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QuestionA quick question about volatile Pin
Megidolaon30-Jul-08 23:27
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Fields that are declared volatile are not subject to compiler optimizations that assume access by a single thread
This is from the VS help about the volatile keyword in C#.

Does that mean normal variables are cached and to optimize speed, the cached value is used unless the variable is changed in the current thread?

And volatile means, that no cached values are used but before every operation, the value of the variable is read again?

Then, the concept of a a volatile variable is that the value a Thread reads from it is always up to date and now possibly outdated like a normal variable?

BUT, what about larger variables, like long or even objects?
Wouldn't it still be possible that while one thread reads the first byte of a long, another thread writes the second byte?
So, the first thread would still have an outdated value of the variable?

Thanks.
AnswerRe: A quick question about volatile Pin
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