Comments by Member 12599631

Member 12599631 4-Sep-16 10:58am View

local IIS Express how to settings ...

Member 12599631 30-Aug-16 5:27am View

thanks

Member 12599631 30-Aug-16 5:20am View

Thanks so much

Member 12599631 30-Aug-16 4:25am View

string name = txtname.Text;

string country = txtcountry.Text;
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
using (SqlCommand cmd = new SqlCommand("sp_customers_Add"))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@Action", "INSERT");
cmd.Parameters.AddWithValue("@Name", name);
cmd.Parameters.AddWithValue("@Country", country);
cmd.Connection = con;
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
this.BindGrid();

i give the identity(1,1) for customerid in database

Member 12599631 30-Aug-16 4:22am View

string name = txtname.Text;

string country = txtcountry.Text;
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
using (SqlCommand cmd = new SqlCommand("sp_customers_Add"))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@Action", "INSERT");
cmd.Parameters.AddWithValue("@Name", name);
cmd.Parameters.AddWithValue("@Country", country);
cmd.Connection = con;
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
this.BindGrid();

Member 12599631 23-Aug-16 3:43am View

thanks

Member 12599631 23-Aug-16 3:37am View

Thanks

Member 12599631 23-Aug-16 3:32am View

m = m + int.Parse(salary.Text);

Member 12599631 22-Aug-16 4:40am View

thanks

Member 12599631 22-Aug-16 3:19am View

thanks

Member 12599631 5-Aug-16 5:44am View

Thank you

Member 12599631 5-Aug-16 4:19am View

yes

Comments by Member 12599631 (Top 12 by date)