Math Parser

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• Download demo project - 13.06 KB

Introduction

This is a parser which uses RegEx to solve mathematical expressions.

How To Use It?

MathParser.Parser p = new MathParser.Parser();
if( p.Evaluate( "-(5-10)^(-1)(3+2(cos(3Pi)+(2+ln(exp(1)))^3))" ) ) 
    Console.WriteLine( p.Result );
else Console.WriteLine( "Error." );

Features

• Functions
• abs
• acos
• asin
• atan
• cos
• cosh
• floor
• ln
• log
• sign
• sin
• sinh
• sqrt
• tan
• tanh
• Operators: +, -, *, , ^, !
• Constants: Pi

Choose between RAD, DEG and GRAD.

p.Mode = MathParser.Mode.RAD;
p.Mode = MathParser.Mode.DEG;
p.Mode = MathParser.Mode.GRAD;

Or:

Parser p = new Parser( MathParser.Mode.DEG );

2(1+3(1e3+1)) = 2*(1+3*(1000+1)) = 2*(1+3(1000+1)) = 2(1+3*(10^3+1)) = 6008

2(1+4(5Pi+2,2e3)(5+2)^3) is the same as 2*(1+4*(5*Pi+2200)*(5+2)^3).

Known Problems

I tested this parser on a German operating system (WinXP).
If I want to convert a string to double (e.g. "3.123") the decimal point must be a "," (Convert.ToDouble("3.123") would throw an Exception).
I'm not sure if this works on an English version of WinXP.

If there are any problems with the decimal point, just report it and I will fix it.

Bug Fixes

• Fixed some problems with exponents

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)