C / C++ / MFC

int Something0 = 0;
int Something1 = 1;
int ** Pointers = new int*[2];
Pointers[0] = &Something0;
*Pointers[0]++; //increase Something0 by 1
Pointers[1] = &Something1;
*Pointers[1]++; //increase Something1 by 1

//Could I do this 
**Pointers =10; //set Something0 to 10
  Pointers++;
**Pointers =30;  //set Something1 to 30

int i = 1;
int j = ++i;   // i is incremented before assignment: i = 2, j = 2;
int k = i++;   // i is incremented after assignment: i = 3, k = 2;
int x = ++i++; // UNDEFINED BEHAVIOR!!! Do not do this!!! 

int i = 2;
printf("%d %d\n", i++, ++);  // undefined order of evaluation 

k5054 wrote:

C++

int i = 2;
printf("%d %d\n", i++, ++);  // undefined order of evaluation

int i = 2;
printf("%d %d\n", i++, ++i);  // undefined order of evaluation

CalinNegru(fearless_) wrote:

It`s basically a simulation of execution without a binary file being involved

FILE *cmd = popen("hcitool dev 2>&1", "r");

char *buffer = NULL;
size_t len = 0;
ssize_t readlen;
while ( (readlen = getline(&buffer, len, cmd)) > 0)
{
   /* process input buffer */
}
free(buffer);
pclose(cmd);

FILE *cmd = popen("hcitool dev 2>/tmp/hcierrs", "r");
   /* process input as above */
FILE *cmd_errs = fopen("/tmp/hcierrs", "r");
   /* loop through input from cmd_errs ... */
unlink("/tmp/hcierrs");