C / C++ / MFC

z=x++ - --y *b/a;
x(++) - ((--y) *b / a);
5 - (-11 * 2 / 4)
5 - (-22 / 4)
5 - (-5) // integer arithmetic ignores remainder
10

z = (x++) - (((--y) * b) / a);

z = (5++) - (((--(-10)) * 2) / 4);

z = (5) - ((-11 * 2) / 4);
z = 5 - (-22 / 4);
// The remaining steps are left to your exercise

parkavikkk wrote:

int z, x=5, y= -10, a=4, b=2;
z=x++ - --y *b/a;
Can anyone please solve it and explain the precedence. i am not getting right answer. my answer is 2.5. but it is wrong.