.How can I give the Initial Directory is in the bin folder

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Hi I am using OpenFileDialog box  in windows form ..How can I give the Initial Directory is in the bin folder ,it never go for any ware in the mycomputer  Directory

Below is my code Can any one tel me ...Below is my code

VB

Private Sub linkTemplate_LinkClicked(ByVal sender As System.Object, ByVal e As System.Windows.Forms.LinkLabelLinkClickedEventArgs) Handles linkTemplate.LinkClicked
        Dim oImport As New OpenFileDialog()
        oImport.Title = "Save As"
        oImport.InitialDirectory = "BeTrans\bin\Debug\"''Hear only i need to Changer the Directory (bin floter)
        'oImport.FileName = txtDocEntry.Text
        oImport.Filter = "Excel Sheet(*.xls)|*.xls|Excel Sheet(*.xlsx)|*.xlsx"
        oImport.FilterIndex = 1
        oImport.RestoreDirectory = True
        If oImport.ShowDialog() = DialogResult.OK Then
            'txtDocEntry.Text = Import.FileName;
            'Import(oImport.FileName)
            Application.DoEvents()
        End If
    End Sub

Posted 14-Nov-13 19:40pm

DhananjayanP

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Sergey Alexandrovich Kryukov 15-Nov-13 1:55am

There is no such thing as "bin folder". There is just the "Output directory", which can be anything.
—SA

2 solutions

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Sergey Alexandrovich Kryukov · Answer 1 · 2013-11-14T19:56:00

Please see my comment to the question.

It's likely that you need executable directory. Anyway, please see two of my past comprehensive answers:
How to find my programs directory (executable directory),
How to find my programs directory (current directory, "special folders").

If this is how I understood your problem, you will need to combine these two answers: first, read executable directory, and set current directory to the same value.

—SA

basurajkumbhar · Answer 2 · 2013-11-14T23:56:00

Solution 2

VB

Dim dlg As New OpenFileDialog
            dlg.InitialDirectory = Application.StartupPath
           
Here Startupath is in Bin folder..
 dlg.InitialDirectory = "'Here you can enter you path

I hope this will helpful for you...

Posted 14-Nov-13 23:56pm

basurajkumbhar

Comments

sp_suresh 15-Nov-13 6:08am

basurajkumbhar is right you have to provide application startup path as initial directory

basurajkumbhar 15-Nov-13 6:11am

ok