How do I create program that match letter and number in C++

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Hi, I'm trying to create one program, but no way to make it. Two lines in the first line of code are strings and three numbers in the second line of code are entered into the program. Like this:
word + other_word = other_other_word
1254 + 5471 = 81755
If I can replace each number with each letter so that there are no letters corresponding to two numbers, the program should print yes, and if that is impossible they should print no.
Can you help me do this in c++?

What I have tried:

I tried to make this program but I can't.

Posted 12-Jan-20 2:22am

User 14681012

Updated 12-Jan-20 6:40am

KarstenK

v3

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Patrice T 12-Jan-20 8:58am

Add the letters result to your example.
and show your work and explain the problem.

2 solutions

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Richard MacCutchan · Answer 1 · 2020-01-12T02:54:00

Solution 1

Yes, we can help, but we are not going to do it all for you. You first need to show what you have done so far and explain exactly where you are stuck. As it stands there is not enough information in your question to know what criteria you use to replace a number with a letter.

Posted 12-Jan-20 2:54am

Richard MacCutchan

Comments

[no name] 12-Jan-20 10:18am

I use vector vector<int, char="">. But I do not know how to compare vectors. For example how to find is there numbers that corresponds to two different letters, or is there letter that corresponds to two different numbers.

Richard MacCutchan 12-Jan-20 10:26am

Sorry, I am not sure what you mean. If you know which character represents which digit, then a simple array will suffice. For example if the digits 1 to 9 are represented by ABCDEFGHI, then something like the following will do it:


char digtoltr[] = "0ABCDEFGHI";
char number = getc();  // get the next digit as a character
int index = number - '0'; // make it an integer value
char letter = digtoltr[index]; // get the letter that corresponds to this number

[no name] 12-Jan-20 10:57am

I managed to do this but I do not know how to continue, please help:
#include <iostream>
#include <string>
#include <stdlib.h>
using namespace std;

int main()
{
string first, second, third, some_string;
string first_number, second_number, third_number;
getline(cin, first, ' ');
getline(cin, some_string, ' ');
getline(cin, second, ' ');
getline(cin, some_string, ' ');
getline(cin, third);

getline(cin, first_number, ' ');
getline(cin, some_string, ' ');
getline(cin, second_number, ' ');
getline(cin, some_string, ' ');
getline(cin, third_number);

int number1 =atoi(first_number.c_str());
int number2 = atoi(second_number.c_str());
int number3 = atoi(third_number.c_str());
return 0;
}

[no name] 12-Jan-20 10:30am

Thanks, but I do not know how to correspond letter to number. If I have string STOP, and int 1234; how should I correspond letter S to number 1, and all others?

[no name] 12-Jan-20 10:32am

I managed to do this, but I do not know how to continue, where to start:
#include <iostream>
#include <string>
#include <stdlib.h>
using namespace std;

int main()
{
string first, second, third, some_string;
string first_number, second_number, third_number;
getline(cin, first, ' ');
getline(cin, some_string, ' ');
getline(cin, second, ' ');
getline(cin, some_string, ' ');
getline(cin, third);

getline(cin, first_number, ' ');
getline(cin, some_string, ' ');
getline(cin, second_number, ' ');
getline(cin, some_string, ' ');
getline(cin, third_number);

int number1 =atoi(first_number.c_str());
int number2 = atoi(second_number.c_str());
int number3 = atoi(third_number.c_str());
return 0;
}

Richard MacCutchan 12-Jan-20 11:24am

If you are reading the two fields together that represent all characters and digits then the following code will do it. NB I have coded two sample strings just to make this code work:


std::string foo = "bludsnake";
std::string number = "956324718";

for each (char c in number)
{
    int i = c - '0';
    std::cout << "number: " << c << " = letter: " << foo[i - 1] << std::endl;
}

[no name] 12-Jan-20 12:15pm

I still do not understand how I can correspond first letter to first number, second letter to second number... in my program?

Richard MacCutchan 12-Jan-20 12:22pm

Select the first letter and the first number. Convert the number to an integer value as I have shown and store the letter in that position of an array. Then when you use the number later on it should select the correct letter.

[no name] 12-Jan-20 11:35am

Thank you, but how can I check if there is 2 different number that is corresponded to same letter, or 2 different letter corresponded to same number?

Richard MacCutchan 12-Jan-20 11:44am

You need to look at each number in order and see if it has already been declared, and do the same with the letters.

But you need to start by thinking about the problem before you write any code. Write some sample strings on paper and think how you would approach each part of the problem to solve it. Write out the basic steps and do a few sample walks through. Once you have that clear in your mind you can start turning those steps into actual code.

[no name] 12-Jan-20 12:03pm

I writes error when I type "for each". Why?

[no name] 12-Jan-20 12:05pm

How I can insert your code:
std::string foo = "bludsnake";
std::string number = "956324718";

for each (char c in number)
{
int i = c - '0';
std::cout << "number: " << c << " = letter: " << foo[i - 1] << std::endl;
}
in my program?

Richard MacCutchan 12-Jan-20 12:15pm

Sorry my mistake, that is the old fashioned way, you should use the range based for statement:
for (char c : number)
See Range-based for Statement (C++) | Microsoft Docs[^].

[no name] 12-Jan-20 12:28pm

I run this program but it writes:
number: 9 = letter: e
number: 5 = letter: s
number: 6 = letter: n
number: 3 = letter: u
number: 2 = letter: l
number: 4 = letter: d
number: 7 = letter: a
number: 1 = letter: b
number: 8 = letter: k
but string is bludsnake, and int is 956324718, and it writes 9 = e. Why it does not write 9 = b? 9 is first number and b is first letter.

Richard MacCutchan 12-Jan-20 12:40pm

See my solution below.

Richard MacCutchan 12-Jan-20 12:18pm

Short answer: don't.
As i said earlier, think about what you need to do and use pen and paper to work out the steps that are needed. Just copying someone else's code without fully understanding what it does will lead to more problems.

Richard MacCutchan · Answer 2 · 2020-01-12T06:40:00

Solution 2

This code will build you a translate table to match the letters and numbers. You can then use the number (converted by: int i = number - '0' - 1) to get the correct letter for future input strings.

C++

std::string letters = "bludsnake";
std::string numbers = "956324718";
std::string table = "";
table.append(letters.length(), ' ');

for (int i = 0; i < letters.length(); ++i)
{
    char c = letters[i];
    int index = numbers[i] - '0';
    table[index - 1] = c;
}

Posted 12-Jan-20 6:40am

Richard MacCutchan

Comments

[no name] 12-Jan-20 12:51pm

OK. But I already have the numbers offered below the letter to check that the same number matches the same letter. How can I make that function?

Richard MacCutchan 12-Jan-20 12:56pm

You really need to start thinking harder about how to do this. I have given you enough ideas to get started. Now it is up to you.

[no name] 12-Jan-20 12:58pm

OK. Thank you so much, but I do not understand what your program does?

Richard MacCutchan 12-Jan-20 13:03pm

It creates a lookup table from the two inputs. You can then find the letter that corresponds to each digit by the following:


char number = // the next number in a set
int index = number - '0';
char matchingLetter = table[index - 1]; // so 9 would return b, 5 would return l etc.

[no name] 12-Jan-20 13:10pm

But what if a number is a bigger than length of string?
For example 8751 for string book, prints:

k

Richard MacCutchan 12-Jan-20 13:23pm

Well that does not really work since 7 and 5 are both set to 'o'. I suspect that my suggestions are not actually what you are looking for.

[no name] 12-Jan-20 13:38pm

So, how can I solve this problem?