Re: problem in applying grid style to datagrid - C# Discussion Boards

11-Jun-04 4:14

If the DataGridTableStyle.MappingName is different for both (and it must match up with the data source, such as a DataTable, array, or an IList implementation's class name), then you don't need to clear them. That's why the DataGrid.TableStyles property is a collection property. So long as the styles handle different data sources, it's not a problem to keep both in there. In fact, I'm pretty sure you're using different MappingNames since the Add method checks for duplicates and throws an exception in such a case. Just keep both styles in the collection.

When you're applying a style, you must re-bind the data source. The data source is "stylized" during binding.

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Readin XML Attributes

saud_a_k11-Jun-04 1:14

11-Jun-04 1:14

I have an XML file with which has elements and each element has one or more attribute. I can read the element fine, but I am no able to read each attribute separately as my attributes are defined like..

<name fname="xxxx" lnem="uuuu">
<job>dddd</job>
....etc
</name>

I cannot read fname & lname separately.
Please help.

Alex Getman11-Jun-04 2:45

Alex Getman

11-Jun-04 2:45

Here is a good article about XML parsing in C#
http://www.windevnet.com/documents/s=8692/win0307b/0307b.htm

xedom developers team

saud_a_k11-Jun-04 3:00

11-Jun-04 3:00

But a registration form comes up there. I can't open the page.

MaXx

Heath Stewart11-Jun-04 4:10

11-Jun-04 4:10

How are you reading in the XML file? If you use an XmlTextReader, for example, there is plenty of ways to access both elements and attributes, as well as processing instructions, comments, etc. If you're using an XmlDocument along with the rest of the XML DOM classes, then there are ways to access attributes, elements, processing insturctions, etc., as well. Read the documentation for the class(es) you're using in the .NET Framework SDK.

Otherwise, please be more specific about why you can't seem to read attributes and maybe we can help.

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saud_a_k13-Jun-04 20:55

13-Jun-04 20:55

Yes I am using the XmlTextReader. I have a file like
<?xml version="1.0" ?>

<bookstore>
<book genre="autobiography" publicationdate="1981" ISBN="1-861003-11-0">
<title>The Autobiography of Benjamin Franklin</title>
<author size="25">
<first-name age="25">Benjamin</first-name>
<last-name>Franklin</last-name>
</author>
<price>8.99</price>
</book>
<book genre="novel" publicationdate="1967" ISBN="0-201-63361-2">
<title>The Confidence Man</title>
<author>
<first-name>Herman</first-name>
<last-name>Melville</last-name>
</author>
<price>11.99</price>
</book>
<book genre="philosophy" publicationdate="1991" ISBN="1-861001-57-6">
<title>The Gorgias</title>
<author>
<name>Plato</name>
</author>
<price>9.99</price>
</book>
</bookstore>

I am using the ReadString funcyion to read attributes like
...
book genre philosophy publicastiondate 1991 etc.. but.. I can read only one string.. like only philosophy, not the reat..
I want to read each of the attributes saparately.
HELP

MaXx

Heath Stewart14-Jun-04 3:40

14-Jun-04 3:40

You should be using XML-specific methods, like GetAttribute, MoveToAttribute, or ReadAttributeValue. The idea about the XmlTextReader is forward-only reading. You move from element to element and attribute to attribute. If you treat everything as a string, of course you will not get what you want; you may as well not even use XML if you treat the document as a simple text file.

You really should read about the class members on the XmlTextReader[^].

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saud_a_k14-Jun-04 17:58

14-Jun-04 17:58

I got this code on the net....

private void AddWithChildren(XmlNode xnod, Int32 intLevel)
{
//Adds a node to the ListBox, togather with its children.
//intLevel controls the depth of indenting
XmlNode xnodWorking;
String strIndent = new string(' ',2 * intLevel);
//Get the value of the node (if any)
string strValue = (string) xnod.Value;
if(strValue != null)
{
strValue = " : " + strValue;
}
//Add the node details to the ListBox
Console.WriteLine(strIndent + xnod.Name + strValue);

//For an element node, retrive the attributes
if (xnod.NodeType == XmlNodeType.Element)
{
XmlNamedNodeMap mapAttributes = xnod.Attributes;
//Add the attributes to the ListBox
foreach(XmlNode xnodAttribute in mapAttributes)
{
Console.WriteLine(strIndent + " " + xnodAttribute.Name +
" : " + xnodAttribute.Value);
}
//If there are any child node, call this procedrue recursively
if(xnod.HasChildNodes)
{
xnodWorking = xnod.FirstChild;
while (xnodWorking != null)
{
AddWithChildren(xnodWorking, intLevel +1);
xnodWorking = xnodWorking.NextSibling;
}
}
}
It workes fine but I thought it would be a little easier to get the attributes.. mainly those which are present in the same line as the element tag like
<person fname=nnn lname=hhh>
.....
</person>
Is there an easier way...

MaXx

Heath Stewart15-Jun-04 2:30

15-Jun-04 2:30

You don't read lines in XML, you move from element to element, and attribute to attribute.

Read the class documentation for the XmlTextReader in the .NET Framework SDK. There are plenty of examples there as well. It is very easy, but you don't treat XML as a plain text file, i.e. you don't read lines.

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saud_a_k15-Jun-04 17:57

15-Jun-04 17:57

ok.. maybe i'll find an easier one..
thanx for everythin' bro.. Smile | :)

MaXx

Heath Stewart16-Jun-04 3:20

16-Jun-04 3:20

There is no easier way, man! Smile | :)

Seriously, read the documentation for classes in the System.Xml namespace in the .NET Framework SDK. XML is easy to work with, one reason it's so popular. There's lots of examples in that documentation, like for the XmlTextReader that you'll probably want.

There's two ways of reading XML: parsing the DOM or parsing the document itself (SAX; basically). You could load an XML document completely into memory using the XmlDocument and use XPath (via SelectNodes or an XPathNavigator, which is pretty fast) to get what you need. This is good for smaller documents.

For larger documents you don't want to load the whole thing into memory, so you use SAX, which is an event-driven way to parse the document. This isn't exactly what using an XmlTextReader is, but it is a forward-only way of reading XML documents. While it isn't event driven, it is operation driven (basically the converse of SAX).

So, if you're document is small and you want to extract, for example, the language that is the default language, do something like this:

XML Document-----------------------------------------------------------
<languages>
  <language default="true">
    <name>en-US</name>
    <englishName>English (United States)</englishName>
  </language>
  <language>
    <name>de-DE</name>
    <englishName>German (Germany)</englishName>
  </language>
</languages>
C# Snippet-------------------------------------------------------------------
XmlDocument doc = new XmlDocument();
doc.Load("languages.xml");
XmlNode node = doc.DocumentElement.SelectSingleNode(
  "language[@default = 'true']/name");
if (node != null)
  return CultureInfo(node.Value);
else return null;

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saud_a_k16-Jun-04 18:49

16-Jun-04 18:49

I think I'll use the XmlTextreader. I can navigate throught the nodes properly with the function I have (given up there^) but do I have to use a level variable to go to each attribute and next, Isn't there an attribute reader?? which can go without bieng followed? (by level)

MaXx

Heath Stewart16-Jun-04 21:00

16-Jun-04 21:00

See the XmlTextReader.MoveToNextAttribute, which should stick out like a sore thumb if you read the class documentation for XmlTextReader. There's simply no reason not to read the class documentation, especially for those classes you use in your code.

Microsoft MVP, Visual C#
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saud_a_k16-Jun-04 21:11

16-Jun-04 21:11

of course I read the documentation, I also did the .. readstring.. thing looking at the documentation..

Believe! Every thing has a purpose

eggie511-Jun-04 12:59

eggie5

11-Jun-04 12:59

watvh this movie[^]

watch the reading xml files one, it shows how to read attributes. it is in vb, but its in simple code, so it should be easy to convert.

/\ |_ E X E GG

saud_a_k14-Jun-04 18:02