Jquery onKeyPress Event

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Hi Team
i want to perform a validations OnkeyPress JQuery Event.
I want to do validation for Alphabets,delete,backspace ,left arrow,up arrow,right arrow,and down arrow using JavascriptkeyCode in one Textbox..How to do this? ..kindly Help..

I have tried this

function keyPressFunctionForValidations(e) {<br />
               debugger;<br />
               var code = e.keyCode || e.which;<br />
              if (code != 32  (code <65 || code > 90)) {<br />
                   return<br />
               }<br />
           }

Thanks
Harshal Raut

Posted 10-Jan-14 23:09pm

R Harshal

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Karthik_Mahalingam · Accepted Answer · 2014-01-10T23:26:00

Solution 1

try this..

JavaScript

<script type="text/javascript">
        $(function () {
        $('#txt').keypress(function (e) {

            var charCode = e.keyCode || e.which;
            if (charCode == 37 || charCode == 39) return true;  // allow arrows
            if (charCode == 46) return true; //delete
            if (charCode == 190 || charCode == 110) return true; // period or dot
            if (charCode == 35 || charCode == 36) return true; // home, end
            if (charCode == 8 || charCode == 9) return true; // backspace , tab
            if (charCode > 64 && charCode < 91) return true;  // a - z
            if (charCode > 96 && charCode < 123) return true; // A- Z
            e.preventDefault();
        });

        });
    </script>

Posted 10-Jan-14 23:26pm

Karthik_Mahalingam

Comments

[no name] 11-Jan-14 5:41am

Thank you so much for giving the answer.
Is it possible to write this statement in one If condition...
If is it possible please let me know..

Thanks
Harshal

Karthik_Mahalingam 11-Jan-14 5:44am

yes you can, need to add an [ or || ] conditions for each case. thats it..

[no name] 11-Jan-14 5:49am

i want to write like this.Please check it

if (charCode == 37 || charCode == 39) return true; ||
(charCode == 46) return true; ||
(charCode == 190 || charCode == 110) return true; ||
(charCode == 35 || charCode == 36) return true;||
(charCode == 8 || charCode == 9) return true; ||
(charCode > 64 && charCode < 91) return true; ||
(charCode > 96 && charCode < 123) return true;
e.preventDefault();

Thank you ..
harshal

Karthik_Mahalingam 11-Jan-14 5:51am

no no not like this..

Karthik_Mahalingam 11-Jan-14 5:52am

like this
if ( (charCode == 37 || charCode == 39) || (charCode == 46) || (charCode == 190 || charCode == 110)................ )
return true;

[no name] 11-Jan-14 5:54am

Thank you so much Karthik.
Thanks a Lot...

Karthik_Mahalingam 11-Jan-14 6:04am

welcome dude :)

[no name] 11-Jan-14 6:08am

Is there any way for asking a question directly to you..?

Karthik_Mahalingam 11-Jan-14 6:14am

xxxxxxxxxxxxx@gmail.com

pls acknowledge it soon. so that i will remove this id here..

as it is not safe to reveal id in social forums..

Karthik_Mahalingam 11-Jan-14 6:25am

removed.

[no name] 11-Jan-14 7:27am

Sorry Brother i got stuck in project..I cant see u r mailID.
will you able to forward u r mailId on my MailId ie:harshalraut1990@gmail.com

Thanks
Harshal..

Karthik_Mahalingam 11-Jan-14 7:56am

ok fine..

[no name] 11-Jan-14 7:35am

i got it ..thank you so Much Dude....

[no name] 13-Jan-14 2:46am

Hi Karthik.
one Query .Please help
According to your solution I have tried ..
if ((charCode < 37 || charCode > 40) || (charCode == 46) || (charCode == 190 || charCode == 110) || (charCode == 8)
|| (code < 65 || code > 90)) {
return true;
}

Problem is if i type any digit it getting display in textbox which i dont want .so will you tell me where i am getting wrong..

Thanks
harshal.

Karthik_Mahalingam 13-Jan-14 3:43am

u mean [0-9] ??

[no name] 13-Jan-14 6:48am

YES buddy...

Karthik_Mahalingam 13-Jan-14 7:02am

Checked now in my machine , its working fine.. it is not allowing numbers
Pls make sure that your aspx page has jquery reference.