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Richard MacCutchan31-May-17 23:32
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QuestionXSLT passing a variable to starts-with Pin
bjmallon13-Feb-17 15:03
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AnswerRe: XSLT passing a variable to starts-with Pin
Richard Deeming14-Feb-17 3:32
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GeneralRe: XSLT passing a variable to starts-with Pin
bjmallon16-Feb-17 19:45
Memberbjmallon16-Feb-17 19:45 
Richard,

Thanks for your reply.

Yes, if I pass 'A' to the template, I get the correct answer. So that's a good thing.

Now, given a tokenised string stored in a variable (Letters):

<xsl:variable name="Letters">
    <xsl:call-template name="tokenise">
        <xsl:with-param name="string" select ="'A B C D E F G H I J K L M N O P Q R S T U V W X Y Z'"/>
        <xsl:with-param name="delimeters" select="' '"/>
    </xsl:call-template>
</xsl:variable>

And trying to process each token through the template:
<xsl:for-each select="msxsl:node-set($Letters)/token">
  <xsl:variable name="currToken">
    <xsl:value-of select="./node()[1]"/>
  </xsl:variable>
  <xsl:call-template name="ListSurnameStartsWith">
    <xsl:with-param name="character" select="$currToken"/>
  </xsl:call-template>
</xsl:for-each>

What should I be using inside the 'select' attribute to ensure that i get 'A' and not some other value.

Some options I've tried, debugging in Visual Studio 2013, are:
<xsl:variable name="currToken">
  <xsl:value-of select="."/>
</xsl:variable>

This gives me:
$currToken	{Dimension:[1]}
    [1]	/
        node()[1]	A


'select="./node()"' gives me the same answer.
'select="./node()[1]"' gives me the same answer.

I haven't had any help from Google, as I can't seem to ask the right question, or nobody's doing this.

What do I need to put into the select to actually get the character A.
GeneralRe: XSLT passing a variable to starts-with Pin
Richard Deeming17-Feb-17 2:48
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GeneralRe: XSLT passing a variable to starts-with Pin
bjmallon20-Feb-17 23:55
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GeneralRe: XSLT passing a variable to starts-with Pin
Richard Deeming21-Feb-17 2:42
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GeneralRe: XSLT passing a variable to starts-with Pin
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QuestionHow to generate XML file with serialisation in vb.net Pin
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