Get ID value of button?

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PHP

MySQL

Hi,
I am trying to get the VALUE of the selected button aka the ID of the item

See code below, the last query brings back $MealID item thats displayed.

The loop loops around & displays 4 items, all which have buttons beside them.

When clicked, i need to get the ID of the meal in order to changed 'Displayed' to 1 in the DB table

Can anyone help?

What I have tried:

//output recipe information
while($dbRow=$dbQuery->fetch(PDO::FETCH_ASSOC) and ($cnt < $max))  
    {
            echo "".$dbRow["Name"].""."<br><img src=\".$dbRow['Picture']."' width='150' height='150' />"."".$dbRow["Instructions"]."<form method='POST'><input type='submit' name='submit' value='Completee' class='button'>";
	  $cnt++;

	$RecipeID=$dbRow["RecipeID"];
	if (!$inserted) {
    $Displayed = false;
		$stmt=$conn->prepare("INSERT into UserMeals (UserID, MealID, Displayed) VALUES (:UserID, :MealID, :Displayed) "); 
		$stmt->execute(array(
	   ':UserID' => $UserID,
		':MealID' => $MealID,
		':Displayed' => $Displayed
		)); 
 }
	}


   if (isset($_POST['submit']) && ($daysLeft == 7)){
$dbQuery = $conn->prepare('UPDATE UserRecipes SET Displayed="1" WHERE UserID=:UserID AND MealID=$MealID');
   $dbParams = array(':UserID'=>$UserID);
 $dbQuery->execute($dbParams);
   }