The user should pick which three of the element will be added to get the sum

See more:

Java

import java.util.Scanner;
import java.util.*;
public class B_MentalWarmUp {
    
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        //nth element input
        System.out.print("Enter the Trio of Elements: ");
        int n = sc.nextInt();
        //Initialize array
        int [] myArray= { 10, 20, 10, 40, 50, 60, 70};
        int sum = 0;
        //Loop through the array to calculate sum of elements  
        for(int i = 0; i < myArray.length; i++)
        {
            n = myArray[i];
            sum = sum + n;
        }
        System.out.println("Sum of all the elements of an array: " + sum);
        // If we reach here, then it is out of range
        {
        System.out.println("Your input is out of range, TRY AGAIN!");
        return;
    }
}
}

Here is the instruction:

Write a Java program that finds a trio of elements (i.e. indices of the three numbers) from a given array A whose sum equals a specific target number B as the output. If the user puts a number that is not within the size of the array. The system should respond "Your input is out of range, TRY AGAIN

What I have tried:

I tried to code one by one the index so that when it is called/input it will will be added. But that made it only difficult and it also didn't work