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thanks brother the problem is in allocation memory destructr
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In your input function (istream& operator>>(istream& i,produit&p), it is possible to write something into p.edsignation without it being allocated.
To solve this, you'd need to have a char* variable with sufficient length to hold any entered designation and then allocate your designation based on this.
e.g.
istream& operator>>(istream& i,produit&p)
{
if(p.edsignation)
delete [] p.edsignation;
i>>p.code;
char d[1024];
i>>d;
p->edsignation=new char[strlen(d)+1];
strcpy(p->edsignation,d);
return i;
}
modified 13-Sep-18 21:01pm.
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As well as the problem that Thaddeus mentioned your assignment operator is going to leak memory. If you changed your code to use std::string instead of messing about with character arrays and manual memory management the problem would go away. If you used std::string you wouldn't need a copy constructor, assignment operator or destructor so it looks like a win all round to me.
And just about as I was going to hit send I noticed that your copy constructor and destructor doesn't update the static data member appropriately either.
Cheers,
Ash
PS: You might like to consider binning all the explicit this->, there's no place in your code where you actually need it and it doesn't make your code any easier to read.
PPS: And the same goes for void as well.
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Hi all,
If i have more then one hard disk in my system then how can i get its logical drive information in a format like Hard disk first then C:/,D:/...Then Hard disk2 E:/,F:/...
GetLogicalDrive() function retrieves all the Logical drives.
How can i do this???
Thanks in advance...
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GetLogicalDrives returns an integer where each bit represents a drive letter which is either present (1) or not (0).
The least significant bit means A: and then each next bit is one letter up. So in order to check for the presence of drive C:, you'd test the 3rd bit:
if(GetLogicalDrives() & 4)
printf("Drive C: is present.");
The number 4 to AND with is represented as 00000000000000000000000000000100 in binary, so in effect you check if the 3rd bit is set.
You can use GetDriveType[^] to determine if a drive is a hard disk or something else, like a CD-ROM or network drive.
modified 13-Sep-18 21:01pm.
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I know of three ways:
1.
There are a number of Win32 functions for this in kernel32.dll; they include GetDriveType, GetVolumeInformation, GetDiskFreeSpaceEx, and maybe more.
2.
reading some keys in the registry. This is not recommended, and may trigger a UAC dialog, or fail, for non-admin accounts under Vista/Win7.
3.
the WMI classes provide a lot of information (e.g. Win32_DiskDrive, Win32_LogicalDiskToPartition, Win32_PhysicalMedia,
Win32_CDROMDrive). WMI works like a database, and it allows to query for other systems on the network.
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learningvisualc wrote: How can i do this???
Are you wanting to know what logical drives belong to each physical drive? If so, see here. It's VB, but can easily be converted.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Man who follows car will be exhausted." - Confucius
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Hi i am using vc++ 6.0 MSCOMM for serial communication i have to read data(4 bytes) and display from serial port.
ex: data format is
88 84 10 02 (4 bytes data from port)
C6 1E 10 02 (Received Data) but i have to display 88 84 but i am getting C6 and 1E.
my code is:
VARIANT data;
BSTR k;
static char dbuff[4];
int dcount=0;
CString data;
if(m_mscom.GetCommEvent()==2) // Receiving data from port
{
data=m_mscom.GetInput();
k=data.bstrVal;
dbuff[dcount] = char (k[0]);
dcount++;
if(dcount == 4)
{
dcount=0;
data.Format ("%02X%02X%02X%02X",(unsigned char)dbuff[0],(unsigned char)dbuff[1],(unsigned char)dbuff[2],(unsigned char)dbuff[3]);
}
}
please help what is the wrong in my code, thanks in advance,please give me one example how use BYTE to read the data
-- Modified Sunday, January 9, 2011 11:06 PM
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The values 0x88 and 0x84 are the characters ê and ä from the extended ASCII table.
Seeing how these characters are changed but the lower ones (from the 128 character ASCII table) are not, it would appear these characters get translated somewhere to another code page; most likely either on the sender's side or in the data.Format call.
modified 13-Sep-18 21:01pm.
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You should not be using either CString or char for your data input, unless you can guarantee that it will be ASCII characters. Use a BYTE type to ensure that your data is presented as received and not converted on the way.
I must get a clever new signature for 2011.
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I am having problems with populating an array with int numbers. Since I am a new programmer, I do not know why my VS 2008 is not completing the code block. In other words when I execute the program, a blank console screen opens. I then input a number and press enter. After I press enter the program stops in a suspended state. What I have discovered is that I have to input a \o for the program to know that it is the end of my input. I though thought that when I pressed enter, VS 2008 would automatically place this end of string designator.
Secondly, I have problems with index variable. When I loop one time or when I press enter after inputing a number, my index number advances to 8. My question is why the index does not advance to 2?
#include <stdio.h>
int const limit = 8;
int numbers[limit];
int main(void)
{
for(int index = 0; index < limit; index++)
{
scanf("%d", &numbers[limit]);
}
return 0;
}
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Here is the problem:
scanf("%d", &numbers[limit]);
scanf("%d", &numbers[index]);
Mike Certini wrote: What I have discovered is that I have to input a \o for the program to know that it is the end of my input.
This is not true. When you enter the limit-th number the loop will end and the program will exit.
Mike Certini wrote:
Secondly, I have problems with index variable. When I loop one time or when I press enter after inputing a number, my index number advances to 8. My question is why the index does not advance to 2?
Actually it is incremented by 1 after each iteration (index++ part of your for loop) but you are indexing with wrong variable (I pointed out this problem at the start of my answer).
I hope this helps.
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Nuri,
Oh, my....
I feel so dumb.
Thank you for your help.
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Hi All
I create a SDI project to implement splitting window using CSplitterWnd and OnCreateClient (VC 6.0).
In MainFrm.h, two CSplitterWnd member variables are declared
public:
CMySplitter wndSplitter_horizontal;
CMySplitter wndSplitter_erect;
In MainFrm.cpp the OnCreateClienct function is as follows
BOOL CMainFrame::OnCreateClient(LPCREATESTRUCT lpcs, CCreateContext* pContext)
{
if(wndSplitter_horizontal.CreateStatic(this,2,1)==NULL)
return FALSE;
wndSplitter_horizontal.CreateView(0,0,RUNTIME_CLASS(CMonitorTopView),CSize(50,50),pContext);
if(wndSplitter_erect.CreateStatic(&wndSplitter_horizontal,1,2,WS_CHILD|WS_VISIBLE, wndSplitter_horizontal.IdFromRowCol(1, 0))==NULL)
return FALSE;
wndSplitter_erect.CreateView(0,0,RUNTIME_CLASS(CViewRight),CSize(220,220),pContext);
wndSplitter_erect.CreateView(0,1,RUNTIME_CLASS(CViewRight),CSize(220,220),pContext);
return TRUE;
}
It works fine when a CEditView based view 'CViewRight' or 'CViewLeft' is linked to the pane with CreateView(), but failed when a CFormView based view 'CViewRight_Dlg1111' , 'CMonitorTopView' or 'CMonitorRightView' is linked to the pane, though compiling is successful.
'CViewRight_Dlg1111' is created as follows,
(1) First create a dialog resource (IDD_Dlg_1111)
(2)Invoke the 'New Class' dialog box
Class Type: MFC class
Base Class: CFormView
Dialog ID: IDD_Dlg_1111
Creating 'CMonitorTopView' and 'CMonitorRightView' follows the same way.
Also, I find that the program works fine when classes derived from CEditView, CTreeView, CView are linked to the pane .
i do not know why. Please help
I would like the program to deploy the multi-pane layout only when the user clicking a menu item, How to do this.
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Please see the implementation of the derived constructor
in this[^] example...
(there are no dialog-related words inside)
They sought it with thimbles, they sought it with care;
They pursued it with forks and hope;
They threatened its life with a railway-share;
They charmed it with smiles and soap.
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salut a tous, j'ai une question a propos le traitement bit à bit dans le langage C : 
* comment accéder au bits d'une variable quelconque et, effectivement, les modifier( les bits) tantot à 1 tantôt a 0 pour former ce qu'on appelle tableau de bits
et merci
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You will get a better response if you ask your question in English. If English is not your first language, try one of the online translation services.
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Please use English to describe your problem because most of us do not speak French.
(the same as above with Google translate converted to french: S'il vous plaît utiliser l'anglais pour décrire votre problème parce que la plupart d'entre nous ne parlent pas français. )
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> Leela: Fry, you're wasting your life sitting in front of that TV. You need to get out and see the real world.
Fry: But this is HDTV. It's got better resolution than the real world <
>Nothing is free in the universe.<
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Translating your question, I think this is what you mean:
"Hi everyone, I have a question about handling individual bits in C. 
How can I access the bits of a variable and change them to either a 1 or 0."
This[^] should contain the requested info with more details on specifics in the 'See also'.
modified 13-Sep-18 21:01pm.
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Hi,
a 32-bit integer would have its bits numbered 0 to 31 from right to left.
their value corresponds to 1<<n where="" n="" is="" the="" bit="" number.
setting="" a="" accomplished="" with="" bitwise-or="" operator,="" symbol="" |
clearing="" bitwise-and="" &
warning:="" clearing="" done="" by="" keeping="" bits="" you="" do="" not="" want="" to="" be="" cleared,="" that="" complement="" of="" one(s)="" get="" rid="" of.
so="" following="" will="" change="" 5="" into="" 6:
<pre="">
int i=5;
int bit1=1<<1; // which is 2
int bit0=1<<0; // which is 1
i=i|bit1; // now i holds 7
i=i&~bit0; // keeping everything but bit0 yields 6
An alternative way of clearing a bit is first setting, then flipping it; flipping is handled by the bitwise-XOR, the symbol is ^.
i=5;
i=i|bit1;
i=(i|bit0)^bit0;
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Hi All,
I am not able to Contents of File when it exceeds length of 1024.
CFile file;
if(file.open("C:\\users\\rakesh\\Desktop\\myText.xml",CFile::modeRead))
{
return false;
}
TCHAR buffer[100000];//say content is very Big
file.read(buffer,100000);
file.close();
I am not able to get the Contents into Buffer. But i am able to get the Length of the File
with int len = file.GetLength(). I am getting Junk into Buffer.
What may be the reason i am not able to get it into buffer.
Uday.
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janaswamy uday wrote: file.read(buffer,100000);
You should always check the return value of an API function call.
See, for instance, the code sample in the _read documentation page[^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Try Using
CStdioFile .
Regards,
Paresh.
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janaswamy uday wrote: if(file.open("C:\\users\\rakesh\\Desktop\\myText.xml",CFile::modeRead))
What you have posted will not even compile. That aside, this should be:
if (! file.Open("C:\\users\\rakesh\\Desktop\\myText.xml", CFile::modeRead))
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Man who follows car will be exhausted." - Confucius
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