Re: project - Android Discussion Boards

I have been evaluating Xamarin for doing Android development in C#. Seems really good, but coming from doing Android dev with Eclipse and Java, I just cannot find any way to justify the $299 for Indie license or the $999 for Business.

Anyone have any thoughts, suggestions, pro's or con's that they could share?

"I've seen more information on a frickin' sticky note!" - Dave Kreskowiak

My only comment would be, if you are doing this development in order to make money then $299, or even $999, is probably a worthwhile investment.

Veni, vidi, abiit domum

Definitely! I really like it a lot. Especially the $999 Business license with its integration with Visual Studio.

"I've seen more information on a frickin' sticky note!" - Dave Kreskowiak

Which means you also must pay a visual studio license? Or does it work with express editions?

The $999 is for Xamarin's Business version of their package. As far as for VS Express Editions, this is off Xamarin's blog site:

Our Visual Studio Extensions for iOS and Android support any <big></big>non-Express editions of Visual Studio 2010, Visual 
Studio 2012 and Visual Studio 2013

http://xamarin.com/faq

"I've seen more information on a frickin' sticky note!" - Dave Kreskowiak

public class MainActivity extends Activity {
ListView lv;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lv=(ListView)findViewById(R.id.listView1);

String[] Wishlist={"VisitTop10beaches","Adventures","Sports","Camp Site","Visit10Beautyfull City","VisitOneOfSevenContients","VisitTopCasinos","OwnadreamCar","VisitSevenWondersOfTheWorld","HolyPalces","UniqueTransportModes"};
ArrayAdapter adapter=new ArrayAdapter(this, android.R.layout.simple_list_item_1,Wishlist);

lv.setAdapter(adapter)
can anyone hlepme how to code for wen i click on listview its should go to listview b i mean a b c a 1.1 1.2 1.3
b 2.2 2.3 2.4 c 2.4.2.5 all should be in signle screen

Please stop reposting the same question over and over. If you have more information to add then edit your original.

Veni, vidi, abiit domum

can any one tell me i have a list 10 items wen i click it goes to another list view but i want wen i click on item it goes to another list view with image n text plz help mail youre reply in this id sallukhan2011@live.com wat code i have done is this main xml
<relativelayout xmlns:android="http://schemas.android.com/apk/res/android"
="" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:paddingbottom="@dimen/activity_vertical_margin" android:paddingleft="@dimen/activity_horizontal_margin" android:paddingright="@dimen/activity_horizontal_margin" android:paddingtop="@dimen/activity_vertical_margin" tools:context=".MainActivity">

<listview
android:id="@+id/listView1"
="" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_alignparentleft="true" android:layout_alignparenttop="true">

beach xml

<linearlayout xmlns:android="http://schemas.android.com/apk/res/android"
="" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical">

<listview
android:id="@+id/listView2"
="" android:layout_width="match_parent" android:layout_height="wrap_content">

main actvity
package com.example.wishfairy;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class MainActivity extends Activity implements OnItemClickListener {
ListView lv;
String[] Wishlist={"VisitTop10beaches","Adventures","Sports","Camp Site","Visit10Beautyfull City","VisitOneOfSevenContients","VisitTopCasinos","OwnadreamCar","VisitSevenWondersOfTheWorld","HolyPalces","UniqueTransportModes"};

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lv=(ListView)findViewById(R.id.listView1);
lv.setAdapter(new ArrayAdapter<string>(this,
android.R.layout.simple_list_item_1, Wishlist));
lv.setOnItemClickListener(this);
}

@Override
public void onItemClick(AdapterView arg0, View arg1, int arg2,
long arg3) {
// TODO Auto-generated method stub
Intent intent;
switch (arg2) {
case 0:
intent= new Intent(this,VisitTop10beaches.class);
startActivity(intent);
break;
case 1:
intent=new Intent(this,Adventures.class);
startActivity(intent);
break;

default:
break;
}
}

}

vistop beaches .java
package com.example.wishfairy;

import android.os.Bundle;
import android.provider.ContactsContract.CommonDataKinds.Im;
import android.widget.ArrayAdapter;
import android.widget.ImageView;
import android.widget.ListView;

public class VisitTop10beaches extends MainActivity{
ListView lv;

String[] Wishlist2={"Seychelles",
"Maldivas",
"Bora Bora Tahiti",
"The Hampton New York",
"Lanikai Beach, Hawai",
"Nantucket Island, Massachusetts",
"Fraser Island", "Austrial",
"St. Bart's",
"Langkawi", "Malaysia",
"Kaunaaa", "Bay" ,"Hawai"
};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.beaches);
lv=(ListView)findViewById(R.id.listView2);
lv.setAdapter(new ArrayAdapter<string>(this,
android.R.layout.simple_list_item_1, Wishlist2));
lv.setOnItemClickListener(this);

}
}plz help me my id is sallukhan2011@live.com reply in this id

salkhan786 wrote:
my id is sallukhan2011@live.com

Enjoy the spam.

Veni, vidi, abiit domum

Please learn to use the code button as it wraps your code around a styled <pre> tag, as it can make the code more readable. making use of the indent button is helpful as well. Which would you rather read below?

protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.beaches);
lv=(ListView)findViewById(R.id.listView2);
lv.setAdapter(new ArrayAdapter(this,
android.R.layout.simple_list_item_1, Wishlist2));
lv.setOnItemClickListener(this);

or....

Java

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.beaches);
    lv=(ListView)findViewById(R.id.listView2);
    lv.setAdapter(new ArrayAdapter(this,
    android.R.layout.simple_list_item_1, Wishlist2));
    lv.setOnItemClickListener(this);

"I've seen more information on a frickin' sticky note!" - Dave Kreskowiak

can anyone help me.. In android i have taken a listview and i have a created a list view ie a catgeory now to now i have to make a sub catgeory in it.how to implement that. wen i click the catgeory its goes to subcatgeory n i want wen i click a catgeory it goes to same screen and replace it. i mean i dont want to make separate screen for all my sub catgeory can anyone help me its urgent
this is mycode i have done upto here
public class MainActivity extends Activity {
ListView lv;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lv=(ListView)findViewById(R.id.listView1);

String[] Wishlist={"VisitTop10beaches","Adventures","Sports","Camp Site","Visit10Beautyfull City","VisitOneOfSevenContients","VisitTopCasinos","OwnadreamCar","VisitSevenWondersOfTheWorld","HolyPalces","UniqueTransportModes"};
ArrayAdapter<string> adapter=new ArrayAdapter<string>(this, android.R.layout.simple_list_item_1,Wishlist);

lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {

@Override
public void onItemClick(AdapterView arg0, View arg1, int arg2,
long arg3) {
// TODO Auto-generated method stub

}
});

}

Please do not repost the same message.

Veni, vidi, abiit domum

can anyone help me.. In android i have taken a listview and i have a created a list view ie a catgeory now to now i have to make a sub catgeory in it.how to implement that. wen i click the catgeory its goes to subcatgeory n i want wen i click a catgeory it goes to same screen and replace it. i mean i dont want to make separate screen for all my sub catgeory can anyone help me its urgent
this is mycode i have done upto here
public class MainActivity extends Activity {
ListView lv;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lv=(ListView)findViewById(R.id.listView1);

String[] Wishlist={"VisitTop10beaches","Adventures","Sports","Camp Site","Visit10Beautyfull City","VisitOneOfSevenContients","VisitTopCasinos","OwnadreamCar","VisitSevenWondersOfTheWorld","HolyPalces","UniqueTransportModes"};
ArrayAdapter<string> adapter=new ArrayAdapter<string>(this, android.R.layout.simple_list_item_1,Wishlist);

lv.setAdapter(adapter);
lv.setOnItemClickListener(new OnItemClickListener() {

@Override
public void onItemClick(AdapterView arg0, View arg1, int arg2,
long arg3) {
// TODO Auto-generated method stub

}
});

}

hi,

I am trying to develop an android application which uses google maps api, and I try to put a layer (overlay) on the map, but my image does not fit correctly with the map but does on google earth and also on google maps api in javascript / html, and i don't understand why? could someone help me please?

For more details:

I used GroundOverlayOptions and for "positionFromBounds" i used a LatLngBounds(southwest,northeast) and southwest and northeast are are deducted from north,south,east and west from google earth and they work correctly on google maps api for javascript/html.

(Sorry for my english, it's not my mother tongue).

Thanks.

/ / TODO Perform some action to recognize strings=Help me pliz! How to bring those recognized strings in a ListView or editText
Creating a dialog box for speech recognition:

Java

Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH)
// Specify an empty entry form
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_PROMPT,
"or forever hold your peace");
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS, 1);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.ENGLISH);
startActivityForResult(intent, VOICE_RECOGNITION);

Removing speech recognition results:

Java

@Override
protected void onActivityResult(int requestCode,
int resultCode,
Intent data) {
if (requestCode == VOICE VOICE_RECOGNITION && resultCode == RESULT_OK)
{
ArrayList<String> results;
results = data.getStringArrayListExtra(RecognizerIntent.EXTRA_
RESULTS);
// TODO Perform some action to recognize strings
}
super.onActivityResult(requestCode, resultCode, data);
}

Salaam friends,
I am a beginner in Java, and I wana learn mobile applications development for android.
please point me to a references which explain how to get start in it.
Thanks

Start making use of Google and you will be able to find sites such as http://developer.android.com/index.html[^] quite easily for yourself.

Veni, vidi, abiit domum

Get the JDK 1.6 or 1.7 installed.
Download ADT Bundle from http://developer.android.com/sdk/index.html
Start coding All the best Thumbs Up | :thumbsup:

Hi i want to design SearchBox Control programatically to search operation in my apps

So? Whats the problem. Go ahead.

I want (programmatically of course) to open the searchview (make it "in use").

I tried several functions such as:

SearchView searchView = (SearchView) menu.findItem(R.id.menu_search).getActionView();
searchView.setOnQueryTextListener(this);

searchView.performClick();
searchView.requestFocus();

But none of those worked...

The SearchView in the XML:

<item android:id="@+id/menu_search"
android:title="Search"
android:icon="@drawable/ic_action_search"
android:showAsAction="ifRoom|collapseActionView"
android:actionViewClass="android.widget.SearchView" />

Thank's

Hi i want design gridview using java program code for calculation in gridview in a linearlayout so only draw a gridview on my layout to do some mathematical operation

Everyone:

I have a WCF service that returns it's results in JSON format. It works fine when I put the url in a browser. I'm have a small test Anroid application in which the user clicks a button, the service is called and the value returned is displayed. The program always hangs on the HttpResponse ... execute statement. I'm using the Android studio for development and as far as I can tell, no error message returns. I also made sure to include the 'permission.INTERNET' statement in the manifest.
Here's the code:

Java

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpget = new HttpGet("http://XXXXXXXX/jsonwebservice/Service1.svc/getCNSP/CN-000186");

HttpResponse response = httpClient.execute(httpget);
HttpEntity responseEntity = response.getEntity();

Thanks for the help,
Dale

Kindly provide the LogCat in case it is showing any warning or errors.

Make sure you are running HTTP connection in Async Task.

Most probably you are making the network call on the main thread. This isn't allowed (NetworkOnMainThreadException).