Can't call two stored procedures

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PHP

$result = mysql_query("CALL verCamasDisponiveis('".$_SESSION['pID']."')")
or die ("Erro-- ".mysql_error());

$camasd = mysql_fetch_array($result);
$n = $camasd['Count(Descricao)'];

mysql_free_result($result);

$result = mysql_query("CALL verMobiliario('".$_SESSION['pID']."')")
or die ("Erro1-- ".mysql_error());

Both returns only one field/row.

At the second I get

Commands out of sync; you can't run this command now

I have php5. At Mysql shell those procedures work fine. How can I solve this?

Posted 26-May-11 10:35am

Maxdd 7

Updated 31-May-11 7:13am

v3

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Manfred Rudolf Bihy · Answer 1 · 2011-05-26T11:03:00

Solution 1

Since we only have the two lines of code you posted, I'll give it a shot and refer you to this interesting bit I found: http://dev.mysql.com/doc/refman/5.0/en/commands-out-of-sync.html[^].

I hope that explains your misery ;)!

Cheers!

-MRB

Posted 26-May-11 11:03am

Manfred Rudolf Bihy

Comments

Maxdd 7 31-May-11 13:12pm

Unfortunately not :(

Those two procs just have two SELECT statements:

SELECT Count(Descricao) FROM Inventario WHERE CelaID IS NULL AND Descricao = 'Cama' AND pID = prID;

I tried the mysql_free_result but don't work :( Check out my updated answer..

" It can also happen if you try to execute two queries that return data without calling mysql_use_result() or mysql_store_result() in between"

PHP5 does not have any of those ..

Maxdd 7 31-May-11 13:22pm

All information I found it was referring to mysqli, but I don't use that.