LsaLogonUser() + MSV1_0_LM20_LOGON - C / C++ / MFC Discussion Boards

Re: sizeof char* array

Programm3r8-Jan-08 4:32

Programm3r

8-Jan-08 4:32

Thank you very much Smile | :)

The only programmers that are better that C programmers are those who code in 1's and 0's Green Alien | [Alien]

Programm3r
My Blog: ^_^

Re: sizeof char* array

David Crow8-Jan-08 4:56

David Crow

8-Jan-08 4:56

Programm3r wrote:
(if I may be so bold ...)

Why is asking a legitimate question considered being bold? Confused | :confused:

"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

Re: sizeof char* array

CPallini8-Jan-08 5:00

CPallini

8-Jan-08 5:00

I think he refers to the daunting design challenge of using STL.
Big Grin | :-D

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

[my articles]

Re: sizeof char* array

C^hris L^osinger8-Jan-08 4:02

C^hris L^osinger

8-Jan-08 4:02

in general, you can't. C/C++ doesn't keep track of array dimensions. at best, you can get the size of a 1D array like this:

#define _ARRAYSIZE(__a)        (sizeof(__a)/sizeof(__a[0]))
int array[5] = {0,1,2,3,4};
int s = _ARRAYSIZE(array);
... s = 5

but that only works if the array is declared in the same scope - it won't work if you just have a pointer to the array.

use the STL's collections.

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Re: sizeof char* array

Programm3r8-Jan-08 4:12

Programm3r

8-Jan-08 4:12

Thanks for the response Chris, I'll give it a try.

The only programmers that are better that C programmers are those who code in 1's and 0's Green Alien | [Alien]

Programm3r
My Blog: ^_^

Re: sizeof char* array

CPallini8-Jan-08 4:13

CPallini

8-Jan-08 4:13

Programm3r wrote:
A simple question, although I do not know the answer, but how can I get the size of a char* array.

Do you really need the size of the array or the number of its elements?
The compiler is, of course, answering correctly to your request: it returns 8 because your array contains two char * and each pointer size is 4 (on a 32-bit system).
If you want to know how many elements the array has, then use, as suggested
by Chris Losinger [^]

sizeof(array)/sizeof(array[0]);

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

[my articles]

Re: sizeof char* array

Programm3r8-Jan-08 4:18

Programm3r

8-Jan-08 4:18

Thanks for the response CPallini.

CPallini wrote:
Do you really need the size of the array or the number of its elements?

Yes, size of the array or the number of its elements.

CPallini wrote:
If you want to know how many elements the array has, then use, as suggested
by Chris Losinger [^]

Thanks

Regards,

The only programmers that are better that C programmers are those who code in 1's and 0's Green Alien | [Alien]

Programm3r
My Blog: ^_^

LsaLogonUser() + MSV1_0_LM20_LOGON

choupani8-Jan-08 3:49

choupani

8-Jan-08 3:49

I'm developing a firewall that authenticate users with ntlm against Active Directory.
My ntlm secnario is complete and work truly but my LsaLogonUser has problem.
When I pass NTLM Challenge,User Name,Lan Manager Response, NTLM Response,WorkStation Name, Domain Name to MSV1_0_LM20_LOGON structure and pass it to LsaLogonUser
function, LsaLogonUser return error,
Dose anybody have a sample or code that can help me?

My code is here:
UNICODE_STRING TempString;
UNICODE_STRING TempString2;
PMSV1_0_LM20_LOGON Auth;
PCHAR Auth1[40*5]; /* lots o' space */
PUCHAR Strings;

Auth = (PMSV1_0_LM20_LOGON) Auth1;
Strings = (PUCHAR)(Auth + 1);
Auth->MessageType = MsV1_0Lm20Logon;
RtlMoveMemory( Auth->ChallengeToClient,challenge,MSV1_0_CHALLENGE_LENGTH );
RtlInitUnicodeString( &TempString, L"Administrator" );
NlpPutString( &Auth->UserName, &TempString, &Strings );
RtlInitUnicodeString( &TempString, L"TOSHIBA" );
NlpPutString( &Auth->Workstation, &TempString, &Strings );
Auth->CaseSensitiveChallengeResponse.Length = 0;
Auth->CaseSensitiveChallengeResponse.MaximumLength = 0;
Auth->CaseSensitiveChallengeResponse.Buffer = NULL;
TempString2.Buffer = (PWSTR)lmPassword;
TempString2.Length = (USHORT)cbLmResp;
TempString2.MaximumLength = TempString2.Length;
if( TempString2.Length > 24 ) {
TempString2.Length = 24;
}
NlpPutString((PUNICODE_STRING)&Auth->CaseInsensitiveChallengeResponse,(PUNICODE_STRING)&TempString2,&Strings);
RtlInitUnicodeString( &TempString, L"KHARAZM.SERVER" );
NlpPutString( &Auth->LogonDomainName, &TempString, &Strings );
UNICODE_STRING OrgnName;
RtlInitUnicodeString( &OrgnName, L"TOSHIBA" );
ULONG ProfileBufferSize;
sysLog("Len=%d",Strings - (PUCHAR)Auth);

Status = LsaLogonUser(
gLsaHandle,
(PSTRING)&OrgnName,
Network,
gAuthPackageId,
// LATER? AuthenticationPackage | LSA_CALL_LICENSE_SERVER,
Auth,
Strings - (PUCHAR)Auth,
NULL,
&SourceContext,
(PVOID *)&pProfileBuffer,
&ProfileBufferSize,
&LogonLuid,
pLogonToken,
&Quotas,
&SubStatus );

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

Rajesh R Subramanian8-Jan-08 21:44

Rajesh R Subramanian

8-Jan-08 21:44

What is the error that LsaLogonUser() is returning?

Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
...formerly known as brahmma
Codeproject.com: Visual C++ MVP

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

choupani8-Jan-08 21:51

choupani

8-Jan-08 21:51

It's return -1073741715 means Invalid Username/Password.
My code is here:
//////////////////////////////////////////////////////////////////////////
UNICODE_STRING TempString;
UNICODE_STRING TempString2;
PMSV1_0_LM20_LOGON Auth;
PCHAR Auth1[40*5]; /* lots o' space */
PUCHAR Strings;

Auth = (PMSV1_0_LM20_LOGON) Auth1;
Strings = (PUCHAR)(Auth + 1);
Auth->MessageType = MsV1_0Lm20Logon;
RtlMoveMemory( Auth->ChallengeToClient,challenge,MSV1_0_CHALLENGE_LENGTH );
RtlInitUnicodeString( &TempString, L"Administrator" );
NlpPutString( &Auth->UserName, &TempString, &Strings );
RtlInitUnicodeString( &TempString, L"TOSHIBA" );
NlpPutString( &Auth->Workstation, &TempString, &Strings );
Auth->CaseSensitiveChallengeResponse.Length = 0;
Auth->CaseSensitiveChallengeResponse.MaximumLength = 0;
Auth->CaseSensitiveChallengeResponse.Buffer = NULL;
TempString2.Buffer = (PWSTR)lmPassword;
TempString2.Length = (USHORT)cbLmResp;
TempString2.MaximumLength = TempString2.Length;
if( TempString2.Length > 24 ) {
TempString2.Length = 24;
}
NlpPutString((PUNICODE_STRING)&Auth->CaseInsensitiveChallengeResponse,(PUNICODE_STRING)&TempString2,&Strings);

RtlInitUnicodeString( &TempString, L"KHARAZM.SERVER" );
NlpPutString( &Auth->LogonDomainName, &TempString, &Strings );
UNICODE_STRING OrgnName;
RtlInitUnicodeString( &OrgnName, L"TOSHIBA" );
ULONG ProfileBufferSize;
sysLog("Len=%d",Strings - (PUCHAR)Auth);

Status = LsaLogonUser(
gLsaHandle,
(PSTRING)&OrgnName,
Network,
gAuthPackageId,
// LATER? AuthenticationPackage | LSA_CALL_LICENSE_SERVER,
Auth,
Strings - (PUCHAR)Auth,
NULL,
&SourceContext,
(PVOID *)&pProfileBuffer,
&ProfileBufferSize,
&LogonLuid,
pLogonToken,
&Quotas,
&SubStatus );
//////////////////////////////////////////////////////////////////////////

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

Rajesh R Subramanian8-Jan-08 22:02

Rajesh R Subramanian

8-Jan-08 22:02

Member 405269 wrote:
means Invalid Username/Password.

So, isn't that error message clear enough?

On an additional note:
Please don't post code unless you're asked to. And instead of copy pasting the entire function, post the code that is relevant to the problem. I suggest that while posting code, please enclose it within the <pre> </pre> tags.

Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
...formerly known as brahmma
Codeproject.com: Visual C++ MVP

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

choupani8-Jan-08 22:10

choupani

8-Jan-08 22:10

Do you have a link or sample code that work truly?
However do you know another way to authenticate users with ntlm hash password?

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

Rajesh R Subramanian8-Jan-08 22:15

Rajesh R Subramanian

8-Jan-08 22:15

Here is a link that might help you: LsaLogonUser - The function from hell[^]

Also, check if the function LogonUser() would help you.

Nobody can give you wiser advice than yourself. - Cicero
.·´¯`·->Rajesh<-·´¯`·.
...formerly known as brahmma
Codeproject.com: Visual C++ MVP

Re: LsaLogonUser() + MSV1_0_LM20_LOGON

choupani8-Jan-08 22:31

choupani

8-Jan-08 22:31

But LogonUser() only accept clear text password.

Working with dynamically created dialog

narayanagvs8-Jan-08 1:56

narayanagvs

8-Jan-08 1:56

Hi,

In a com component ,I took a dialog resource added a class
for it and even inserted an Activex Control on dialog
(with activex variable m_ctrlHMFAx).

I am creating the dialog dynamically as shown below

//pDialog initialized to NULL in the constructor of CMyWnd class
   pDialog = new CMyDialog();
   //Check if new succeeded and we got a valid pointer to a dialog object
   if(pDialog != NULL)
   {
      BOOL ret = pDialog->Create(IDD_MYDIALOG,this);
      if(!ret)   //Create failed.
         AfxMessageBox("Error creating Dialog");
      pDialog->ShowWindow(SW_SHOW);
   }

Now as my dialog is created I am trying to work with my
ActiveX variable as pDialog->m_ctrlHMFAx.AddItem(); but
it throws an assertion

when I debug I recognized that m_ctrlHMFAx is showing NULL
value.I tried creating the activex control dynamically in
OnInitdialog but no use.

I also placed AfxEnableControlContainer() in initinstance.
What could be the reason ? Any suggestions would be helpful.

Thanks
Satya

Today is a gift, that's why it is called the present.

Re: Working with dynamically created dialog

CPallini8-Jan-08 2:16

CPallini

8-Jan-08 2:16

narayanagvs wrote:
I tried creating the activex control dynamically in
OnInitdialog but no use.

Usually you can have a quit amount of info (from HRESULT return value) whenever a step of such a operation fails.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

[my articles]

Re: Working with dynamically created dialog

David Crow8-Jan-08 3:13

David Crow

8-Jan-08 3:13

narayanagvs wrote:
BOOL ret = pDialog->Create(IDD_MYDIALOG,this);
if(!ret) //Create failed.
AfxMessageBox("Error creating Dialog");
pDialog->ShowWindow(SW_SHOW);

If Create() fails, why proceed with calling ShowWindow()?

Re: Working with dynamically created dialog

Hamid_RT8-Jan-08 18:14

Hamid_RT

8-Jan-08 18:14

narayanagvs wrote:

BOOL ret = pDialog->Create(IDD_MYDIALOG,this);
if(!ret) //Create failed.
AfxMessageBox("Error creating Dialog");
pDialog->ShowWindow(SW_SHOW);

You must use of

if(!ret)   //Create failed.  
AfxMessageBox("Error creating Dialog");  
else  
pDialog->ShowWindow(SW_SHOW);

unexpected exception handler

George_George8-Jan-08 1:46

George_George

8-Jan-08 1:46

Hello everyone,

This question is about when it is allowed to call throw to re-throw exception -- make the exception re-throw.

I can only think of two situations,

1. in catch block of an exception;
2. in unexpected handler.

For (2), in unexpected handler, since the input parameter is null, so in order to get the exception information, we need to re-throw it and catch it to get exception informaiton.

Is my understanding correct? Here is some pseudo code from Bjarne's book.

// suppose throwY is unexpcted handler
void throwY() throw (Yunexpected)
{
    try{
        throw; // have to re-throw and catch in order to get exception information since current input parameter is null and has no exception information, my understanding correct?
    } catch (Network_exception& p)
    {
        throw (Yunexpected (&p));
    } catch (...)
    {
        throw (Yunexpected (0));
    }
}

thanks in advance,
George

Re: unexpected exception handler

Matthew Faithfull8-Jan-08 7:27

Matthew Faithfull

8-Jan-08 7:27

Yes, and they're really the same as the unexpected handler is just like an ultimate catch block for when all others have failed to catch. If you want to understand how this works in the real world, as opposed to how Bjarne says it should work, then take a look at the source code for the C Runtime that ships with Visual Studio. C++ exception handling in the MS world relies on both the runtime and special code injected into your functions by the Compiler. There's also a good article on here somewhere called something like How C++ Exception Handling Really Works. Enjoy Smile | :)

Nothing is exactly what it seems but everything with seems can be unpicked.

Re: unexpected exception handler

George_George8-Jan-08 16:29

George_George

8-Jan-08 16:29

Hi Matthew,

I can not find the article you mentioned "How C++ Exception Handling Really Works" from Google. Could you provide a link please?

regards,
George

Re: unexpected exception handler

Matthew Faithfull8-Jan-08 21:50

Matthew Faithfull

8-Jan-08 21:50

My mistake George the title is somewhat different. This[^] is the one I'd seen a link to. It comes up every now and then in the list of related popular articles at the bottom of one page or another on CP. If you soak up all that you'll know more about exception handling than I do so you can answer the next query that comes up in that area Smile | :)

Nothing is exactly what it seems but everything with seems can be unpicked.

Re: unexpected exception handler

George_George9-Jan-08 2:29

George_George

9-Jan-08 2:29

Thanks Matthew,

Great article! About my original question, do you agree? Smile | :)

--------------------
For (2), in unexpected handler, since the input parameter is null, so in order to get the exception information, we need to re-throw it and catch it to get exception informaiton.

Is my understanding correct?
--------------------

regards,
George

using swap to make assignment operator exception safe

George_George8-Jan-08 1:14

George_George

8-Jan-08 1:14

Hello everyone,

The following swap technique is used to make assignment operator exception safe (means even if there is exception, the current object instance's state is invariant).

It used a temporary object "temp" in this sample, and assignment is made on a to temp ar first. Even if there is exception, the current this object's state is not corrupted.

My question is, the pattern works only if there is no exception thrown by swap function. If there are exception in swap function, the state of current object instance may still be corrupted (swap may invoke the assignment operator of member variables). Is my understanding correct?

class A;
A& A::operator= (const A& a)
{
    A temp;
    temp = a; // exception may be thrown
    swap (*this, temp);
    return *this;
}

thanks in advance,
George

Re: using swap to make assignment operator exception safe

CPallini8-Jan-08 2:03

CPallini

8-Jan-08 2:03

Hey George, wait a moment, throw out your book, that's recursive junk!!!!!!!!!!!

Big Grin | :-D

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

[my articles]

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