Regular Expressions Discussion Boards

Member 1489067816-Sep-21 3:50

16-Sep-21 3:50

I have this regex to replace accents but it fails if the text contains "|".
string Text = "word|word2";

// Regex.
System.Text.RegularExpressions.Regex replace_a_Accents = new System.Text.RegularExpressions.Regex("[á|à|ä|â]", System.Text.RegularExpressions.RegexOptions.Compiled);
System.Text.RegularExpressions.Regex replace_e_Accents = new System.Text.RegularExpressions.Regex("[é|è|ë|ê]", System.Text.RegularExpressions.RegexOptions.Compiled);
System.Text.RegularExpressions.Regex replace_i_Accents = new System.Text.RegularExpressions.Regex("[í|ì|ï|î]", System.Text.RegularExpressions.RegexOptions.Compiled);
System.Text.RegularExpressions.Regex replace_o_Accents = new System.Text.RegularExpressions.Regex("[ó|ò|ö|ô]", System.Text.RegularExpressions.RegexOptions.Compiled);
System.Text.RegularExpressions.Regex replace_u_Accents = new System.Text.RegularExpressions.Regex("[ú|ù|ü|û]", System.Text.RegularExpressions.RegexOptions.Compiled);

// Reemplaza.
Texto_Retorno = replace_a_Accents.Replace(Texto_Retorno, "a");
Texto_Retorno = replace_e_Accents.Replace(Texto_Retorno, "e");
Texto_Retorno = replace_i_Accents.Replace(Texto_Retorno, "i");
Texto_Retorno = replace_o_Accents.Replace(Texto_Retorno, "o");
Texto_Retorno = replace_u_Accents.Replace(Texto_Retorno, "u");

Re: regex to replace accents

Richard Deeming16-Sep-21 4:28

Richard Deeming

16-Sep-21 4:28

Why would you use a Regex for something so simple?

bool replacedAny = false;
char[] characters = Texto_Retorno.ToCharArray();
for (int index = 0; index < characters.Length; index++)
{
    switch (characters[index])
    {
        case 'á':
        case 'à':
        case 'ä':
        case 'â':
        {
            characters[index] = 'a';
            replacedAny = true;
            break;
        }
        case 'é':
        case 'è':
        case 'ë':
        case 'ê':
        {
            characters[index] = 'e';
            replacedAny = true;
            break;
        }
        case 'í':
        case 'ì':
        case 'ï':
        case 'î':
        {
            characters[index] = 'i';
            replacedAny = true;
            break;
        }
        case 'ó':
        case 'ò':
        case 'ö':
        case 'ô':
        {
            characters[index] = 'o';
            replacedAny = true;
            break;
        }
        case 'ú':
        case 'ù':
        case 'ü':
        case 'û':
        {
            characters[index] = 'u';
            replacedAny = true;
            break;
        }
    }
}

if (replacedAny)
{
    Texto_Retorno = new string(characters);
}

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

modified 16-Sep-21 10:54am.

Re: regex to replace accents

Richard MacCutchan16-Sep-21 4:44

Richard MacCutchan

16-Sep-21 4:44

characters[index] = '3'; // ??

Re: regex to replace accents

Richard Deeming16-Sep-21 4:55

Richard Deeming

16-Sep-21 4:55

Nothing to see here. :innocent-whistle-smily:

In my defence, "3" is directly above "e" on the keyboard. Laugh | :laugh:

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: regex to replace accents

Richard MacCutchan16-Sep-21 5:05

Richard MacCutchan

16-Sep-21 5:05

Given some of the nonsense that appears when I type too fast I think you do very well.

Re: regex to replace accents

Member 1489067816-Sep-21 5:38

Member 14890678

16-Sep-21 5:38

I was dreading it, Regex doesn't do the job and doesn't replace either?

Re: regex to replace accents

Richard Deeming16-Sep-21 5:54

Richard Deeming

16-Sep-21 5:54

Regex can do the job. But running five+ separate regex operations on a string just to replace a few letters with their unaccented alternatives is overkill.

The other option, which is even nastier and less obvious, is to use Unicode normalization:

static string RemoveDiacritics(string stIn)
{
    string stFormD = stIn.Normalize(NormalizationForm.FormD);
    StringBuilder sb = new StringBuilder();

    for(int ich = 0; ich < stFormD.Length; ich++) 
    {
        UnicodeCategory uc = CharUnicodeInfo.GetUnicodeCategory(stFormD[ich]);
        if (uc != UnicodeCategory.NonSpacingMark) 
        {
            sb.Append(stFormD[ich]);
        }
    }

    return sb.ToString().Normalize(NormalizationForm.FormC);
}

string input = "Príliš žlutoucký kun úpel dábelské ódy.";
string result = RemoveDiacritics(input); // "Prilis zlutoucky kun upel dabelske ody."

Source[^]

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: regex to replace accents

Member 1489067816-Sep-21 5:39

Member 14890678

16-Sep-21 5:39

case 'Á' case 'À' case 'Ó' ... to be continue

Re: regex to replace accents

Peter_in_278016-Sep-21 4:45

Peter_in_2780

16-Sep-21 4:45

In [...] groups (alternatives) you don't want the |s.
[aeiou] as a regex will match any vowel, for example.

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

Regex Match with Multiple Words, I need you to not use leading and trailing spaces.

Member 1489067816-Sep-21 3:07

Member 14890678

16-Sep-21 3:07

I use Regex match to find multiple words in Like mode (start and end point). I do not want the return to include the space as the first position and I do not want the final space to count as valid.

Regular Expression: "\b(?:.Road.|.ous.|.Street.)\b" Must Return: Match:9 length:5 End:13
Text: "have one house free."

Trying to match a string with many backslashes

Florian Rammler31-Aug-21 1:35

Florian Rammler

31-Aug-21 1:35

Hello there, I have a string that looks like this

XML

\abc\rvr\sad\dqwdwq Some text  \rfdqwdvr\rtgevr\rgwvrr\23rvrv Some text \rffewvr\rfewvr\rvfewrr\rvrwefewv

I want to match the parts of the string that are connected by the backslashes. I partially achieved this with

XML

[\\][A-z0-9]+

but this only matches the first one. How can I match every part with backslashes in this string?

Thanks

modified 31-Aug-21 8:08am.

Re: Trying to match a string with many backslashes

Richard Deeming31-Aug-21 2:55

Richard Deeming

31-Aug-21 2:55

Assuming you want to extract three strings:

\abc\rvr\sad\dqwdwq
\rfdqwdvr\rtgevr\rgwvrr\23rvrv
\rffewvr\rfewvr\rvfewrr\rvrwefewv

Try:

RegEx

([\\][A-Za-z0-9]+)+

Regexper[^]

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Regex to match exact word and dash symbol

Member 1533502224-Aug-21 9:28

Member 15335022

24-Aug-21 9:28

hi would any one have a regex that would match (aug -) or(july -) or (june -)without the brackets
but would not match just (aug)or (july) or (june)
So far i have
\W*((?i)aug -(?-i))\W*
but this also matches aug which i dont want thanks

Re: Regex to match exact word and dash symbol

OriginalGriff24-Aug-21 9:32

OriginalGriff

24-Aug-21 9:32

I tried your regex in Expresso, and it matches "hello aug -goodbye" but not "hello aug goodbye".
So ... what are you talking about?

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Re: Regex to match exact word and dash symbol

Member 1533502224-Aug-21 10:00

Member 15335022

24-Aug-21 10:00

im using regex in placemint for placement of window and brousers
if i title a folder aug placemint macthes it , but i only want match on aug -

Re: Regex to match exact word and dash symbol

User 1521787324-Aug-21 17:47

User 15217873

24-Aug-21 17:47

Im no ideas what should be captured, so Im guessing that it should include alternates like...
\W*(?i)((?:aug|july|june)(?-i) -)\W*

Except that both \W* are redundant since they allow 0-occurrences, so they dont alter any matched text.
Its best to include samples to keep the experts from guessing, so I will try to save them some troubles...

Capture 'aug' or 'July' or 'JUNE' as whole words if followed by: 1-space, 1-hyphen, 0-or-1 space, and a 1-or-2 digit word.
.*\W(?i)(aug|july|june(?-i)) - ?\d{1,2}\W.*

Capture 'aug -' or 'July -' or 'JUNE -' with the same conditions...
.*\W(?i)((?:aug|july|june(?-i)) -) ?\d{1,2}\W.*

Capture 'aug -##' or 'July - ##' or 'JUNE - ##' with the same conditions...
.*\W(?i)((?:aug|july|june(?-i)) - ?\d{1,2})\W.*

Capture 'aug -' or 'July -' or 'JUNE -' as whole words, but only if - is followed by a non-word character like %.
This does seem the most unlikely, but Im trying to copy your original match, because no samples are being posted...
.*\W(?i)((?:aug|july|june)(?-i) -)\W.*

If none of these match properly, you should include samples of your text lines, and say what should be captured.
There is many experts who is not even going to answer, without first seeing some samples.

modified 5-Oct-21 21:01pm.

Re: Regex to match exact word and dash symbol

Member 1533502224-Aug-21 22:57

Member 15335022

24-Aug-21 22:57

Thanks for trying to help me with this, im a complete novice with regex
i am trying to capture 'aug -' or 'July -' or 'JUNE -'

sentance 'the aug' = would not match
sentance 'aug1' = would not match
sentance 'aug -2' = would not match
sentance 'aug -' = would match

Re: Regex to match exact word and dash symbol

User 1521787324-Aug-21 23:32

User 15217873

24-Aug-21 23:32

Im guessing that you posted 4 complete samples, and that 'sentance' means 1 whole line?...
\b(?i)((?:aug|july|june)(?-i) -)$

modified 5-Oct-21 21:01pm.

Re: Regex to match exact word and dash symbol

Member 1533502224-Aug-21 23:37

Member 15335022

24-Aug-21 23:37

yes thanks sentance means 1 whole line,
i tried \b(?i)((?:aug|july|june)(?-i) -)$
but its not matching anything

Re: Regex to match exact word and dash symbol

User 1521787325-Aug-21 0:08

User 15217873

25-Aug-21 0:08

Its a PCRE regex to capture text just like your 4th-sample, so matching any lines that end like...
aug -

Maybe you're using something else?? Not using $1 or \1 for replace?? Not giving full samples??

modified 5-Oct-21 21:01pm.

Re: Regex to match exact word and dash symbol

Member 1533502225-Aug-21 0:24

Member 15335022

25-Aug-21 0:24

example i use
\W*((?i)ALARM CLOCK(?-i))\W*
so any window that says alarm clock is placed at same position on desktop

Re: Regex to match exact word and dash symbol

User 1521787325-Aug-21 1:11

User 15217873

25-Aug-21 1:11

Without full samples relating to your posted question, Im really afraid nobody is going to help you.
This site shows how my regex matches what you said needs to matched.
https://regex101.com/r/cH4Jrg/1

Feel free to experiment with it, if that's easier than trying to describe what should be matched.

modified 5-Oct-21 21:01pm.

Problem capturing last group in a line: CLOSED

mo149222-Aug-21 13:18

mo1492

22-Aug-21 13:18

Don't know if this is the correct solution but it seems to work.
Using the RegexOptions.RightToLeft option seems to work.

I'm not too familiar with Regex. I've created an expression to capture data in a line and it works except for the last group DataType which does not extract the value "dtText". Can someone help?
Thank You

Expression:
FieldName=(?<FieldName>.*?),ColumnWidth=(?<ColumnWidth>.*?),Size=(?<Size>.*?),DataType=(?<DataType>.*?)

Data:
FieldName=Field1,ColumnWidth=50,Size=10,DataType=dtText

Output:
FieldName: [Field1]
ColumnWidth: [50]
Size: [10]
DataType []

-- modified 22-Aug-21 19:28pm.

Re: Problem capturing last group in a line: CLOSED

Richard Deeming22-Aug-21 21:46

Richard Deeming

22-Aug-21 21:46

.*? tells the expression to capture as little as possible. Since there's nothing to match after the last expression, the least it can capture is nothing, so that's precisely what it does.

If you're looking to capture everything up to the end of the line, then you'll want to add an end-of-line anchor:

RegEx

...,DataType=(?<DataType>.*?)$

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: Problem capturing last group in a line: CLOSED

mo149223-Aug-21 6:17

mo1492

23-Aug-21 6:17

Thank you for your help Smile | :)

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