Convert this into Python

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Help me convert this to python Thankyou

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main()
{
    char Operation();
    string variableStr;
    double V1;
    double V2;
    double T1;
    double T2;

    cout << "V1/T1 = V2/T2" << endl << "Which variable are you solving for?" << endl;
    cin >> variableStr;

    system("clear");

    if (variableStr == "V1") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;

        cout << "What is the value of V2?" << endl;
        cin >> V2;

        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;

        V1 = (V2/T2)*T1;
        return V1;

    } else if (variableStr == "V2") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;

        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;

        cout << "What is the value of V1?" << endl;
        cin >> V1;

        V2 = (V1/T1)*T2;
        return V2;

    } else if (variableStr == "T1") {
        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;
        cout << "What is the value of V1?" << endl;
        cin >> V1;
        cout << "What is the value of V2?" << endl;
        cin >> V2;
        T1 = V1/(V2/T2);
        return T1;
    } else if (variableStr == "T2") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;
        cout << "What is the value of V1?" << endl;
        cin >> V1;
        cout << "What is the value of V2?" << endl;
        cin >> V2;
        T2 = V2/(V1/T1);
        return T2;
    } else {
        cout << "Please enter a valid option!" << endl;
        char Operation();
    }
    return 0;
}

What I have tried:

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main()
{
    char Operation();
    string variableStr;
    double V1;
    double V2;
    double T1;
    double T2;

    cout << "V1/T1 = V2/T2" << endl << "Which variable are you solving for?" << endl;
    cin >> variableStr;

    system("clear");

    if (variableStr == "V1") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;

        cout << "What is the value of V2?" << endl;
        cin >> V2;

        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;

        V1 = (V2/T2)*T1;
        return V1;

    } else if (variableStr == "V2") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;

        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;

        cout << "What is the value of V1?" << endl;
        cin >> V1;

        V2 = (V1/T1)*T2;
        return V2;

    } else if (variableStr == "T1") {
        cout << "What is the value of T2 in Kelvin?" << endl;
        cin >> T2;
        cout << "What is the value of V1?" << endl;
        cin >> V1;
        cout << "What is the value of V2?" << endl;
        cin >> V2;
        T1 = V1/(V2/T2);
        return T1;
    } else if (variableStr == "T2") {
        cout << "What is the value of T1 in Kelvin?" << endl;
        cin >> T1;
        cout << "What is the value of V1?" << endl;
        cin >> V1;
        cout << "What is the value of V2?" << endl;
        cin >> V2;
        T2 = V2/(V1/T1);
        return T2;
    } else {
        cout << "Please enter a valid option!" << endl;
        char Operation();
    }
    return 0;
}

Posted 14-Apr-22 0:41am

Mcdean Bernardo

Updated 14-Apr-22 2:38am

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Rick York 14-Apr-22 13:25pm

NO!

2 solutions

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OriginalGriff · Answer 1 · 2022-04-14T01:00:00

This is not a code conversion service: we are not here to translate code for you.
Even if we did, what you would end up with would not be "good code" in the target language – they are based on very different frameworks, and what makes something work in one language does not always "translate" directly into another.
So what you end up with is very poor code, that is difficult if not impossible to maintain, that can’t be upgraded nicely, and that will cause you immense headaches if the original is changed. And it'll be a nightmare to debug if it doesn’t work "straight out of the box".
Instead, use the source code as a specification for a new app written in and for the target language / framework and write it from scratch using the original as a "template". You will get a much, much better result that will save you a lot of time in the long run.

CPallini · Answer 2 · 2022-04-14T02:38:00

Solution 3

That is a very simple program. Read one (or more) of the many freely available Python tutorials, and 'do it yourself'.

Posted 14-Apr-22 2:38am

CPallini

Comments

OriginalGriff 14-Apr-22 9:10am

But ... but ... it's my *homework*
Plzzz do it 4 me m8 ...

:sigh:

CPallini 14-Apr-22 10:31am

Homework?!
Converting C++ to Python?
Are they really 'teaching' this stuff at school?
:-D

OriginalGriff 14-Apr-22 11:32am

Nah. The task is very similar, so when they copy'n'pasted the whole question Google came back with a C++ version. They figure "who'll know?" and just try to get it converted so they can hand it in. Sad really.

CPallini 14-Apr-22 13:08pm

That's reasonable.