How to clear error in xmlnodes.

Question

1.00/5 (1 vote)

See more:

Hai,

I am having .net application and I have an xml document.I want to get the values of childnodes and put it into notepad.After I run the program the error is occurs.
"Data at the root level is invalid. Line 1, position 1.".Plz help me.Below is the code

//Default.aspx.cs//

XmlDocument xml = new XmlDocument();
       xml.LoadXml("C:/Documents and Settings/sridharan/Desktop/RTSLINK FOR TALLY/XMLFile3.xml");
       XmlNodeList xnlist = xml.SelectNodes("/Names/Name");
       foreach (XmlNode xn in xnlist)
       {
           string firstname = xn["firstname"].InnerText;
           string lastname = xn["secondname"].InnerText;
           Console.WriteLine("Name:{0} {1}", firstname, lastname);

//xmlfile//

<names>
  <name>
    <firstname>John</firstname>
    <lastname>Smith</lastname>
  </name>
  <name>
    <firstname>James</firstname>
    <lastname>White</lastname>
  </name>
</names>

Posted 17-May-11 19:01pm

sridharan28

Add a Solution

Comments

Sergey Alexandrovich Kryukov 18-May-11 1:20am

Everything is hard-coded. Very bad code.
--SA

sridharan28 18-May-11 1:27am

thanks for ur reply

sridharan28 18-May-11 1:25am

Thanks alot for your reply.Please give me suitable answer

Sergey Alexandrovich Kryukov 18-May-11 1:49am

I commented to the answer by S Mewara. I don't see the problem you report from your code. Are you sure this is the same code as the one which cause the problem? Perhaps you did not properly reported a problem. Check it up. Catch all exceptions around the code which throws it and dump exception stack, don't forget all inner exceptions (recursively); show the code lines in code file.
--SA

Sergey Alexandrovich Kryukov 18-May-11 2:03am

OK, you got a real answer. I suggest you do it right. It's easy, too. Please see my solution.
--SA

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sandeep Mewara · Answer 1 · 2011-05-17T19:09:00

Solution 1

Similar issue discussed[^] here at length.

Few possible reasons are:
1. Not a well formed XML
2. Having a white space just before the root element
3. Wrong reference of the file
4. Encoding specified in XML document

Have a look at this discussion[^] too.

UPDATE:
Apart from above answer, try two things:
1. Use xml.Load instead of xml.LoadXml method.
2. If 1 does not do, put this as the first line (make sure no space before the first character)

XML

<?xml version="1.0" encoding="utf-8"?>

Posted 17-May-11 19:09pm

Sandeep Mewara

Updated 17-May-11 19:55pm

v2

Comments

Sergey Alexandrovich Kryukov 18-May-11 1:23am

I'm not sure. First, items 1, 2 and 4 is the same as 1. Secondly, you see the XML code, it looks like well-formed. Item 3 is not applicable (see the error message).
Most probably, OP did not report the problem correctly...
--SA

Sandeep Mewara 18-May-11 1:46am

In a sense, agree 1,2 & 4 sounds same. But 1 is just for opening/closing tags. :)

Based on the thread references, I see that 3 can be the reason... though I totally agree again. To me, point 2 or 4 has highest chance.

Meanwhile, since you posted these comments, let me read more on what and why of this error - if I get anything else, I will share with you.

Sergey Alexandrovich Kryukov 18-May-11 2:49am

No! 1 is not just about tags. There is a whole lot of well-formed rules. See my comment below. Why doing all that?
--SA

sridharan28 18-May-11 1:26am

Exactly i am getting the error "Data at the root level is invalid. Line 1, position 1."

Sandeep Mewara 18-May-11 1:51am

Can you try putting this as the first line:
<?xml version="1.0" encoding="utf-8" ?>

Sergey Alexandrovich Kryukov 18-May-11 2:50am

Parser can work without it if I'm not much mistaken... good to check up... even if so, it wouldn't hurt, of course.
--SA

Sergey Alexandrovich Kryukov 18-May-11 2:01am

Sandeep, you know what? I see no point for OP to ram this problem.
Instead of using this naive home-baked approach to serialization, why not using ready-to-use technology which will serialize and deserialize everything automatically?

Please see my answer.
--SA

Sergey Alexandrovich Kryukov · Answer 2 · 2011-05-17T19:55:00

Here is the alternative. I would totally avoid this approach. I don't see why you need to deal with XML manually. Use Data Contract. It will robustly save your data model to XML and restore it back; the schema will be created on the fly. This is the most non-intrusive method as well: you only add attributes [DataContract] and [DataMembers].

See:
http://msdn.microsoft.com/en-us/library/ms733127.aspx[^],
http://msdn.microsoft.com/en-us/library/system.runtime.serialization.datacontractserializer.aspx[^],
http://msdn.microsoft.com/en-us/library/system.runtime.serialization.datacontractattribute.aspx[^],
http://msdn.microsoft.com/en-us/library/system.runtime.serialization.datamemberattribute.aspx[^].

—SA

Roman_wolf · Answer 3 · 2011-05-17T20:01:00

Here's what your problem is:

XmlDocument has 2 load methods for loading XML

XmlDocument xml = new XmlDocument();
xml.LoadXml(...)

the passed paramater here should be a valid xml string.

the method you want is

XmlDocument xml = new XmlDocument();
xml.Load("PathGoesHere.xml")

Also, the XPath is case sensitive (Names is different than name)

How to clear error in xmlnodes.

3 solutions

Solution 1

Solution 2

Solution 3

Add your solution here

Preview 0