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C#

#include <stdlib.h>
#include <stdio.h>
int main (){
int x,y,z;
scanf("%d%d%d",x,y,z);
if (x>y)
{
    if (x>z)
    {
        printf("%d",x);
        if (y>z)
        {
            printf("%d%d",y,z);
        }
        else
        {
            printf("%d%d",z,y);
        }
    }
    else
        printf("%d%d%d",z,x,y);
}
else
{
    if (y>z)
    {
        printf("%d",y);
        if (x>z)
        {
            printf("%d%d",x,z);
        }
        else
        {
            printf("%d%d",z,x);
        }
    }
    else
    {
        printf("%d%d%d",z,y,x);
    }
}
}

When I run this program it always tell me I have run into the wrong memory.

Posted 21-Jan-11 22:08pm

zhaoyilong1

Updated 21-Jan-11 22:15pm

Andrew Brock

v2

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Andrew Brock 22-Jan-11 4:16am

Removed several unused <code> and <pre> tags from the end of the question

1 solution

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Andrew Brock · Accepted Answer · 2011-01-21T22:11:00

Solution 1

You have to pass the parameters to scanf as pointers so it can write into the memory represented by the variable, not the memory represented by the variable value.

scanf("%d%d%d",&x,&y,&z);

EDIT:
On a side note, you probably want spaces in between each %d so you can enter the 3 numbers as 123 456 789
otherwise you have to separate the numbers by a line break like

123
456
789

Posted 21-Jan-11 22:11pm

Andrew Brock

Updated 21-Jan-11 22:15pm

v2

Comments

Espen Harlinn 22-Jan-11 4:34am

Right Answer 5+

Sergey Alexandrovich Kryukov 22-Jan-11 6:05am

Simple as that - my 5

zhaoyilong1 23-Jan-11 4:10am

Thank you very much! I see where my fault is.