Java

Richard MacCutchan14-Feb-14 0:47

14-Feb-14 0:47

Well the numbers (3,2,4) don't seem to match your pattern anywhere so it is difficult to see the connection between the two. However, in order to print patterns of stars you print rows first. So it is just a matter of using the counts to decide how many to print on each row. If you try figuring out how you would do it using pen and paper, then coverting that to code should be quite easy.

Veni, vidi, abiit domum

V$ethi15-Feb-14 5:01

V$ethi

15-Feb-14 5:01

opp!!! that was my typing mistake first i want to print the 3 stars then 2 and then 4 means basically depending upon the oder of input given by user ..

Richard MacCutchan15-Feb-14 6:03

15-Feb-14 6:03

So what is the problem? Just use each number to create a loop and print that number of stars.

Veni, vidi, abiit domum

V$ethi15-Feb-14 16:25

V$ethi

15-Feb-14 16:25

i have to print the stars in vertical manner mean first three stars vertical line then 4 stars vertical line and so on basically like the tower of asterisks . the problem is that after printing a line how can i take back control to the top to print another asterisks tower ??

Richard MacCutchan15-Feb-14 21:11

15-Feb-14 21:11

You need to save these numbers in an array which you then use to calculate how many stars to print across each line. It's just a question of a bit of logic and mathematics.

Veni, vidi, abiit domum

chronodekar17-Feb-14 21:18

chronodekar

17-Feb-14 21:18

Try changing your approach to the problem. Let's try this.
Input : 2, 4, 3
Desired output:

*
**
***
***

For graphical purposes let me remake the output as follows

*OO
**O
***
***

Replace the "O" with spaces. Does it help?

-chronodekar

Richard MacCutchan17-Feb-14 21:30

17-Feb-14 21:30

How exactly does that help?

chronodekar18-Feb-14 3:40

chronodekar

18-Feb-14 3:40

There might be a more efficient way of doing it, but here's my thinking.

1. Arrange all the numbers in descending order. Make note of the largest one ( = A). Also store the numbers in an array ( = ARRAY)
2. Count the number of inputs ( = B).
3. Visualize the output in the form of a rectangle - you need to draw (with ASCII) a rectangle whose height is A and width B. Alternatively, you need to print A no. of lines with B characters.

Now we come to implementation. In pseudo-code;

Java

for (i = A ; i>0; i--) 
{
    for (j = 0; j<B; j++)
    {
        if (ARRAY(j) > i)
            print("*");
        else
            print("O");
    }
    print("\n");    
}

I think that should do it. Any edge case I missed?

-chronodekar

jschell14-Feb-14 10:30

14-Feb-14 10:30

If I understand you post your 'algorithm' is incorrect.
You do not print vertically - Instead you print horizontally.

Hopefully you have already learned about loops and arrays. So
1. Put the values in an array
2. Write a method that finds the maximum value in the array. When if finds it set the array location to -1 (this is how you 'remove' it.)
3. Write a method that takes a X value and prints that many stars.
4. Put 2 and 3 together to print all the rows.
5. Think about how you know it will end (the '-1' is a hint.)

How to encrypt old data instead of using jasyptHibernateEncryptorin

V$ethi15-Feb-14 5:07

V$ethi

15-Feb-14 5:07

yeah i have read about loops and array.i can also find the max among all the elements of an array but what are you saying about location and all couldn't understand... Cry | :((

Member 1058731510-Feb-14 21:50

Member 10587315

10-Feb-14 21:50

Java

Hi
This is suman.
we are using spring with Hibernate in to my application,but we want to implenting jasyptHibernateEncryptorin in to my application.

its working fine when storing a new entry into database table and fetching the same entry,
but problem here its how to encrypt my old data.

can you please any one help me , ASAP

System timezone

Hans Ruck9-Feb-14 22:06

Hans Ruck

9-Feb-14 22:06

Hi,

Is there any way to read the current time zone of the operating system? I need to check it to see if it has been updated.
I have to do this every minute, without restarting the application and without launching an external process.

Thank you very much for your attention.

Richard MacCutchan9-Feb-14 22:47

9-Feb-14 22:47

Try the following:

Java

TimeZone tz = Calendar.getInstance().getTimeZone();  
System.out.println(tz.getDisplayName());
System.out.println(tz.getID());

Note that an application can set its own time zone, independently of the system.

Veni, vidi, abiit domum

Hans Ruck9-Feb-14 23:20

Hans Ruck

9-Feb-14 23:20

Thank you Richard. But try this and you will see what I mean:

Java

TimeZone tz = Calendar.getInstance().getTimeZone();  
System.out.println(tz.getDisplayName());
System.out.println(tz.getID());

tz = Calendar.getInstance().getTimeZone();   // breakpoint here, stop, change the system time zone and then continue running
System.out.println(tz.getDisplayName());
System.out.println(tz.getID());

The time zone is set at the beginning of the current JVM process. It is subsequently detached from the system time zone and it sadly seems that there is no orthodox way to reattach it...

Bogdan Rechi.

Richard MacCutchan10-Feb-14 0:06

10-Feb-14 0:06

The timezone setting is part of the environment of every process and is set at the time the process is started. I cannot see any way to tell when it changes apart from some system process that can hook into the operating system in some way. Sorry.

Veni, vidi, abiit domum

jschell10-Feb-14 8:18

10-Feb-14 8:18

From the other responses....

Windows has the following command line utility

tzutil.exe

It has an option '/g' which returns the current timezone.

You use java.lang.Process to run it and collect the results.

Bernhard Hiller10-Feb-14 21:34

Bernhard Hiller

10-Feb-14 21:34

Just note that a process inherits the environment from its parent process - and when the time zone is part of the environment, then tzutil will report the time zone of the application it was started from, which may be different from the time zone of the system.

jschell11-Feb-14 11:10

11-Feb-14 11:10

Bernhard Hiller wrote:
Just note that a process inherits the environment from its parent process

I just tried the following
- Open a console window
- Run tzutil to report current TZ
- Leave console window running.
- Change the TZ using the tray applet
- In the same console window above use tzutil again
- It reports the new TZ.

The documentation also states that tzutil updates the TZ in the registry. Which wouldn't be an environment update. So that suggests that in terms of reporting it would report from the same source and not from the environment.

Bernhard Hiller11-Feb-14 20:14

Bernhard Hiller

11-Feb-14 20:14

Thanks for that information.

Richard MacCutchan11-Feb-14 21:56

11-Feb-14 21:56

Unfortunately that only works for a new execution of a program, e.g. tzutil. I just tried it with a running Java application, and the app did not see the change of timezone.

Veni, vidi, abiit domum

jschell12-Feb-14 9:16

12-Feb-14 9:16

Not exactly sure what you mean.

My suggestion was that one needs to run tzutil from the java application via Process. One would need to run it each time one wanted an update.

You tried that and it didn't work?

Richard MacCutchan13-Feb-14 2:53

Java Code for Filling in Random Radio Buttons

13-Feb-14 2:53

jschell wrote:
My suggestion was that one needs to run tzutil from the java application via Process.

And it works as you described. Thumbs Up | :thumbsup:

Veni, vidi, abiit domum

Romahn Graham6-Feb-14 4:08

Romahn Graham

6-Feb-14 4:08

Hi, I have a code that just won't work and I can't figure out why.
It's supposed to go to a survey page and fill in radio buttons randomly. For instance a survey with 100 questions, 6 per question. It fills in one question. For some reason my Aunt really needs this? Any thought?

JavaScript

// randomizer
 
function randomFromTo(from, to) {
    return Math.floor(Math.random() * to) + from;
}

function autoFill() {
var radioList = [];

for (var i = 0; i < document.forms.length; i++) {
        for (j = 0; j < document.forms[i].length; j++) {
            if (document.forms[i].elements[j].type == "radio") {
	if(typeof radioList[document.forms[i].elements[j].name.substring(0, 10)] == 'undefined') {
                radioList[document.forms[i].elements[j].name.substring(0, 10)] = [];
        }
	radioList[document.forms[i].elements[j].name.substring(0, 10)].push(document.forms[i].elements[j].id);
        }
    }
}
for (var radio in radioList) {
var rand = randomFromTo(0, radioList[radio].length-1);
document.getElementById(radioList[radio][rand]).checked = true;
}
}
 
window.onload = function(){ 
autoFill();
};

Re: Java Code for Filling in Random Radio Buttons

Richard MacCutchan6-Feb-14 6:20