set selected value in dropdownlist in mvc razor

Question

0.00/5 (No votes)

See more:

, +

i wanna set my selected state into this state dropdownlist. i dont have any idea to set this . please help some one with this below code.

Model(ClaimModel ):

C#

public DataSet Bindcarrier()
        {
            //StudentContext db = new StudentContext();
            try
            {
                con.Open();
                DataSet ds = new DataSet();
                if (con.State == ConnectionState.Open)
                {
                    SqlCommand cmd = new SqlCommand("usp_ddlb_ref_carrier_login", con);
                    cmd.CommandType = CommandType.StoredProcedure;
                    cmd.Parameters.AddWithValue("@pi_is_active", 1);
                    cmd.Parameters.AddWithValue("@pi_login_id", DBNull.Value);
                    SqlDataAdapter da = new SqlDataAdapter(cmd);

                    da.Fill(ds);
                    return ds;
                }
                else
                {
                    return ds;
                }

            }
            finally
            {
                con.Close();
            }
        }

View:

@Html.DropDownList("state", null, new { @class = "drplist" })

Controller:

C#

[HttpGet]
    public ActionResult Create(Boolean Name)
    {                   ClaimModel obj = new ClaimModel();
                        DataSet ds = obj.Bindstate();

                        ViewBag.fname = ds.Tables[0];
                        List<SelectListItem> items = new List<SelectListItem>();
                        foreach (System.Data.DataRow dr in ViewBag.fname.Rows)
                        {
                            items.Add(new SelectListItem { Text = @dr["state_short_name"].ToString(), Value = @dr["state_id"].ToString() });
                        }

                        ViewBag.State = items;

      }

Posted 22-Dec-14 20:41pm

Deenuji

Updated 28-Aug-18 3:48am

v3

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Kornfeld Eliyahu Peter · Answer 1 · 2014-12-22T20:58:00

Solution 1

SelectListItem[^] has property Selected...set it for the right item and it will be the selected one...

C#

items.Add(new SelectListItem { Text = @dr["state_short_name"].ToString(), Value = @dr["state_id"].ToString(), Selected = (@dr["state_id"] == any_index) });

Posted 22-Dec-14 20:58pm

Kornfeld Eliyahu Peter

Comments

Deenuji 23-Dec-14 3:13am

thank you peter. but its selected only in list value but its not reflecting in dropdownlist . we need add any selected item parameter in dropdownlist?

Richard Maly · Answer 2 · 2018-08-28T03:49:00

I use DropdownListFor()

Which has a slightly different approach I use a model not a view bag. A model is a separate class called by the Controller. An example is given in this stack overflow c# - MVC ViewModel example - Stack Overflow[^]

For this to work in your model you need 2 properties.

public List<SelectListItem> items {get;set;}
public int MyAssignedToValue {get;set;}

then in your view

@Html.DropdownListFor(a=> a.MyAssignedToValue, Model.items)