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Questionupdate xml file Pin
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QuestionopenFileDialog win form Pin
arkiboys28-Jul-08 0:59
Memberarkiboys28-Jul-08 0:59 
Hello,
The following code shows how to use the openFileDialog to read the contents of a .csv file into a textbox.

Question:
After selecting the file iin the dialog, how do I actually open the file?
remember that I would like to open the .csv file and NOT read it into the textbox.

StreamReader ts = null;

openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
openFileDialog1.DefaultExt = "csv";

openFileDialog1.Filter = "Text files (*.csv)|*.csv|" + "All files|*.*";
openFileDialog1.Multiselect = false;
openFileDialog1.FilterIndex = 2;
openFileDialog1.ValidateNames = true;

if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
ts = new StreamReader(openFileDialog1.OpenFile());

txtSQL.Text = ts.ReadToEnd();
}
}

Thanks
AnswerRe: openFileDialog win form Pin
stancrm28-Jul-08 1:05
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GeneralRe: openFileDialog win form Pin
arkiboys28-Jul-08 1:58
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GeneralRe: openFileDialog win form Pin
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GeneralRe: openFileDialog win form Pin
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