How do I write algorithm adding 2 number in base 2?

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the algorithm is about 2 numbers for example a,b in base 2 and adding them in base 2 without converting to base 10
and i've spend hours on it and there's only one day left

What I have tried:

this is the last thing i've tried:

c=0
i=1
ans=0
(**)c=c+a%10+b%10
if c>=2
{
ans=ans+10^i+(c-2)*10^(i-1)
c=1
}
else
{
ans=ans+c*10^(i-1)
c=0
}
a=a/10
b=b/10
i=i+1
if a=0 && b=0 && c=0
go (!!)
else
go(**)
(!!)end

Posted 24-Oct-17 9:37am

yegmor

Updated 24-Oct-17 12:01pm

OriginalGriff

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OriginalGriff · Answer 1 · 2017-10-24T12:01:00

Do it the way processors do (sort of) - use a one-bit adder.
Extract each bit from a and b in turn, and add them together with a carry bit to produce a single bit solution with an updated carry:

Inputs:    Result:
A B C      C X
0 0 0      0 0
0 1 0      0 1
1 0 0      0 1
1 1 0      1 0
0 0 1      0 1
0 1 1      1 0
1 0 1      1 0
1 1 1      1 1

Use that it a loop to process all the bits, and you are done.