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Decimal to English Fraction Algorithm

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23 Jan 20052 min read 87.2K   14   12
A four line algorithm in MC++ for converting decimals to fractions.

Introduction

A four line algorithm in MC++ for converting a decimal value to three separate pieces: units, numerator, denominator. Their results are suitable to format a string.

Formula

The basic formula is to divide the right side of the decimal value by the decimal equivalent of the fractional measure and round to an integer. This becomes the numerator over the desired denominator (of the conversion fraction). Thus, for converting to an eighth, as 1/8 is .125, one divides the IEEERmainder() of the decimal by .125 to obtain a numerator over 8.

Convert 3.6742 to 16th: .6742/.0625 = 10.7872. 10.7872 rounds to 11 creating the fraction 11/16. The result is three and eleven sixteen (3 11/16).

Convert 3.6742 to 8th: .6742/.125 = 5.3936 = 5/8. The result is three and five eighth. (3 5/8).

I use Math::IEERemainder(decimal, 1.0) to separate the decimal from the single value, and Math::floor(decimal) to separate the units. If the decimal part is greater than .5 then the Math algorithm returns a negative complement, and must be subtracted from one. Thus the line:

if (Math::Sign(remainder) == -1) remainder = 1 + remainder

.6742 returns -0.32579942, which, when added to 1.0 results in .6742008.

Due to this check of the sign the algorithm only works for positive numbers.

The Algorithm:

(The decimal and denominator are input)

Single remainder = Math::IEEERemainder(decimal, 1.0);
if (Math::Sign(remainder) == -1) remainder = 1 + remainder;
Int32  units = Convert::ToInt32(Math::Floor(decimal));
Int32  numerator = Convert::ToInt32(Math::Round(remainder/denominator));

Other considerations;

For flexibility, one would prefer to provide an integer specifying the desired conversion rather than hard code, say, .125 as the denominator. Thus input an integer numerator and compute the divisor.

// compute the fractions numerator
Single divisor = Convert::ToSingle(1)/Convert::ToSingle(denominator);
Int32 numerator = Convert::ToInt32(Math::Round(remainder/divisor));

The algorithm only works for positive decimals, thus one needs to test for flag, correct and restore negativity. Further, problems that need to be considered are the rounding down to zero and rounding up to the next unit, and reduction of the fraction. The following code accounts for these.

The following code was written for a very specific purpose: to convert English inch measurement fractions, specifically, the common fractions 1/8, 1/4 and 1/2. (Although I tested to 1/32.) I was not interested in fractions like 1/5 or 1/7 or 1/324 whatever. The algorithm may be useful to help those, but not the example function. The code is not generalized. But the algorithm is. The code is only provided as a wrapper example.

Code:

MC++
#pragma warning( disable : 4244 )  // possible loss of data due to conversion
// Convert a Single to a string fraction of the 
// form "integer numerator/denominator"
String* Utils::Form1::SingleToStringFraction(Single decimal, Int32 denominator)
{
   // Input must be positive so save and restore the negative if necessary.
   bool isneg = (Math::Sign(decimal) == -1) ? true : false;
   if (isneg) decimal *= -1;

   // obtain the decimal and units parts of the input number
   Single remainder = Math::IEEERemainder(decimal, 1.0);
   if (Math::Sign(remainder) == -1) remainder = 1 + remainder;
   Int32  units = Convert::ToInt32(Math::Floor(decimal));

   // compute the fractions numerator
   Single divisor = Convert::ToSingle(1)/Convert::ToSingle(denominator);
   Int32 numerator = Convert::ToInt32(Math::Round(remainder/divisor));

   String* fraction;

   // Handle an error or condition or reduce the fraction
    // and convert to a string for the return.
   if ((numerator > 0) && (numerator == denominator))
   {
      // than fraction is one full unit
      units++;
      fraction = S"";
   }
   else if (numerator == 0)
   {
      // as numerator is 0, no fraction
      fraction = S"";
   }
   else
   {
      // reduce
      while (numerator%2 == 0)
      {
         numerator   /= 2;
         denominator /= 2;
      }
      fraction = String::Format(" {0}/{1}",
                   numerator.ToString(), denominator.ToString());
   }

   // restore negativity
   if (isneg) units *= -1;

#ifdef _DEBUG_CUT
   String* rtnstr;
   if (isneg) decimal *= -1;
   rtnstr = String::Format("{0}{1}", units.ToString(), fraction);
   Diagnostics::Trace::WriteLine(rtnstr, decimal.ToString());
#endif

   return String::Format("{0}{1}", units.ToString(), fraction);
}
#pragma warning( default : 4244 )

Caveat

I have never claimed to know everything. And, my MC++ skills may be lacking. If you know of a better and more efficient algorithm, or can improve on the quality of the above code, please comment. In the program that I am working on, I will be going back and forth from fractions to decimals regularly. Efficiency would be nice.

Oh yes, one could simply convert to a string and use split on S"."; but what fun in that? And using Math to split the Single qualifies as an algorithm while splitting a string does not.

License

This article has no explicit license attached to it but may contain usage terms in the article text or the download files themselves. If in doubt please contact the author via the discussion board below.

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Written By
Retired
United States United States
Retired C programmer and Unix Sys Admin, then VC6 C++ MFC programmer. I moved to VC7 C++ 2003 in Oct of 04, and VC8 C++/CLI early in 06. I resisted C#; but now it is my preferred language. I'm through with upgrading. I'll stay at VC2008 and C#, as I only program for fun anymore.

Update 2019: I have moved back to Unix: Linux Cinnamon Mint. I got aggravated with Windows and VC. I've returned to my roots. Now, my preferred language is Java. I use IntelliJ as my IDE; but write my code with Emacs. I thoroughly enjoy Linux and being back on Unix! I've published a little game on the Kindle Fire and a little apt for Android phones. I hope you still love to code as much as I do when you reach my age... advanced 70's.

Comments and Discussions

 
GeneralMy vote of 5 Pin
Manoj Kumar Choubey14-Mar-12 0:28
professionalManoj Kumar Choubey14-Mar-12 0:28 
GeneralBase 2 fractions Pin
Jaen18-Jun-05 13:46
Jaen18-Jun-05 13:46 
GeneralA few points Pin
Chris Hills17-Jan-05 23:35
Chris Hills17-Jan-05 23:35 
GeneralRe: A few points Pin
Gammill18-Jan-05 9:46
Gammill18-Jan-05 9:46 
GeneralSingle limits to only 7 digits Pin
Gammill16-Jan-05 19:00
Gammill16-Jan-05 19:00 
GeneralOthers of set of 3 Pin
Gammill16-Jan-05 12:10
Gammill16-Jan-05 12:10 
GeneralRe: Others of set of 3 Pin
WoR16-Jan-05 23:45
WoR16-Jan-05 23:45 
GeneralRe: Others of set of 3 Pin
Gammill17-Jan-05 14:10
Gammill17-Jan-05 14:10 
GeneralRe: Others of set of 3 Pin
rvdt25-Jan-05 20:33
rvdt25-Jan-05 20:33 
Lets redo your example to show what was meant:

Convert 3.6742 to 16ths: .6472 * 16 = 10.7872 = 11 ==> 11/16 ==> result 3 11/16
Convert 3.6742 to 8ths: .6472 * 8 = 5.3936 = 5 ==> 5/8 ==> result 3 5/8

You just do not need to calculate 1/8 or 1/16 etc.

---

You can calculate the remainder in one step less if you
first calculate the units. see pseudo code below.
furthermore make the denominator parameter unsigned.


So far my two cents,
rob

---

string ToFraction(double decimal, uint denominator, bool reduce)
{
int sign = sign(decimal); // keep sign as int
decimal *= sign; // no need for bool test here

int units = (int) floor(decimal);
Double remainder = decimal - units;
int numerator = round(remainder * denominator);
units *= sign; // no bool test here

if (numerator == 0)
{
// convert units to string s
}
else
{
if (reduce)
{
// reduce factor 2 code or GCD code here
}
// convert units, num, denom to string s
}
return s;
}


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