How to find a certain element in a template function in linked list?

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I'm tring to find a certain element in a list but it always give me this error

There are no conversions from integral values to pointer-to-member values

What I have tried:

Node<T>* GetptrTo(T k)
	{
		Node<T>* ptr = Head;
		while (ptr != NULL)
		{
			if (ptr->getItem == k) { return ptr; }
			ptr = ptr->getNext();
		}
		

	}

Posted 23-Dec-20 7:14am

Member 14771149

Updated 23-Dec-20 7:32am

v2

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Rick York · Accepted Answer · 2020-12-23T07:32:00

Solution 1

Without seeing the header that declares the Node class we can only guess. My guess is getItem is a method of the class so you need have parenthesis to call it : getItem().

Note - the GetptrTo function also needs to return something. I would guess it needs to return ptr.

Guessing again, it should probably look something like this :

C++

Node<T>* GetPtrTo( T k )
{
    Node<T>* ptr = getHead();
    while( ptr )
    {
        if( ptr->getItem() == k )
            break;
        ptr = ptr->getNext();
    }
    return ptr;
}

One last thing - isn't GetptrTo a method of the Node class? It looks like it should be to access the Head item. I would make a method for the class to access the list's Head item.

Posted 23-Dec-20 7:32am

Rick York

Updated 23-Dec-20 7:40am

v3

Comments

CPallini 23-Dec-20 17:23pm

5.

Rick York 24-Dec-20 14:26pm

Thanks.

Stefan_Lang 24-Dec-20 5:48am

Great analysis on all counts. getItem() is spot on: the compiler tries to do a conversion, and this is the only location in the code that could cause this exact error message. I was also wondering about this function accessing the symbol Head: either this is a global variable, which is bad (but not fatal), or it is a data member of the list class, in which case this function is meant to be an implementation of a method, but is missing the class qualifier. (which would result in another compiler error)

Rick York 24-Dec-20 14:25pm

thanks!