How to reverse a number ending with zero C#

Question

1.00/5 (2 votes)

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Hi,

i have below code

C++

fiveDigNo=17660;

while (fiveDigNo!= 0)
{
   reverse = reverse * 10;
   reverse = reverse + fiveDigNo% 10;
   fiveDigNo= fiveDigNo/ 10;
}

I want to get reverse like 06671. But i am getting 6671.

What I have tried:

Reverse Function .

Posted 2-May-16 3:08am

nikhil2015

Updated 16-Nov-21 19:19pm

PIEBALDconsult

v2

Add a Solution

6 solutions

Solution 4

Quote:
I want to get reverse like 06671. But i am getting 6671.

The result is perfectly normal. Because 06671 and 6671 are the same value.
In order to handle a leading zero, the only way is to use a string instead of a numeric value. reversing the string "17660" will give you "06671".

Otherwise, you need to give us more information about the usage of this reverse.

Posted 2-May-16 4:45am

Patrice T

Solution 6

C#

"I want to get reverse like 06671. But i am getting 6671."

That's the same right?

With the reverse function, you might have got a string. Convert 06671 to numeric and you will have the results.

Posted 2-May-16 18:19pm

Abhinav S

Solution 10

#include<iostream>
#include <string>
using namespace std;

int reverseDigits(int num)
{
string strin=to_string(num); //covert integer to char to print zero.
reverse(strin.begin(), strin.end());
num=stoi(strin);
cout<<"Reverse of num entered: ";
for(char p:strin){
cout<<p;
}

="" return="" 0;
="" }

int="" main(){
="" int="" num;
="" cout<<"enter="" a="" number="" :="" ";
="" cin="">>num;
reverseDigits(num);
cout<

Posted 16-Nov-21 19:19pm

Member 15433673

Comments

Richard Deeming 17-Nov-21 6:07am

Your unformatted, unexplained code-dump is not a "solution" to this already-solved question.

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Sergey Alexandrovich Kryukov · Accepted Answer · 2016-05-02T03:15:00

Solution 1

This is the same. 06671 = 6671. Isn't it obvious?

If you want to obtain "06671", it it not about your number, this is about the way you present the number as a string:
Int32.ToString Method (System)[^],
Int32.ToString Method (String) (System)[^],
Standard Numeric Format Strings[^],
Custom Numeric Format Strings[^].

Strictly speaking, the problem "reverse a number" wasn't correctly defined. For example, you would get different result if you "reverse" the number's octal, hexadecimal digits, and so on. So, you could, alternatively, simply get a string first, via ToString or in some other way, and then reverse that string.

—SA

Posted 2-May-16 3:15am

Sergey Alexandrovich Kryukov

Updated 2-May-16 3:20am

v2

Comments

CPallini 2-May-16 9:28am

5.

Sergey Alexandrovich Kryukov 2-May-16 9:31am

Thank you, Carlo.
—SA

George Jonsson 2-May-16 10:03am

Definitely a 5.
Don't know how many "formatting issues" for either numbers or dates I have seen lately, because people think data is stored in memory the same way as it is shown on screen.

Sergey Alexandrovich Kryukov 2-May-16 10:11am

Thank you, George. Worse, many behave as if the only kind of data were strings... Wasted...
—SA

George Jonsson 2-May-16 10:18am

True, especially when dates are stored in a database column as a string in some odd format, and then problems occur when the date is to be manipulated in some way.

ridoy 2-May-16 13:22pm

exactly, a 5.

Sergey Alexandrovich Kryukov 2-May-16 14:44pm

Thank you.
—SA

CPallini · Accepted Answer · 2016-05-02T03:17:00

Solution 2

'06671' and '6671' are two different string representations of the same integer number. That is, if you really need the leading 0 in the output then you have to change your integer variable into a string one, sooner or later.

Posted 2-May-16 3:17am

CPallini

Comments

Sergey Alexandrovich Kryukov 2-May-16 9:21am

I guess, we answered at the same time... 5ed.
—SA

CPallini 2-May-16 9:29am

You know, great minds... :-)

Sergey Alexandrovich Kryukov 2-May-16 9:33am

In our culture, the proverb is different, it's something like
"Fools' thoughts match..."
—SA

CPallini 2-May-16 11:45am

I guess your culture is right.

Sergey Alexandrovich Kryukov 2-May-16 12:28pm

:-)

ridoy 2-May-16 13:23pm

a 5 too, :)

CPallini 2-May-16 15:34pm

Thank you.

Jochen Arndt · Accepted Answer · 2016-05-02T03:22:00

Solution 3

The numbers 06671 and 6671 are numerical identical. If you want a result like "06671" (a string representation) you have to use a string and reverse that:

C#

string numString = fiveDigNo.ToString();
char[] charArray = numString.ToCharArray();
Array.Reverse(charArray);
string revString = new string(charArray);
// If you need the numeric value too:
int revNumber = Convert.ToInt32(revString);

Posted 2-May-16 3:22am

Jochen Arndt

Updated 2-May-16 20:24pm

v2

Comments

nikhil2015 3-May-16 1:04am

string revString = new string(Array); showing error as "Array is a type,which is not valid in the given context"

int revNumber = revString.ToInt32(); as "string doesnot contain a definition for ToInt32" and no extension method 'ToInt32' accepting a first argument of type string could be found

Jochen Arndt 3-May-16 2:23am

I had just typed in the answer and made two mistakes:
Array should be charArray
and it must be Convert.ToInt32(revString)
I will update my answer.

nikhil2015 4-May-16 1:43am

string myString = fiveAddNumber.ToString();
char[] arrayR = myString.ToCharArray();
Array.Reverse(arrayR);

revString = new string(arrayR);

I got the solution from above code

Thanks Jochen Arndt