How Can I Display Message With The Help Of Webservice..If A Is Greater Than B

Question

1.00/5 (1 vote)

See more:

C#

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Services;

namespace WebService2
{
    /// <summary>
    /// Summary description for Service1
    /// </summary>
    [WebService(Namespace = "http://tempuri.org/")]
    [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
    [System.ComponentModel.ToolboxItem(false)]
    // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line.
    // [System.Web.Script.Services.ScriptService]
    public class Service1 : System.Web.Services.WebService
    {

        [WebMethod]
        public int add( int a, int b)
        {
            if (a > b)
            {

            }
            int c;
            c = a + b;
            return c;
        }
    }
}

Posted 1-Dec-14 19:14pm

Member 10874581

Add a Solution

Comments

KaushalJB 2-Dec-14 1:22am

Unclear !!

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

DamithSL · Answer 1 · 2014-12-01T19:25:00

Solution 1

you can return object, create class like below

C#

public class Results
{
   public string Message {get; set;}
   public int Value {get; set;}
}

then

C#

[WebMethod]
 public Results  add( int a, int b)
 {
     Results res new Results();  
     if (a > b)
     {
         res.Message ="a is grater than b";
     }

     res.Value = a + b;
     return res;
 }

when you call

C#

localhost.Service1 client = new localhost.Service1();
int a = int.Parse(TextBox1.Text);
int b = int.Parse(TextBox2.Text);
var res = client.add(a, b);
LabelValue.Text = "Add Result : " + res.Value;
LabelMessage.Text = "Add Message : " + res.Message;

Posted 1-Dec-14 19:25pm

DamithSL

Updated 1-Dec-14 21:20pm

v3

Comments

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 2-Dec-14 1:42am

Cool. +5.

DamithSL 2-Dec-14 1:42am

Thank you Tadit

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 2-Dec-14 2:04am

Welcome bro. :)

Member 10874581 2-Dec-14 2:49am

protected void Button1_Click(object sender, EventArgs e)
{
localhost.Service1 tt = new localhost.Service1();
int a = int.Parse(TextBox1.Text);
int b = int.Parse(TextBox2.Text);
int yy = tt.add(a, b);
Label3.Text = "add" + yy.ToString();

}
error is coming

DamithSL 2-Dec-14 3:23am

after you update your web method, right click your web service reference and update it, then it will reflect web service changes to your client application.

check my updated answer, you will get object with two properties ( message and value)

Member 10874581 2-Dec-14 2:48am

protected void Button1_Click(object sender, EventArgs e)
{
localhost.Service1 tt = new localhost.Service1();
int a = int.Parse(TextBox1.Text);
int b = int.Parse(TextBox2.Text);
int yy = tt.add(a, b);
Label3.Text = "add" + yy.ToString();

}

Member 10874581 2-Dec-14 2:29am

not working

/\jmot · Answer 2 · 2014-12-01T19:59:00

Solution 2

C#

[WebMethod]
 public String add( int a, int b)
 {
   String res="";
     if (a > b)
     {
         res="a is grater than b";
     }
     return res;
 }

Posted 1-Dec-14 19:59pm

/\jmot

Badal Kumar · Answer 3 · 2014-12-01T21:57:00

Solution 3

You can throw the exception by using SOAP FAULT message. See article about soap fault

Posted 1-Dec-14 21:57pm

Badal Kumar