How do I load a node of an XML into a property object C#

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Hi Guys

I need some assistance please
I am trying to simply an XML import and need some advice

i have an XML which has parent nodes and some child nodes.
when my import runs i currently import my Parent node items into my C# object by using the

xmlSerializer.Deserialize(XMLString)

The object i am doing my load into is the client object

In my client object i have a property for order which is another class object in my Project

sample of my XML is

<client>
<name>x
<surname>y
<orders>
<order>
<orderno>QA122
<order>
<order>
<orderno>QA125
<order>

so currently the Client object loads the values fine but the order object is null
i would like to know how could i get the Order object to load from the XML.

What I have tried:

StringReader stringreader = new StringReader(XMLString);
                    XmlSerializer xmlSerializer = new XmlSerializer(this.GetType());
                    Policy pol = (Policy)xmlSerializer.Deserialize(stringreader);

Posted 23-Jun-19 7:33am

isi Rajah

Updated 23-Jun-19 23:35pm

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BillWoodruff 23-Jun-19 20:49pm

without seeing the structure of 'Policy, and sample actual XML: I don't think we can assist you.

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Maciej Los · Answer 1 · 2019-06-23T23:35:00

The answer is obvious: your xml structure is invalid!

Proper xml should looks like:

XML

<clients>
  <client>
    <name>x</name>
    <surname>y</surname>
    <orders>
      <order>
        <orderno>QA122</orderno>
      </order>
      <order>
        <orderno>QA125</orderno>
      </order>
    </orders>
  </client>
</clients>

or:

XML

<clients>
  <client name="x" surname="y">
    <orders>
      <order orderno="QA122" />
      <order orderno="QA125" />
    </orders>
  </client>
</clients>

Depending on that, a set of classes have to be created. Then you'll be able to serialize/deserialize data.

For further details, please see:
Introducing XML Serialization | Microsoft Docs[^]
XmlSerializer Class (System.Xml.Serialization) | Microsoft Docs[^]
XML Serialization and Deserialization: Part 1[^]