Fast and best way get content string in words

Question

1.00/5 (1 vote)

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i have code like this :

input :

dim msg as string = "Agen 05, Pembelian SM5.08132166171 Hrg=5500 SUKSES SN: 3778882223. Saldo Rp.(Awal 780700 Akhir 775200)"

and i hope string output :
SN: 3778882223

hope you help,

What I have tried:

i try

'Dim arr As String() = Regex.Split(msg, "\W+")
'For Each msg In arr
' MessageBox.Show(sPesan)
'Next

Posted 9-Aug-16 17:47pm

ulungss

Updated 9-Aug-16 18:37pm

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3 solutions

Solution 2

You should learn RegEx (Regular Expressions)
Here is documentation
perlre - perldoc.perl.org[^]
End a few tools to help building and debug a RegEx:
Debuggex: Online visual regex tester. JavaScript, Python, and PCRE.[^]
.NET Regex Tester - Regex Storm[^]
Expresso Regular Expression Tool[^]

Posted 9-Aug-16 18:36pm

Patrice T

Comments

ulungss 10-Aug-16 4:43am

thanks for reference....

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Peter Leow · Accepted Answer · 2016-08-09T18:27:00

Try this:

VB.NET

Imports System
Imports System.Text.RegularExpressions
				
Public Module Module1
	Public Sub Main()
		
		Dim regex As Regex = New Regex("SN: \d+")
		Dim match As Match = regex.Match("Agen 05, Pembelian SM5.08132166171 Hrg=5500 SUKSES SN: 3778882223. Saldo Rp.(Awal 780700 Akhir 775200)")
		If match.Success Then
	    	Console.WriteLine(match.Value)
		End If

	End Sub
End Module

Learn more:
1. The 30 Minute Regex Tutorial[^]
2. http://www.dotnetperls.com/regex-vbnet[^]

Mehdi Gholam · Accepted Answer · 2016-08-09T18:37:00

Solution 3

Use the regex SN\s*:\s*(\d*) like this :

VB.NET

Dim match As Match = Regex.Match(inputstring, "SN\s*:\s*(\d*)",  RegexOptions.IgnoreCase)
	If match.Success Then
	    ' Write value.
	    MessageBox.Show(match.Groups(1)) ' will give 3778882223
	End If

Posted 9-Aug-16 18:37pm

Mehdi Gholam

Updated 9-Aug-16 18:40pm

v2