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AnswerRe: How to access GUI from another thread? Pin
Ralf Meier11-Feb-21 10:36
professionalRalf Meier11-Feb-21 10:36 
AnswerRe: How to access GUI from another thread? PinPopular
Luc Pattyn11-Feb-21 11:29
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GeneralRe: How to access GUI from another thread? Pin
Eddy Vluggen11-Feb-21 14:01
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GeneralRe: How to access GUI from another thread? Pin
Alex Dunlop11-Feb-21 18:18
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GeneralRe: How to access GUI from another thread? Pin
Alex Dunlop11-Feb-21 19:39
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GeneralRe: How to access GUI from another thread? Pin
Alex Dunlop11-Feb-21 18:16
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QuestionJsonConvert.DeserializeObject Pin
Member 1449252210-Feb-21 21:43
MemberMember 1449252210-Feb-21 21:43 
AnswerRe: JsonConvert.DeserializeObject Pin
OriginalGriff10-Feb-21 22:05
mveOriginalGriff10-Feb-21 22:05 
Your JSON does not match the class, which is probably why you get a problem. If I run your JSON through a class creator (Convert JSON to C# Classes Online - Json2CSharp Toolkit[^]) then what I get is three classes:
// Root myDeserializedClass = JsonConvert.DeserializeObject<Root>(myJsonResponse); 
    public class _201506301400001    {
        public string contacto { get; set; } 
        public string telefono { get; set; } 
        public string email { get; set; } 
        public string notas { get; set; } 
    }

    public class _201506301400011    {
        public string contacto { get; set; } 
        public string telefono { get; set; } 
        public string email { get; set; } 
        public string notas { get; set; } 
    }

    public class Root    {
        [JsonProperty("20150630140000#1")]
        public _201506301400001 _201506301400001 { get; set; } 
        [JsonProperty("20150630140001#1")]
        public _201506301400011 _201506301400011 { get; set; } 
    }
Which is what I would expect from that: two different classes with identical content but different names!

I'd start by looking at the data source - I'd expect an array of JSON data containing two elements, not two individual items.
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AnswerRe: JsonConvert.DeserializeObject Pin
Member 1449252211-Feb-21 4:13
MemberMember 1449252211-Feb-21 4:13 
AnswerRe: JsonConvert.DeserializeObject Pin
James Curran11-Feb-21 23:58
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QuestionBackGroundWorker gives runtime error Pin
Alex Dunlop10-Feb-21 4:13
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AnswerRe: BackGroundWorker gives runtime error Pin
OriginalGriff10-Feb-21 4:36
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GeneralRe: BackGroundWorker gives runtime error Pin
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GeneralRe: BackGroundWorker gives runtime error Pin
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GeneralRe: BackGroundWorker gives runtime error Pin
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GeneralRe: BackGroundWorker gives runtime error Pin
OriginalGriff12-Feb-21 2:11
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GeneralRe: BackGroundWorker gives runtime error Pin
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AnswerRe: BackGroundWorker gives runtime error Pin
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GeneralRe: BackGroundWorker gives runtime error Pin
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GeneralRe: BackGroundWorker gives runtime error Pin
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