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I noticed today when editing a program on Visual C++ 2015 that if I left a variable undeclared, it showed underlined in red, similar to misspellings in Word for Windows. That is useful. Thanks to whoever put that feature in.
Hi i am using following code for silent installation of MSI am getting 2203 error.
This is the code i am using.
Not working if i pass domain Administrator username and password, it is giving error like "The installer has encountered an unexpected error installing this package. This may indicate a problem with this package. The error code is 2203".
Can anyone tell me how to resolve this issue.
Note: It is working fine if i pass the local/Built-in administrator username and password.
As well as i tried only with following code also no luck.
CreateProcessWithLogonW(strUserName, strDomainName, strPassWord, LOGON_WITH_PROFILE, NULL, CT2W(strTempFolderToDownload),CREATE_UNICODE_ENVIRONMENT, NULL, NULL, &si, &pi );
1.) I am trying to install in C:\Program Files(x86)\ folder.
2.) I logged in as non admin user, am trying to install the MSI with domain Administrator credentials am using CreateProcessWithLogonW to do this.
3.) Yes, i copied the installer into temp location.
In that case, if the command line your code generated works if an admin on the machine runs it, the problem is going to be in your code that logs in as an admin, but apparently doesn't run anything as an admin. I couldn't tell you what the problem is there.
Much the same syntax as when passing anything, in this case a pointer is the norm:
int myFunction(char* anArrayOfChars) // a pointer to the array
// function code ...
// calling codechar anArray;
// fill the arrayintvalue = myFunction(anArray) // name of the array is a pointer to its content
will modifying the array content within the function make the edit permanent i.e. the modification will remain after the function ceased to exist. i.e. "myFunction(&anArray)" won`t this edit outside the function. I need the edit to work backwards.
Yes, if the function changes anything in the array then that data will remain when the function returns to the caller. Note: you do not need the addressof operator (&) on an array name. Just code it as I showed in my example.
Try this simple test:
Well, of course that breaks it so you may find that your code crashes. You must not overwrite arrays that are passed to you with more data than it can hold. But this conversation is missing some vital information. Maybe you can explain exactly what problem you are trying to solve.
This will prevent data overflows, and/or segfaults, when accessing myArray inside the function.
Things to note:
* we can get the compiler to tell us how many elements in the array using the sizeof(myArray)/sizeof(myArray) construct. This is calculated at compile time and in release mode, in most cases it will be optimized out, so it does not add to your memory usage, if that's a concern.
* Using the constant arrLen means that if we change the number of elements in myArray, we don't need to go through the code and find all uses of myArray and make sure we're passing in the right number
* If we had used arrLen = sizeof(myArray)/sizeof(int), we need to remember to change the definition of arrLen if we change the type of myArray. Using sizeof(myArray mean that if we change the type of myArray from int to double, for example, we don't need to remember to change the definition of arrLen as well