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The compiler knows how he stores every variable.
The programmer of that compiler just parses for an explicit cast (like (int)myvar) and then says: well, I have to shove these first bits into a new integer-style, then turn them around and here we go....
Casting is all about conversion between different bit arrangements.
Everything is stored as bits in your memory. By declaring variables or designing your class, you also did a description of how these objects or whatever are stored in memory.
Of course, for SOME types, there is no logical conversion. It DOES NOT MAKE SENSE to cast a string into an integer or the other way round.
In these cases, you need to PARSE your stuff, which takes much longer (microcode-wise) than simply rearraning your bits in a given pattern.
Really, just think about it. Everything is bits. You have an signed integer and want to cast it into an unsigned long. What do you have to do?
basically, substract one, then xor with all ones (like 01010011 ^ 11111111)
you then have the "normal" representation of your number, now just remove the sign and...
And so on.
Computers work by rules. If you know these rules, you just have to write them down into a program.
Still, writing a compiler is something I wish I never have to do.
Cheers
Sebs
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 Thanks Sebs, this gives some insight. Pretty helpful. ![Rose | [Rose]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/rose.gif)
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Thx!
We just need a dynamic array but not a ArrayList
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I don´t know what are you exactly looking for (same as leppie)
but there is a IList available, which could dynamicly take objects.
using System.Collections is necessary!
Ciao
Norman-Timo
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Hi,
I want to do lot of Drawing,in my application.I am Doing that on Panel Control palced on Form.One requirement is i want to connect two UserControls on the panel with the line.When UserControls are moved by user line between them should be adjusted accordingly.That line should be Clickable as well so that user will Click on that line and adust the position of that line by draging it,or even he can delete that line.
If i draw that line with CreateGraphics().DrawLine,it will not be clickable??
How can i do this??
Thanks,
TusharM
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hi,
i can smell new visio here.....
**************************
S r e e j i t h N a i r
**************************
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Firstly, just to say.. I've got some experience in C#, mainly scripting components for a MMORPG Emu, so I understand a decent variety of concepts in the language.
However recently I decided to.. ahem.. expand my horizons and branch into outside applications in C#, namely Windows Forms in this case.
I've sort of hit a road block early on with generating the components of my form.
using System;<br />
using System.Windows.Forms;<br />
using System.Drawing;<br />
<br />
namespace Waverian.ScriptGenerator<br />
{<br />
public class ScriptGenForm : Form<br />
{<br />
public ScriptGenForm()<br />
{<br />
InitializeComponent();<br />
<br />
Button b1 = new Button();<br />
b1.Height = 10;<br />
b1.Width = 25;<br />
b1.Text = "Text";<br />
b1.Location = new Point( 15, 15 );<br />
}<br />
<br />
[STAThread]<br />
public static void Main(string[] args)<br />
{<br />
Application.Run(new ScriptGenForm());<br />
}<br />
<br />
#region Windows Forms Designer generated code<br />
private void InitializeComponent()<br />
{<br />
this.AutoScaleBaseSize = new System.Drawing.Size(5, 13);<br />
this.ClientSize = new System.Drawing.Size(292, 266);<br />
this.Text = "Waverian's Script Generator";<br />
this.Name = "ScriptGenForm";<br />
}<br />
#endregion<br />
}<br />
}
The problem is, even though I've created a button b1, and thought I'd placed it correctly ( in defining location ), when I run the program it only displays the form itself, and not the button.
I've also tried adding components within the InitializeComponent() method, but that also did not produce the button. -.-
Could anybody enlighten me in to how ( or where. I'd assume it was in the constructor ) I'd place a component such as a button?
Cheers,
Waverian.
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hi,
See after creating the control instance you need to add this control to forms(base) controls collection.
Button b1 = new Button();
b1.Height = 10;
b1.Width = 25;
b1.Text = "Text";
b1.Location = new Point( 15, 15 );
this.Controls.Add(b1);
try this 
**************************
S r e e j i t h N a i r
**************************
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I need to allow my application to only be run once. I presume I need to set some sort of system wide flag to do this ?
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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Okay, my project is almost finished and this seems to be the last bug. My error is on line 613 during the last 'while' code. It seems that garbage collection has 'dumped' my initial 'hash' instance??? I then get the error message "Object reference not set to an instance of ans object."!
Q. How do I fix the code to eliminate the error???
try
{
while((line = reader.ReadLine()) != null)
{
string [] tmp = line.Split('\t');
if(tmp.Length == 2)
{
if(!hash.Contains(tmp[0]))
{
hash.Add(tmp[0], tmp[1]);
}
listBox1.Items.Add(tmp[0] + "\t" + tmp[1]);
}
}
}
finally
{
reader.Close();
}
while(myReader2.Read())
{
if (! hash.ContainsKey(str_col_DestIP.Trim()))
{
string strDestDns = "Use Other...";
}
else
{
string str = (hash[1].ToString()); // line 613
}
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It would seem that your Hashtable (I'm assuming that's what 'hash' is) does not have an object stored at the index you're trying to retrieve. Did you mean to say hash[0].ToString()? Or possibly whatever you're reading in the first while loop contains only one line.
These are only guesses, as not enough code is posted for a definitive answer. The garbage collector won't collect something you still hold a reference to. It's not the hash that's null, though, so that wouldn't be it anyway.
Charlie
if(!curlies){ return; }
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There wouldn't be an item at any index: a Hashtable is not a collection or a list (but can expose them through properties and methods). Coding hash[1] would only work if an object was added to the Hashtable using the integer (Int32, unless otherwise cast) value 1 for the key.
Software Design Engineer
Developer Division Sustained Engineering, Microsoft
My Articles
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D'oh! 
Charlie
if(!curlies){ return; }
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No, your hash variable is fine (you should really use a debugger and examine the state of variables in your Autos or Locals window). It's because hash[1] is returning null, which you're trying to call ToString on. Unrolling it, it would look something like this:
object o = hash[1];
o.ToString(); If you added "1" to your Hashtable, then you need to pass "1" - not 1 - to your indexer. They are very different (see the documentation for GetHashCode on any class).
If you're trying to index the second element (remember that in .NET indexes are 0-based) of the Hashtable, you're out of luck. Hash tables don't sort their collections - they use hash keys to store and reference data. You should do a search on google or something for basic theory on hash tables to find out more.
There's never a good reason for NullReferenceException to be thrown, either. When there's a chance that a variable may be null, check it. Even if you could access items like a collection, assuming that's there 2 - or even 1 - element is a bogus assumption. What if the file was empty and you didn't collect any data? There would be nothing in your Hashtable. It would simply be empty.
Software Design Engineer
Developer Division Sustained Engineering, Microsoft
My Articles
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While adding the object in the HashTable hash you have used
hash(tmp[0], tmp[1])
where tmp[0] is a string and also the key value for string object tmp[1]
where as while accessing the hash value you are using hash[1], here key u r using as int (value 1). This is the cause of the error.
Replace the line 613 as below.
if(hash.ContainsKey("1"))
{
string str = hash["1"].ToString();
}
Regards,
Jay
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Well, to draw on a panel, i use:
Graphics pg = panel.CreateGraphics();
pg.FillEllipse( new SolidBrush( Color.Black ), e.X, e.Y,2,2);
Its draw, but, when i minimize the form, the panel is clear!
What can i do to not clear the draw?
Thanks.
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Anytime a window is moved off screen, minimized, or is obstructed from view (by another window) it needs to be repainted then next time it is shown.
In order for your graphics to survive this process, the drawing code needs to be called in response to the Paint event of the control in question (or in an override of OnPaint for a derived control).
Also, when you move the code you posted to the Paint event handler, use the Graphics object supplied in the PaintEventHandler parameter instead of calling CreateGraphics.
Charlie
if(!curlies){ return; }
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You need to modify your code as below:
private void panel1_Paint(object sender, System.Windows.Forms.PaintEventArgs e)
{
Graphics pg = e.Graphics;
pg.DrawEllipse(new Pen(Color.Black ), 0, 0,
this.panel1.Width,this.panel1.Height);
pg.FillEllipse( new SolidBrush( Color.Red ), 0, 0,
this.panel1.Width, this.panel1.Height);
}
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In this way, how i ll get the mouse position to draw?
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Moon Boy wrote:
In this way, how i ll get the mouse position to draw?
Thats windows job! Not yours....
top secret xacc-ide 0.0.1
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Hi MoonBoy,
You want me to write the entire code and logic, then below is it:
int mouseX =0, mouseY =0;
private void panel1_Paint(object sender, System.Windows.Forms.PaintEventArgs e)
{
Graphics pg = e.Graphics;
pg.DrawEllipse(new Pen(Color.Black ), mouseX, mouseY, 50,50);
pg.FillEllipse( new SolidBrush( Color.Red ),mouseX, mouseY, 50, 50);
}
private void panel1_MouseUp(object sender, System.Windows.Forms.MouseEventArgs e)
{
this.mouseX = e.X;
this.mouseY = e.Y;
this.panel1.Invalidate();
}
Do revert back whether it could solve your purpose or not?
Regards,
Jay.
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Hi,
I am learning C# Express and have hit a roadblock with UserControl.
What is the minimum set of steps needed to create and display a dialog derived from UserControl?
So far, I think that I have created a form derived from UserControl.
From the IDE:
Project > Add Windows Form > User Control
This gives me a form and a .cs file.
namespace MyPropertiesDialog
{
public partial class MyPropertiesControl : UserControl
{
public MyPropertiesControl()
{
InitializeComponent();
}
private void MyPropertiesControl_Load(object sender, EventArgs e)
{
}
}
}
How do I invoke this dialog from the main application??
Since this works for message box,
MessageBox.Show("Hello!", "Greeting Box", MessageBoxButtons.OK,
MessageBoxIcon.Exclamation);
I tried variations on this theme, but no success yet.
Thanks for your help,
Mark
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It's a UserControl, so for example you could place a series of Button's on it that have specific functionality and then make sure your Form class accesses the Controls collection and Add's your control, then it should work. Do you have something specific you are trying to do?
- Nick Parker
My Blog | My Articles
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