Get the first visible item in a listview whose view property is tile.

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Hello everyone.
I have defined the following ListView with the View property in Tile mode, since it is assigned a list of images, ImageList1:

C#

ListView1.AllowDrop = true;
ListView1.View = View.Tile;
ListView1.FullRowSelect = true;
ListView1.GridLines = true;
ListView1.Columns.Add("indice", -2, HorizontalAlignment.Right);
ListView1.Columns.Add("nombre", -2, HorizontalAlignment.Left);
ListViewCanalesDelFichero.LargeImageList = ImageList1;

When I access the ListView.TopItem property to get the item that visually appears first in the ListView as follows,

C#

string item = ListView1.TopItem.SubItems[1].Text;

an exception is thrown:
"You can't get the top item in the LargeIcon, SmallIcon, or Tile view. "
The problem is in the View property that is in Tile. In View.Details mode there is no problem.
What do I have to do to, while maintaining the Tile mode, get the first visible item?

What I have tried:

The problem is in the View property that is in Tile.  In View.Details mode there is no problem.

Posted 15-Jul-22 21:36pm

pertenet

Updated 15-Jul-22 21:43pm

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Richard MacCutchan · Answer 1 · 2022-07-15T21:43:00

Solution 1

Look at the error message; it clearly states that you can only do this in Details view, as referred in the documentation at ListView.TopItem Property (System.Windows.Forms) | Microsoft Docs[^].

Posted 15-Jul-22 21:43pm

Richard MacCutchan

Member 1408653 · Answer 2 · 2024-05-18T00:59:00

This works for me

int FindFirstVisibleItem(Rectangle rectangle)
{
    foreach (ListViewItem item in Items)
    {
        if (item == null) continue;
        if (rectangle.IntersectsWith(item.Bounds))
        {                   
            Invalidate();
            return item.Index;
            }
        }
        return -1;
}

and call it as in as follows

int firstVisibleItem = FindFirstVisibleItem(new Rectangle(0, 0, e.Bounds.Width, e.Bounds.Height));
if (e.ItemIndex == firstVisibleItem)
    e.Graphics.DrawRectangle(Pens.Red, e.Bounds);