyCol>1</KeyCol> <Classification>APS 3</Classification> <Number>5</Number> <SupervisorNumber>5476</SupervisorNumber> <CreationDate>30/08/2005</CreationDate> <EndDate>15/09/2005</EndDate> </Position> <Position> <KeyCol>2</KeyCol> <Classification>APS 5</Classification> <Number>55</Number> <SupervisorNumber>45476</SupervisorNumber> <CreationDate>31/08/2005</CreationDate> <EndDate>14/09/2005</EndDate> </Position> </NewDataSet>
|
|
|
|
|
This file is part of Windows SharePoint Services (WSS) and is used to store information about themes. Here is a snippet of the contents:
<spthemes xmlns="http://tempuri.org/SPThemes.xsd">
<templates>
<templateid>none
<displayname>No Theme(Default)
<description>Description
<thumbnail>../images/thnone.png
<preview>../images/thnone.gif
<templates>
<templateid>af.........etc
I am try to write a bit of code that will find a node using
node = doc.SelectSingleNode("/SPThemes/Templates[TemplateID='SOME_THEME_NAME']");
This bit if code works for an xml file that does not contain a namespace (i.e. in the xml sample above "xmlns="http://tempuri.org/SPThemes.xsd"), but with a namespace the code will not work.
Any ideas will be mucg appreciated
|
|
|
|
|
The xml did not display correctly above, therefore here is an encoded version
<?xml version="1.0" encoding="utf-8"?>
<SPThemes xmlns="http://tempuri.org/SPThemes.xsd">
<Templates>
<TemplateID>none</TemplateID>
<DisplayName>No Theme(Default)</DisplayName>
<Description>Description</Description>
<Thumbnail>../images/thnone.png</Thumbnail>
<Preview>../images/thnone.gif</Preview>
</Templates>
<Templates>
<TemplateID>af......etc
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
![Jig | [Dance]](https://codeproject.freetls.fastly.net/script/Forums/Images/jig.gif)
