You have an error in your SQL syntax; check the manual that corresponds to your MySQL

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hi
I have error in my project
this error comes

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

when
I make a list in aa.php
then get sID in advisor.php

inside 2 files
first: aa.php

PHP

        $db_name="coop";
        $tbl_name="students";
        mysql_connect("localhost", "root", "");
        mysql_select_db("$db_name");
        session_start();
$tID=$_SESSION['tID'];
        $sql=mysql_query("SELECT * FROM $tbl_name WHERE advisor=$tID") or die(mysql_error());
        while($mysqlf =mysql_fetch_array($sql))
        {
            $student=$mysqlf['sname'];
            //echo "$student &nbsp&nbsp&nbsp";
            $sid=$mysqlf['sID'];
            //echo"$sid<br>";
            echo "<center></font><a href='advisor.php?students=$student'>".$mysqlf['sname']."</a>&nbsp;&nbsp;&nbsp;&nbsp;".$mysqlf['sID']."</label>";
        }?>

second: advisor.php

PHP

    $sID = $_GET['students'];
    $db_name="coop";
        $tbl_name="students";
        mysql_connect("localhost", "root", "");
        mysql_select_db("$db_name");
        $sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=.$sID.") or die(mysql_error());
        $mysqlf =mysql_fetch_array($sql);
            $sID=$mysqlf['sID'];
            echo "$sID<br>";;
?>

how can I solve this problem?

thanks for all

Posted 25-May-11 13:57pm

malemar

Updated 25-May-11 17:03pm

thatraja

v3

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Comments

Orcun Iyigun 25-May-11 20:15pm

There are two reasons for this:

1-The command that you are trying to execute doesn't have a valid syntax.

2-There is a mismatched data that query that you have. Like an inter value on string value or vice-a-versa.

also try deactivating your bulletins.

ZeeroC00l 25-May-11 22:30pm

-- edited pre tag

1 solution

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Kim Togo · Answer 1 · 2011-05-25T22:41:00

Solution 1

Either $tbl_name, $tID $sID is empty and have no value or the value is not valid for SQL statement.

The line

PHP

$sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=.$sID.") or die(mysql_error());

Has to be changed to

PHP

$sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=".$sID) or die(mysql_error());

Posted 25-May-11 22:41pm

Kim Togo

Comments

malemar 26-May-11 4:56am

when I change this line
$sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=.$sID.") or die(mysql_error());
to this
$sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=".$sID) or die(mysql_error());
appear this line an page
Unknown column 'Abrar_Saad_Al' in 'where clause'
and also
this name "Abrar_Saad_Al" inside the data base is like this "Abrar_Saad_Al-Rifaes"

Kim Togo 26-May-11 5:06am

I think the error "Unknown column", has nothing to do with the change in SQL statement. There is not reference to "Abrar_Saad_Al" column in the SELECT statement.

I think the error is farther down the PHP file.

malemar 26-May-11 5:23am

I also think the error in the query

did you thing there are anther solution??

thank you Kim Togo

Kim Togo 26-May-11 5:38am

The line

$sql=mysql_query("SELECT sID FROM ".$tbl_name." WHERE sID=".$sID) or die(mysql_error());

Does not have any relation to column "Abrar_Saad_Al".
Is there other SQL statements in the PHP file that requires column "Abrar_Saad_Al" ?

malemar 26-May-11 5:40am

loooooooool
I solved it
thanks Mr. Kim Togo