how to get html source code by usng ajax request

Question

0.00/5 (No votes)

See more:

Hello frnds,

I want to get html source of particulate url by using ajax call,

till I have done,

JavaScript

url: "http://google.com",
         type: "GET",
         dataType: "jsonp",
         context: document.doctype
     }).done(function (data) {
         alert(data);
     });

but in this code its give error,

JavaScript

SyntaxError: syntax error

<!doctype html><html itemscope="" itemtype="http://schema.or

I want to read html from this call,

How can I achive this , or any other way to do like this?

Thanks in advance

Posted 23-Mar-14 22:29pm

ExpertITM

Updated 23-Mar-14 22:31pm

v2

Add a Solution

4 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Trajan McGill · Answer 1 · 2014-03-24T05:13:00

Solution 1

The page coming back from Google is not going to be jsonp. Try "html" as the dataType instead, if you want to load html.

Posted 24-Mar-14 5:13am

Trajan McGill

Comments

ExpertITM 29-Mar-14 12:56pm

hi,
I have try with datatype html/text, but its not load. responce is 200 ok but it gives empty responce,
Can you give me any code for the same
Thanks

kishore@cse · Answer 2 · 2014-03-24T06:08:00

Solution 2

You have take the json object data Type , but the google url doesn't give you that type and as well as HTML
So you can try that type of html and try to extract the data

Posted 24-Mar-14 6:08am

kishore@cse

Comments

ExpertITM 29-Mar-14 12:58pm

hi,
I have try with datatype html/text, but its not load. responce is 200 ok but it gives empty responce,
Can you give me any code for the same
Thanks

kishore@cse · Answer 3 · 2014-03-29T19:50:00

Solution 3

One thing I forgot to tell you, it is not possible to get the source code of any file like php , html ...etc

JavaScript

$("123.php",function(data){
    alert(data);
});

It is restricted in ajax and also in jquery , because

If You try to "alert(data)" that means whole source code is revealed , if it is php then it may be security problem.

Posted 29-Mar-14 19:50pm

kishore@cse

Comments

Trajan McGill 31-Mar-14 10:42am

Of course you can get the source code of an HTML file, because that's what is sent to the browser. The reason you can't get source for PHP or some other executable has nothing to do with ajax or jquery. It is because the server doesn't send the code, it sends the output from running the code, which is (usually) HTML.

ExpertITM 13-Apr-14 12:19pm

hello, I dont want php code. I just need html contant i.e. page source. I am not hacker!!
Thanks

**Nirav Prabtani** · Answer 4 · 2014-03-29T20:19:00

try this.....

C#

HttpWebRequest request = (HttpWebRequest)WebRequest.Create
            ("http://www.YourSiteUrl.com");

            //Method GET
            request.Method = "GET";

            //HttpWebResponse for result
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();


            //Mapping of status code
            if (response.StatusCode == HttpStatusCode.OK)
            {
                Stream receiveStream = response.GetResponseStream();
                StreamReader readStream = null;

                if (response.CharacterSet == "")
                    readStream = new StreamReader(receiveStream);
                else
                    readStream = new StreamReader(receiveStream, Encoding.GetEncoding(response.CharacterSet));

                //Get news data in json string
                //You will get html source here......
                string data = readStream.ReadToEnd();
             }

You will get source code in data string