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You are very stupid, aren't you ?
You asked three times in the C# forum, did you want C# or VB code ? Why do you even want to do this ?
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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Welcome in the CP's Memorable Quotes page. ([^] the link is indirect, since the PermaLink on the message is broken, sorry...).
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Multithreading, no idea. I do know how to copy files from one folder to another, just take a look at System.IO. I won't explain exactly how to, that will be a nice (though a simple) challenge 
Greets,
Zaegra
Motivation is the key to software development.
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ok here is my code for loading the file
Imports System.Xml.XPath
Imports System.Xml.Linq
Imports System
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim xmldoc As XDocument = XDocument.Load("OpenFileDialog1.FileName")
Dim
OpenFileDialog1.Filter = "Xml (*.xml)|*.xml"
OpenFileDialog1.ShowDialog()
System.Xml.Linq.XDocument.Load(OpenFileDialog1.FileName)
End Sub
End Class
How do i load node text into text box from here
a simple xml file for testing here person.xml
<xml version="1.0" encoding="utf=8">
<person>
<fname>Keith</fname>
<lname>Ryan</lname>
</person>
thanks
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here is the xml
<xml version="1.0" encoding="utf=8">
<person>
<fname>Keith
<lname>Ryan
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<xml version="1.0" encoding= "utf=8"?>
<Person>
<FName>Keith</FName>
<LName>Ryan</LName>
</Person>
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Try the following
Dim doc as New xml.xmldocument
doc.Load(Filename)
Dim MainNode as xml.xmlnode = doc.ChildNodes(1)
For Each NameNode As Xml.Xmlnode In MainNode.ChildNodes
Dim Name as String = NameNode.InnerText
TextBox1.Text = Textbox1.Text & vbCrLf & Name
Next
Just replace the names of the controls, that's pretty obvious.
Note: You might have to delete the first enter (vbCrLf) in your textbox. (Why? Take a good look at the code :P)
Hope this helped you out,
Zaegra
Motivation is the key to software development.
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here is what i have. childnodes not seen by system.xml.linq.xdocument is there another import i need to do for this or refrence i am refrenceing microsoft xml 6.0. What do you mean replace name of controls i am really new to programming
OpenFileDialog1.Filter = "Xml (*.xml)|*.xml"
OpenFileDialog1.ShowDialog()
Dim filename = OpenFileDialog1.FileName
Dim xmldoc As XmlDocument
xmldoc.Load(filename)
Dim MainNode As Xml.XmlNode = xmldoc.ChildNodes(1)
For Each NameNode As Xml.XmlNode In MainNode.ChildNodes
Dim Name As String = NameNode.InnerText
TextBox1.Text = TextBox1.Text & vbCrLf & Name
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Well, why do you need an XDocument in the chain ? Why not just use File.ReadAllText ?
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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i think i need xdocument not sure i am new to programming because the file i am loading into memory is an xml file i need the information from each node to fill different text boxes. File.readalltext is for text files only correct?
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Hi,
you will get more help around here by posting your problem here, in English, and with a relevant subject line.
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mo1om1 wrote: plz follow this link
Uhm..... no
Why is common sense not common?
Never argue with an idiot. They will drag you down to their level where they are an expert.
Sometimes it takes a lot of work to be lazy
Individuality is fine, as long as we do it together - F. Burns
Help humanity, join the CodeProject grid computing team here
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It's depressing just how absolutely moronic these boards are becoming.
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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I know!! I didn't get an MS MVP this time around. I've spent too much time with the munchkin in the last year and frankly, with all the idiots running around lately, it's impossible to get an intelligent question to answer.
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They are cutting back in general. I got cut for not liking Vista, over a year ago now. Screw them if they can't take a joke.
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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Nice one 
Motivation is the key to software development.
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Then why do you read them?
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mo1om1 wrote: plz follow this link
Please follow this link [^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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For those wondering what the message said, Google Translate has the English version.
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Yeah, that made everything sooooo much more clear!
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OK guys....
I have two hex bytes which I want to convert into a decimal number. Lets say, for instance, 3A2D, or 14893.
Here's what I am doing:
Dim msg As Byte() = New Byte(2) {}
msg(0) = &H3A
msg(1) = &H2D
MsgBox(BitConverter.ToUInt16(msg, 0))
Why does VB give me a completely different number (11578)? What's the correct way to accomplish this?
Thanks,
Dan
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Both values are correct, it all depends where in your opinion the "most significant byte" is.
Intel has chosen to apply "little-endian" byte ordering in all its hardware, hence when they store the decimal value 258 (hex 0x0102) they put 0x02 at the lower address and 0x01 at the higher address.
Others, such as Motorola/FreeScale use "big-endian" byte ordering.
Systems need to be consistent in the ordering they apply.
Communicating between systems is even harder: imagine exchanging files, or sending network packets.
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Thank you! Pretty confusing, but that solves it!
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