To replace a day part in date column for the records selected in where clause keeping remaining part same is not working in mysql

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UPDATE outturn set `year_month` = DATE_ADD(dd,(01-datepart(dd,`year_month`)),`year_month`) WHERE `year_month` LIKE '%-%-02 %'

What I have tried:

UPDATE outturn set `year_month` = DATE_ADD(dd,(01-datepart(dd,`year_month`)),`year_month`) WHERE `year_month` LIKE '%-%-02 %'

Posted 8-Nov-19 2:47am

webmasteroficf

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Richard MacCutchan 8-Nov-19 9:30am

What does "not working" mean? Please edit your question and show proper details of what your code is doing and what results you see or do not see.

ZurdoDev 8-Nov-19 11:30am

What exactly is the problem?

Richard Deeming 8-Nov-19 13:26pm

The fact that you're using LIKE on the column would seem to suggest that you're storing the date as a string instead of using a proper date data type.
MySQL :: MySQL 8.0 Reference Manual :: 11.3.1 The DATE, DATETIME, and TIMESTAMP Types[^]

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