XML / XSL

Import a C# textbox value into a XSLT to generate a .aspx page

27-Aug-09 22:23

I suspect CDATA sections[^] will be useful for this.

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Arokiamary27-Aug-09 17:22

Re: Import a C# textbox value into a XSLT to generate a .aspx page

27-Aug-09 17:22

Hi All,
We have a C# windows application which will transform the xml and xslt we give into a .aspx page. The user has to specify the XML and the .aspx file name , we have a standard XSLT which will use the xml and create the file with the name specified by the user. The problem we face is in the .aspx page we want to write the Page attribute E.g. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" >; where we include the .aspx.cs file name , but this value comes from the C# code , how can we import the textbox value from C# code into our standard XSLT to write the page attribute in our to be generated .aspx page. Please Advice.TIA

Regards,
Nancy

Stuart Dootson27-Aug-09 22:22

Reference a node or an element in one .xml file in another

27-Aug-09 22:22

Add a parameter at the top level of the XSLT file:

<xsl:stylesheet version="2.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                exclude-result-prefixes="xsl">

  <!-- Allow the user to specify the .cs filename -->
  <xsl:param name="CSFilename"/>

<!-- The rest of your XSLT - use $CSFilename to access the .cs filename -->
</xsl:stylesheet>

You then use the XsltArgumentList[^] class to add the parameter values when you perform the transform.

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XML in Word 2007

Idle_Force25-Aug-09 18:07

Idle_Force

25-Aug-09 18:07

If you can add an XSD schema to a .docx and add the elements to the doc itself, then how do you send data to this? Can you use word automation via VB.Net 2008?

Arokiamary24-Aug-09 16:58

Re: Reference a node or an element in one .xml file in another

24-Aug-09 16:58

Hi All,

We have two .xml files, one has the details about categories and in the other .xml file we need to reference the categories. When we searched in net we found that we need to declare the categories as entities in the DTD file and use them in the xml, but we want to take the categories from the xml file only. Kindly advice. TIA

Regards,
Nancy

Stuart Dootson24-Aug-09 23:38

Re: Reference a node or an element in one .xml file in another

24-Aug-09 23:38

You could use XInclude to logically include the 'categories' XML file in the file that needs to reference the categories?

A question - when do the category usages need to be resolved to the original categories? What processing step *NEEDS* the link between category use and category definition to be available?

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Arokiamary25-Aug-09 0:51

Re: Reference a node or an element in one .xml file in another

25-Aug-09 0:51

Thanks for your help.
In brief we have an xml file (kind of Master XML) which has all categories and Values for Each category Eg. Technology, Department will be categories, Technology will hold values like Technology_id and Technology_name, same for department.

We have another XML(Pagewise) which describes about what controls should be in each page. E.g. Listbox, Button , Radio button. The XSLT file will use the Pagewise XML to get details about the controls and the master xml to get the details about the values to be stored in controls like Listbox.

We are actually trying to create dynamic .aspx pages using XML and XSLT.

Regards,
Nancy

Stuart Dootson25-Aug-09 2:04

Re: Reference a node or an element in one .xml file in another

25-Aug-09 2:04

If you're using xslt, then there's always the document function[^] that allows you to read in a separate XML document.

Alternatively, the XInclude[^] suggestion will work with XSLT, provided your XSLT processor has support.

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Arokiamary25-Aug-09 19:03

How to load xml file in mozillla

25-Aug-09 19:03

Thanks a lot for your help Smile | :)

Regards,
Nancy

biswa4724-Aug-09 3:55

biswa47

24-Aug-09 3:55

Hi dear friends,

from last few days i am digging my head like anything for loading rss feed(its nothing but a xml file) in to mozilla browser.

i am succesfully load that and displayed in IE but unable to load it in mozzlia.here the link for rss feed is-"http://www.ed.gov/rss/edgov.xml".
here i am able to dtect the browser but unable to load it in mozilla

plz help me out.

<br />
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><br />
<html xmlns="http://www.w3.org/1999/xhtml" ><br />
<head><br />
    <title>Untitled Page</title><br />
    <script type="text/javascript"><br />
 if(navigator.appName == "Netscape")<br />
    {<br />
     alert("You're using a Netscape browser.")<br />
      function loadXML()<br />
            {<br />
            <br />
             var xmlDoc = document.implementation.createDocument("", "", null) <br />
             xmlDoc.load("http://www.ed.gov/rss/edgov.xml");<br />
             xmlDoc.onload = readXML;<br />
             <br />
              alert("hi")<br />
                document.getElementById("title").innerHTML= xmlDoc.getElementsByTagName("title")[2].firstChild.nodeValue<br />
                document.getElementById("description").innerHTML=   xmlDoc.getElementsByTagName("description")[2].firstChild.nodeValue<br />
                <br />
                document.getElementById("title1").innerHTML= xmlDoc.getElementsByTagName("title")[3].firstChild.nodeValue<br />
                document.getElementById("description1").innerHTML=   xmlDoc.getElementsByTagName("description")[3].firstChild.nodeValue<br />
                <br />
                document.getElementById("title2").innerHTML= xmlDoc.getElementsByTagName("title")[4].firstChild.nodeValue<br />
                document.getElementById("description2").innerHTML=   xmlDoc.getElementsByTagName("description")[4].firstChild.nodeValue<br />
                <br />
                document.getElementById("title3").innerHTML= xmlDoc.getElementsByTagName("title")[4].firstChild.nodeValue<br />
                document.getElementById("description3").innerHTML=   xmlDoc.getElementsByTagName("description")[4].firstChild.nodeValue<br />
                <br />
                document.getElementById("title4").innerHTML= xmlDoc.getElementsByTagName("title")[5].firstChild.nodeValue<br />
                document.getElementById("description4").innerHTML=   xmlDoc.getElementsByTagName("description")[5].firstChild.nodeValue<br />
                <br />
                document.getElementById("title5").innerHTML= xmlDoc.getElementsByTagName("title")[6].firstChild.nodeValue<br />
                document.getElementById("description5").innerHTML=   xmlDoc.getElementsByTagName("description")[6].firstChild.nodeValue<br />
              <br />
              <br />
            }<br />
            <br />
            	<br />
                <br />
        <br />
    }<br />
     if(navigator.appName == "Microsoft Internet Explorer")<br />
    {<br />
        var xmlDoc<br />
        function loadXML()<br />
            {<br />
            if (window.ActiveXObject)<br />
              {<br />
              xmlDoc = new ActiveXObject("Microsoft.XMLDOM");<br />
              xmlDoc.async=false;<br />
              xmlDoc.load("http://www.ed.gov/rss/edgov.xml");<br />
              xmlObj=xmlDoc.documentElement; <br />
<br />
              if (xmlDoc.readyState != 4) <br />
                 { <br />
                   return false; <br />
                 } <br />
            	<br />
                document.getElementById("title").innerHTML= xmlDoc.getElementsByTagName("title")[2].firstChild.nodeValue<br />
                document.getElementById("description").innerHTML=   xmlDoc.getElementsByTagName("description")[2].firstChild.nodeValue<br />
                <br />
                document.getElementById("title1").innerHTML= xmlDoc.getElementsByTagName("title")[3].firstChild.nodeValue<br />
                document.getElementById("description1").innerHTML=   xmlDoc.getElementsByTagName("description")[3].firstChild.nodeValue<br />
                <br />
                document.getElementById("title2").innerHTML= xmlDoc.getElementsByTagName("title")[4].firstChild.nodeValue<br />
                document.getElementById("description2").innerHTML=   xmlDoc.getElementsByTagName("description")[4].firstChild.nodeValue<br />
                <br />
                document.getElementById("title3").innerHTML= xmlDoc.getElementsByTagName("title")[4].firstChild.nodeValue<br />
                document.getElementById("description3").innerHTML=   xmlDoc.getElementsByTagName("description")[4].firstChild.nodeValue<br />
                <br />
                document.getElementById("title4").innerHTML= xmlDoc.getElementsByTagName("title")[5].firstChild.nodeValue<br />
                document.getElementById("description4").innerHTML=   xmlDoc.getElementsByTagName("description")[5].firstChild.nodeValue<br />
                <br />
                document.getElementById("title5").innerHTML= xmlDoc.getElementsByTagName("title")[6].firstChild.nodeValue<br />
                document.getElementById("description5").innerHTML=   xmlDoc.getElementsByTagName("description")[6].firstChild.nodeValue<br />
        <br />
              }<br />
            }<br />
            <br />
        <br />
      }<br />
</script><br />
</head><br />
<body onload="loadXML()"><br />
<table width="100%" ><br />
    <tr><br />
        <td ><br />
        <marquee  onmouseover="if(this.stop)this.stop()" onmouseout="if(this.start)this.start()"><br />
        <label id="title"> </label> - <label id="description"></label>;<br />
        <label id="title1"></label> - <label id="description1"></label>; <br />
        <label id="title2"></label> - <label id="description2"></label>; <br />
        <label id="title3"></label> - <label id="description3"></label>;<br />
        <label id="title4"></label> - <label id="description4"></label>;<br />
        <label id="title5"></label> - <label id="description5"></label>;<br />
         </marquee><br />
     </td><br />
    </tr><br />
</table><br />
</body><br />
</html><br />
<br />

Stuart Dootson24-Aug-09 23:33

24-Aug-09 23:33

Strange - I can load the URL (http://www.ed.gov/rss/edgov.xml) directly into FireFox, but using your code, I get this error in the Firebug console: Access to restricted URI denied" code: "1012

An aside - if you're using Firefox (and as you're using Mozilla, seems highly likely), use Firebug to help you debug your Javascript - it's an awesome tool!

In addition, I would also recommend using a Javascript library like jQuery or Prototype (I have experience of jQuery, but not Prototype) for cross-browser DOM manipulation like this - they allow you to a) write your code as if there was only one browser - the library will deal with the browser differences, and b) simplify your code significantly.

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p

biswa4724-Aug-09 23:50

biswa47

24-Aug-09 23:50

HI,
Stuart Dootson.

Will you kindly give me ur code in which u have successfully loaded the xml file in to mozilla

Stuart Dootson24-Aug-09 23:52

24-Aug-09 23:52

No code - I typed the URL into the address bar...

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p