the problem of Activator.CreateInstance()

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Assembly a = Assembly.Load("Dll file");
 Type theType = a.GetType("ClassName");   
dynamic agDrvr = Activator.CreateInstance(ClassType);

this is the common function to create the instance of some Class by use reflection

in the above of common function ,I just know the class name ,not the class type ,

so how can I make the result of the [Activator.CreateInstance(ClassType)] from the

type of Object to the type of class whitch name is [className];

Posted 12-Dec-10 23:49pm

lmhf004

Updated 12-Dec-10 23:52pm

Toniyo Jackson

v2

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Toniyo Jackson 13-Dec-10 5:52am

Always put your code inside code block

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E.F. Nijboer · Answer 1 · 2010-12-13T00:09:00

Solution 1

You could use this:

Activator.CreateInstance("Dll file", "ClassName");

You can get the assembly name (firs parameter of CreateInstance above) from the Assembly object opr could also directly create an instance using that Assembly object:

Assembly a = Assembly.Load("Dll file");
MyObject o = a.CreateInstance("ClassName");

http://msdn.microsoft.com/en-us/library/dex1ss7c.aspx[^]

Good luck!

Posted 13-Dec-10 0:09am

E.F. Nijboer

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lmhf004 13-Dec-10 6:24am

But I don't know the type of [MyObject ]

E.F. Nijboer 13-Dec-10 7:25am

Ah, ok. In that case you can simply use the GetTypes method of Assembly to traverse all of the defined types.
http://msdn.microsoft.com/en-us/library/system.reflection.assembly.gettypes.aspx