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ya i thought some people may not have seen that who know it
so i posted again
"Men never do evil so completely and cheerfully as when they do it from religious conviction"
-Pascal
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I asked you one question but you dont answer to me
whitesky
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Problem
It is a tale of two friends, A and his colleague B working in a software company FIFO. Both of them have interest in coding and are pretty good at it. At times you cannot even differentiate who is better than the other. Their manager decided to use the Lines of Code (LoC) written by them to judge their smartness. He is going to appraise them on the basis of who has written more lines of code in that year.
In the beginning of the year, he gives A and B a set of modules for the year with his estimation of lines of code for each module. He asks both of them to divide the modules among themselves.
To divide the modules, B offered to split them using following system: they both take turns, each time choosing one module from either end of the set. He even generously offered A to make the first choice.
You need to write a C code to tell the total lines of code A will write compared to B if A chooses first. Of course we will assume that both A & B are brilliant, and since their appraisals depend on this, they will always choose in a way to try and end up with the maximum number of Lines of Code in their share.
The program must take input as the number of modules in the set given by the manager followed by the estimated lines of code for each of the module. The program should print how much more lines of code A will write than B. The value can be negative in case A writes less code than B. It should also print who gets the better grade in appraisal at the end of this year. In case both A and B gets same grade, print “NONE”.
Constraints
- Module set will contain between 1 and 50 elements inclusive.
- Each module will have lines of code between 1 and 10000 inclusive.
- Use standard scanf and printf as input and output methods. Please go through the test cases sample to understand the expected input and output. The input/output format in your program should be as given in the examples.
Test Cases Sample:
1. Input:
2
400 400
Output:
0
NONE
HINT: There are two modules in the set with LoC as 400 and 400. A starts first and chooses 400 and B chooses 400. Hence Answer is (400-400 = 0) and they both get the same grade.
2. Input:
3
200 700 400
Output:
-100
B
HINT: There are three modules in the set with LoC as 200 700 and 400. A chooses 400, followed by B choosing 700 and then A chooses 200.
3. Input:
4
1000 10000 900 50
Output:
8150
A
HINT: There are four modules in the set with LoC as 1000 10000 900 and 50. A chooses 50, B chooses 1000, then A chooses 10000 and then B chooses 900.
4. Input:
50
1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10
Output:
25
A
HINT: There are 50 modules in the set. Use your code to figure out how it works
Solve this and check u r talent in C.
Thanks in advance...
Ashok.
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Looks like homework, and a complicated one.
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ashok3450 wrote: Solve this and check u r talent in C.
First of all Check this[^].. Then have vote 1 from My side!...
Why don't you urself test your talent in C? ... rather testing Talents of people here.
I would be sounding rude to you? but that truth we(i.e. People here) don't help in Homeworks..
If you have some specific problem related it we can solve!
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
VC Forum Q&A :- I/ IV
Support CRY- Child Relief and You
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i have a picture control on a dialog i want to convert the points withr espect to dialog to with respect to picture control.
thank u in advance,
sree.
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If you have a CPoint value that contains coordinate relative to dialog, then you can try this in your dialog:
CPoint p = ...;
ClientToScreen(p);
m_cMyPicture.ScreenToClient(p);
Hope it helps.
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I am currently working on a project where I need to use a number of icons and store them in a datafile that also contains other data. I could use something like:
ICONINFO Info;
DWORD dwSize;
char Bits [5000];
char Mask [ 250];
if ( m_hIcon == (HICON)1
|| m_hIcon == NULL)
return ;
GetIconInfo (m_hIcon, &Info);
dwSize = GetBitmapBits (Info.hbmColor, 5000, Bits);
dwSize = GetBitmapBits (Info.hbmMask , 250, Mask);
I could get the icon back again by using the CreateIconIndirect routine, using the data that I extracted in the above way.
However, this results in 4096 bytes of colorbits and another 128 bytes of mask data, whereas the original .ico file is only 766 bytes! Does anyone have a better idea on how to extract the bits of the icon and put them back in another icon again?
Secondly, I would very much like to add a very simple icon editor to my program. Does anyone know of an open-source icon editor that I could include in my project?
Thanks in advance,
William
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Engberts wrote: Does anyone have a better idea on how to extract the bits of the icon and put them back in another icon again?
If you want to preserve the database space, I think you should compress the data.
If you work with source *.ico files, you can store the content of these files.
Otherwise, if you create icons dynamically, you can try to save your HICON objects to *.ico format. For this, you can try the CxImage library available at http://www.codeproject.com/bitmap/cximage.asp[^]. With this library, you can store the icon to a memory or disk file, and then store this content to database.
Alternatively, you can use a third-party compression procedure. For instance, you can try zlib library from http://www.zlib.net[^].
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consider a class
Class C
{
private:
int a;
int b;
};
then i write a copy constructor.
i believe copy constructor can be written in two wayz:
C& C::operator=(const C&);
void C::operator=(const C&);
In the former case, we deference by returning this* and the latter we dont return anything, so here is my question:
which one of the above is better??(in terms of efficiency)
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The efficiency of the two does not realy differ very much. Of course, the first way comes with some additional machine instructions. It mainly depends on what you want to do with your constructor.
William
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namaskaaram wrote: which one of the above is better??(in terms of efficiency)
I think first one is good to direct the reference correctly. As well we can give the gurantee of consistency in data.
Knock out 't' from can't,
You can if you think you can
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Actually "copy constructor" is this one: C(const C & );
Regarding overloading assignment operators, I think your first variant, which returns a reference, allows multiple assignments like this: a = b = c, or compact expressions like this: f(a = b). The second one does not allow this, but is little faster because of missing return value.
-- modified at 4:24 Tuesday 20th June, 2006
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actually i meant assignment operator overloading....sorry abt the typo! ;o)
thank u all!!!! 
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Viorel. wrote: The second one does not allow this, but is little faster because of missing return value.
You'll save 1, or maybe 2 CPU cycles. (Depending on how the compiler allocates registers, you may end up saving no cycles)
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in fact, prefer the following operator :
C& C::operator = (const C&);
the reason to prefer this one instead of the void operator is that the user of your class will then be able to cascade the assignment operations. consider this :
int i1, i2, i3;
C c1, c2, c3;
i1 = i2 = i3 = 5;
c1 = c2 = c3 = ;
this is possible only because the operator = returns a reference to the object it has just modified...
TOXCCT >>> GEII power
[VisualCalc 3.0 updated ][Flags Beginner's Guide new! ]
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Yes, you're right. The rationale is that the assignment operator should behave in the same way as assignment for primitive types.
Kevin
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namaskaaram wrote: i believe copy constructor can be written in two wayz:
That is not a copy constructor, it's an assignment operator.
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Hi,
lets say that i have an operation that is performed on two sets of data independently,
that is the data is separable, and not related.
so, for an example;
<br />
void Function1(int *a, int *b, int *c, int count)<br />
{<br />
for(int i=0; i< count; i++)<br />
c[i] = a[i] * b[i];<br />
}<br />
I can measure the execution time using QueryPerformanceCounter.
<br />
main()<br />
{<br />
Function1(a,b,c,count);<br />
<br />
OtherFunction(...);<br />
}
My question is, now, if i want to break the function to two threads, to take advantage
of dual cpu, or dual core, how do i
1- Measure the performance of the code..
2- Determine the function has finished, or terminated
Example of an implementation that i am looking at is;
void Function2(int *a, int *b, int *c, int count)<br />
{<br />
AfxBeginThread1()
AfxBeginThread2()
}
<br />
main()<br />
{<br />
Function2(a,b,c,count);<br />
<br />
<br />
<br />
OtherFunction(...);<br />
}
Can anyone help on this?
Thanks
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See Here[^] maybe it is some helpful to you
whitesky
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Hi,
nice link, there's some info on how to wait for a thread to finish, but how do i time the threads?
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Usman Ullah Sheikh wrote: // How do i block OtherFunction from executing before Function2 finishes.
Use criticalSection
<marquee scrollamount="1" scrolldelay="1" direction="up" height="10" step="1">--[![Jig | [Dance]](https://www.codeproject.com/script/Forums/Images/jig.gif) ]--
[My Current Status]
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Usman Ullah Sheikh wrote: // How to measure the time Function2 takes? Function2 is multithreaded.
// Time it takes for both thread to finish,
Why not you use global variables? and update it with the last process that finishes its task?
<br />
void Function2(int *a, int *b, int *c, int count)<br />
{<br />
AfxBeginThread1()
now, if the process is completed, inside the function that thread1 runs,
do your///QueryPerformanceCounter - end
AfxBeginThread2()// for data in the range of count/2 -> count
now, if the process is completed, inside the function that thread1 runs,
do your///QueryPerformanceCounter - end
}
while updating your "end" check if it has been updated by the previous process, if so, one process is already over so no need to worry, the last one you update is the resultant one. If the "end" counter is still 0, no process is yet over. So after updating it, you still need to wait. When the next process gets over it again checks if the "end" counter is 0 or not. This time it finds value inside it (since it's been updated by the previous thread) now you can be sure everything's over and 'end'- this 'start' this is the total time taken.
<marquee scrollamount="1" scrolldelay="1" direction="up" height="10" step="1">--[ ]--
[My Current Status]
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I think that will work! Thanks! I'll try it!
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Surely, the Dialog will close when the Enter and ESC key down.
I know reload the PreTranslateMessage(MSG* pMsg) function can avoid the problem.
In my project, there are some other controls in the dialog, and I want the Edit controls and buttons can get the Enter/ESC command but not close the Dialog, is there any way?
I tried the OnChar(), OnCommad(), there din't work at all.
BOOL CEditDlg::PreTranslateMessage(MSG* pMsg)
{
// TODO: Add your specialized code here and/or call the base class
if(pMsg->message==WM_KEYDOWN)
{
if(pMsg->wParam==VK_RETURN || pMsg->wParam==VK_ESCAPE)
{
if (!GetFocus()->IsKindOf(RUNTIME_CLASS(CEdit)))
return true;// pMsg->wParam=NULL ;
else
{
...............
}
}
}
return CDialog::PreTranslateMessage(pMsg);
}
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