Comments by Member 10626057 (Top 48 by date)

the problem is in this line
if (!($stmt = $mysqli->prepare($sql))) {

i'm getting an error
Fatal error: Call to a member function prepare() on a non-object

thank u.. i'll try it :)

sql injection?

stil the same =/

nt working =/

the size of the browser..

thank u :)

...

thank u :-)
but the examples r in .NET..

thank U ^^

i think u've not understd my question well..
anyway thank u..

your code is displaying only the lastname in the list.. not even the iD

i guess there is a problem with the editor --'

I have the codes to send back the updated values..
I want only the first part,i.e, info displayed in textboxes when i select the radio button..
=/

its not working..
getting Parse error: syntax error, unexpected '"', expecting ',' or ';'

yaa my code is in PHP..
thank u for ur help :)

the next step is
when i select a radio button i want all the information in the row to be displayed in textboxes so that i can update the information..

can you help plz..

<tr><td>Lecturer ID:</td>
";
while ($row=mysql_fetch_array($result)) {
echo "<option>".$row["lecturer_id"]."</option>";
echo $row["lecturer_lastname"] ;
}
echo "</select>"
?><br/>


It is displaying only the ID.. I want to display the name as well.. When i select 1 ID i want to get its corresponding name..

wow thank u Kozub Marcin..

no i want a radio button for each row..

i've retrieve data from my database and insert them in a table.. i want to add radio buttons at the end of each row..

<table class='TFtable'>
<tr>
<td>Lecturer ID</td>
<td>Lastname</td>
<td>Firstname</td>
</tr>";


while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['lecturer_id'] . "</td>";
echo "<td>" . $row['lecturer_lastname'] . "</td>";
echo "<td>" . $row['lecturer_firstname'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysql_close($con);

?></span>

I've already made the connection to the database..

; } ECHO "</select>"; is being displayed in my form..

I'm getting only the word "Choose" in my list.. The item from the database are not displayed..

am new to php.. javascript
i want a simple code..
I've tried the code below but it is displaying only the word "Choose" in my list

?php //connection

$sql="SELECT lecturer_lastname FROM lecturer";
$result=mysql_query($sql);

$options="";

while ($row=mysql_fetch_array($result)) {

$id=$row["lecturer_lastname"];

$options.="$id".;
}
?>
<SELECT NAME=thing>
<OPTION VALUE=0>Choose

</SELECT>

yaa i've already connected to the database..
stil it is displaying only "Choose" in the list.. not the values from my database..

Here is my code but only the word "Choose" is displayed in the list.. It does not retrieve any item from my database.. please help me

<!--?php ....


$sql="SELECT lecturer_lastname FROM lecturer";
$result=mysql_query($sql);

$options="";

while ($row=mysql_fetch_array($result)) {

$name=$row["lecturer_lastname"];

$options.="$name".;
}
??-->
<SELECT NAME=thing>
<OPTION VALUE=0>Choose

</SELECT>

:)

okie i'm a beginner.. sorry if i've troubled u..
thank you for ur help:)

no not asp.net
only html, javascript, php

can u copy the solution here..
plzz
i guess there is a problem with the editor..

although i click register OK it does not save anything

wat happen?

when i click on the button nothing happens..

function myfunction() {
var r=confirm("Are you sure to continue");
if (r==true) {
return true; }
else {
return false; }
}


<input type=submit name='Sign In' value="Register" button önclick="myfunction()">


this code adds the item in my database although i click CANCEL

function myfunction() {
var r=confirm("Are you sure to continue");
if (r==true) {
return true; }
else {
return false; }
}

<input type=submit name='Sign In' value="Register" button önclick="myfunction()">

function myfunction()
{

var r=confirm("Are you sure to continue");
if (r==true)
{
return true;
}
else
{
return false;
}

}


<input type=submit name='Sign In' value="Register" button önclick="myfunction()">

although i click CANCEL the item is added in my databse..
how can i change it?

I've tried all.. its not working :(

Its displaying
"; while($row = mysql_fetch_array($result)) { echo ""; echo ""; echo ""; } echo "
" . $row['lecturer'] . "
"; mysql_close($con) ?>

thank you :)

thx RK..
but whatever option i select i got the "invalid" message..