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Convert Numeric Currency into Words (For INDIAN Currency Only) (Optimized)

, 6 Sep 2011
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Converts from 0(zero) to 10^39(adant-shinghar) into words. E.g. 70250 into seventy thousand two hundred fifty


This is a simple program or a complicated one too that converts numeric value into words from 0 to 1039;... Great!!!

A Short introduction may be:

It can convert 0 to Zero, can also convert to 12345 to "twelve thousand three hundred forty five" and can also covert 1039 to 1 Adant-Shinghar. (Courtesy: Wikipedia for providing me with the notations.)

Before you move further, let me inform you first that this class will give you a returned value in string with HTML tags attached, so please use it for web application so that you will find neat and clean results and to use it for Windows Forms, please make the necessary changes.

So guys, let's dive into the logic !!!


Below is a snap shot provided to get the following results.

Using the Code

Let's dig into the code step by step.

Step 1

Take three static List<DictionaryEntry> Type objects for static data storage and load that in the constructor of class.

Have a look at the code snippets.

Constructor of the class:

namespace Hirs.IndianNumericToWordConverter
    public class IndiaCurrencyConverter
        private Hashtable htPunctuation;
        private Dictionary<int> DictStaticSuffix;
        private Dictionary<int> DictStaticPrefix;
        private Dictionary<int> DictHelpNotation;
        private System.Drawing.Color color;

        public IndiaCurrencyConverter()
            htPunctuation = new Hashtable();
            DictStaticPrefix = new Dictionary<int>();
            DictStaticSuffix = new Dictionary<int>();
            DictHelpNotation = new Dictionary<int>();
            Native = native;

Here is the method that loads static data with values.

private void LoadStaticSuffix()
            DictStaticSuffix.Add(1, "One ");
            DictStaticSuffix.Add(2, "Two ");
            DictStaticSuffix.Add(3, "Three ");
            DictStaticSuffix.Add(4, "Four ");
            DictStaticSuffix.Add(5, "Five ");
            DictStaticSuffix.Add(6, "Six ");
            DictStaticSuffix.Add(7, "Seven ");
            DictStaticSuffix.Add(8, "Eight ");
            DictStaticSuffix.Add(9, "Nine ");
            DictStaticSuffix.Add(10, "Ten ");
            DictStaticSuffix.Add(11, "Eleven ");
            DictStaticSuffix.Add(12, "Twelve ");
            DictStaticSuffix.Add(13, "Thirteen ");
            DictStaticSuffix.Add(14, "Fourteen ");
            DictStaticSuffix.Add(15, "Fifteen ");
            DictStaticSuffix.Add(16, "Sixteen ");
            DictStaticSuffix.Add(17, "Seventeen ");
            DictStaticSuffix.Add(18, "Eighteen ");
            DictStaticSuffix.Add(19, "Nineteen ");
            DictStaticSuffix.Add(20, "Twenty ");
            DictStaticSuffix.Add(30, "Thirty ");
            DictStaticSuffix.Add(40, "Forty ");
            DictStaticSuffix.Add(50, "Fifty ");
            DictStaticSuffix.Add(60, "Sixty ");
            DictStaticSuffix.Add(70, "Seventy ");
            DictStaticSuffix.Add(80, "Eighty ");
            DictStaticSuffix.Add(90, "Ninety ");
        private void LoadStaticPrefix()
                DictStaticPrefix.Add(2, "Thousand ");
                DictStaticPrefix.Add(3, "Lac ");
                DictStaticPrefix.Add(4, "Crore ");
                DictStaticPrefix.Add(5, "Arab ");
                DictStaticPrefix.Add(6, "Kharab ");
                DictStaticPrefix.Add(7, "Neel ");
                DictStaticPrefix.Add(8, "Padma ");
                DictStaticPrefix.Add(9, "Shankh ");
                DictStaticPrefix.Add(10, "Maha-shankh ");
                DictStaticPrefix.Add(11, "Ank ");
                DictStaticPrefix.Add(12, "Jald ");
                DictStaticPrefix.Add(13, "Madh ");
                DictStaticPrefix.Add(14, "Paraardha ");
                DictStaticPrefix.Add(15, "Ant ");
                DictStaticPrefix.Add(16, "Maha-ant ");
                DictStaticPrefix.Add(17, "Shisht ");
                DictStaticPrefix.Add(18, "Singhar ");
                DictStaticPrefix.Add(19, "Maha-singhar ");
                DictStaticPrefix.Add(20, "Adant-singhar ");
        private void LoadHelpofNotation()
            DictHelpNotation.Add(2, "=1,000 (3 Trailing Zeros)");
                DictHelpNotation.Add(3, "=1,00,000 (5 Trailing Zeros)");
                DictHelpNotation.Add(4, "=1,00,00,000 (7 Trailing Zeros)");
                DictHelpNotation.Add(5, "=1,00,00,00,000 (9 Trailing Zeros)");
                DictHelpNotation.Add(6, "=1,00,00,00,00,000 (11 Trailing Zeros)");
                DictHelpNotation.Add(7, "=1,00,00,00,00,00,000 (13 Trailing Zeros)");
                DictHelpNotation.Add(8, "=1,00,00,00,00,00,00,000 (15 Trailing Zeros)");
		(9, "=1,00,00,00,00,00,00,00,000 (17 Trailing Zeros)");
                DictHelpNotation.Add(10, "=1,00,00,00,00,00,00,00,00,000 
					(19 Trailing Zeros)");
                DictHelpNotation.Add(11, "=1,00,00,00,00,00,00,00,00,00,000 
					(21 Trailing Zeros)");
                DictHelpNotation.Add(12, "=1,00,00,00,00,00,00,00,00,00,00,000 
					(23 Trailing Zeros)");
                DictHelpNotation.Add(13, "=1,00,00,00,00,00,00,00,00,00,00,00,000 
					(25 Trailing Zeros)");
                DictHelpNotation.Add(14, "=1,00,00,00,00,00,00,00,00,00,00,00,00,000 
					(27 Trailing Zeros)");
                DictHelpNotation.Add(15, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(29 Trailing Zeros)");
		(16, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(31 Trailing Zeros)");
		(17, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(33 Trailing Zeros)");
		(18, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(35 Trailing Zeros)");
		(19, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(37 Trailing Zeros)");
		(20, "=1,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,00,000
					(39 Trailing Zeros)");

and I got comments on what is needed of List<DictionaryEntry> listHelpNotation so, the reason behind that is on Hovering you can get help its unit values.

Step 2

Now insert Input value (Let me notify you that input value will be in string because no datatype supports 1039).

Assume input value is 123456789.

First reverse the input string:


Then split and insert reversed string into hashtable (first 3 digit, and then after 2 till end):


and then reverse every splitted value inserted into hashtable so that it makes real sense.


and insert that to hashtable with key value pair using the following code:

private void InsertToPunctuationTable(string strValue)
            htPunctuation.Add(1, strValue.Substring(0, 3).ToString());
            int j = 2;
            for (int i = 3; i < strValue.Length; i = i + 2)
                if (strValue.Substring(i).Length > 0)
                    if (strValue.Substring(i).Length >= 2)
                        htPunctuation.Add(j, strValue.Substring(i, 2).ToString());
                        htPunctuation.Add(j, strValue.Substring(i, 1).ToString());


Now get the word notation for every value stored in hashtable descending.

Have a look at the code.

Here's the function:

GetWordConversion(string inputNumber)

It takes Stringconverted numeric value and gives its Word Conversation, It will take input which will have a maximum of 3 digits. You may remember from the upper hashtable that Entry has value which is maximum of 3 digits.

Explanation of Condition Check

if (int.Parse(inputNumber.Substring(0, 1)) > 0)

Checks if the first digit is not zero, then return Hundreds notation. E.g. 434 then it returns Four Hundred

string TempString = StaticSuffixFind(inputNumber.Substring(1, 2));

This condition checks that if the two digit value is already stored in List. E.g., it will return twelve with input of 12. Rather than returning One Two, and if it is 34 then No stored value will be found and it will pass the condition if(tempString == "") and will move on. The different condition will be applied to if the number is Two digit, or 1 digit.

private string GetWordConversion(string inputNumber)
            string ToReturnWord = String.Empty;
            if (inputNumber.Length <= 3 && inputNumber.Length > 0)
                if (inputNumber.Length == 3)
                    if (int.Parse(inputNumber.Substring(0, 1)) > 0)
                        ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(0, 1)) + "Hundred ";

                    string TempString = StaticSuffixFind(inputNumber.Substring(1, 2));

                    if (TempString == "")
                        ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(1, 1) + "0");
                        ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(2, 1));
                    ToReturnWord = ToReturnWord + TempString;
                if (inputNumber.Length == 2)
                    string TempString = StaticSuffixFind(inputNumber.Substring(0, 2));
                    if (TempString == "")
                        ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(0, 1) + "0");
                        ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(1, 1));
                    ToReturnWord = ToReturnWord + TempString;
                if (inputNumber.Length == 1)
                    ToReturnWord = ToReturnWord +
			StaticSuffixFind(inputNumber.Substring(0, 1));
            return ToReturnWord;

After that, attach the following splitted words from the splitted hashtable value and their notation and make the one big string that will depict the whole notation:

private string ReturnHashtableValue()
            string strFinalString = String.Empty;
            for (int i = htPunctuation.Count; i > 0; i--)
                if (GetWordConversion((htPunctuation[i]).ToString()) != "")
                    strFinalString = strFinalString +
			GetWordConversion((htPunctuation[i]).ToString()) +
            return strFinalString;

Points of Interest

For now, I have submitted code for Indian currency only. Now for moving further in part-II, I will also depict how to covert in international currency as suggested by Indian mentors from Indian forums.

FYI, Part-II is published. Have a look:

And last but not the least, thanks to the audience for giving your votes and valuable time.

For further details, please see the attached class.


  • This is Part-I. Part-II has been submitted for international currency.


This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)


About the Author

Hiren solanki
Software Developer
India India
He is a Smart IT devloper with Few years of Expeariance But having Great command on,C#,SQL Query,SSRS,Crystal Reports
Apart from that He Loves multimedia work too, Master of Adobe photoshop, Illustrator, CSS , HTML and all things.
He is Currently working in Microsoft Dynamics CRM and Having Nice Expearince with CRM. CRM Rocks!!!

Comments and Discussions

QuestionQ 1 Pinmembersofyan_fly25-Jan-13 2:17 
AnswerRe: Q 1 PinmemberHiren solanki24-Mar-14 5:31 
QuestionThanks Pinmemberrahulkanojia20026-Sep-12 20:22 
GeneralMy vote of 4 Pinmembermanoj kumar choubey2-Feb-12 22:46 
GeneralMy vote of 5 PinmemberGPUToaster™4-Oct-11 1:26 
QuestionWorks only till 999 Pinmemberarunglobal23-Aug-11 20:43 
AnswerRe: Works only till 999 PinmemberHiren solanki5-Sep-11 1:08 
Sorry for the inconvenience I found little bug in the code.
Article is very old so I can't attach working file instantly, I've intimated code project about this they will attach working copy soon.
-"I don't know, I don't care, and it doesn't make any difference".

General[My vote of 1] OMG i've never seen... PinmemberSelvin27-Dec-10 0:54 
GeneralRe: [My vote of 1] OMG i've never seen... PinmemberHiren Solanki27-Dec-10 0:58 
Generalgood work PinmemberPranay Rana15-Dec-10 20:16 
GeneralRe: good work PinmemberHiren Solanki15-Dec-10 20:17 
GeneralMy vote of 5 PinmemberGPUToaster20-Oct-10 1:07 
GeneralRe: My vote of 5 PinmemberHiren Solanki28-Oct-10 0:49 
GeneralGood one Hiren! PinmemberSushant Joshi22-Sep-10 19:46 
GeneralRe: Good one Hiren! PinmemberHiren Solanki22-Sep-10 19:49 
GeneralMy vote of 5 PinmemberProsanta Kundu online12-Sep-10 18:33 
GeneralRe: My vote of 5 PinmemberHiren Solanki12-Sep-10 19:31 
GeneralMy vote of 2 [modified] PinmemberNagy Vilmos10-Sep-10 3:23 
AnswerRe: My vote of 2 PinmvpAbhijit Jana10-Sep-10 7:14 
GeneralRe: My vote of 2 PinmentorKunalChowdhury10-Sep-10 7:57 
GeneralRe: My vote of 2 PinmvpAbhijit Jana10-Sep-10 8:27 
GeneralRe: My vote of 2 PinmemberHiren Solanki10-Sep-10 17:12 
GeneralRe: My vote of 2 [modified] PinmemberHiren Solanki10-Sep-10 19:11 
GeneralMy vote of 3 Pinmemberkarabax1-Sep-10 6:00 
GeneralRe: My vote of 3 PinmemberHiren Solanki5-Sep-10 19:30 

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