C # running a program through a shortcut using processstartinfo process

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Столкнулся с проблемой запуска программы через ярлык(.lnk)
с помощью ProcessStartInfo Process

Получается так что запуская ярлык(.lnk) программы
"C:\Program Files\Notepad++\notepad++.exe" ,
Process отказываеться запускать программу.

Если запустить программу по прямому пути
"C:\Program Files\Notepad++\notepad++.exe" ,
Process запускает программу.

Translation:
Faced the problem of starting the program through a shortcut (.lnk)
using ProcessStartInfo Process

It turns out that by launching the shortcut (.lnk) of the program
"C: \ Program Files \ Notepad ++ \ notepad ++. Exe",
Process refuses to run the program.

If you run the program in a direct way
"C: \ Program Files \ Notepad ++ \ notepad ++. Exe",
Process starts the program.

What I have tried:

В качестве альтернативы запуска был использован AIMP.
Process запускает программу как через ярлык(.lnk) так и по прямому пути
"C:\Program Files (x86)\AIMP\AIMP.exe"

procStart.7z / Облако Mail.ru[^]

procStart.7z — Yandex.Disk[^]

Translation:
AIMP was used as an alternative to launch.
Process launches the program both through the shortcut (.lnk) and along the direct path
"C: \ Program Files (x86) \ AIMP \ AIMP.exe"

Posted 27-May-20 7:38am

Mesartim

Updated 28-May-20 15:56pm

Richard Deeming

v5

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ZurdoDev 27-May-20 14:57pm

English

Maciej Los 27-May-20 15:48pm

This is English forum. Please, use English.
BTW: No one would like to download suspicious files.

Mesartim 28-May-20 22:45pm

"BTW: No one would like to download suspicious files."
Why then do you need antivirus programs if you are afraid to download. It would be even more convenient to view the code by downloading the source code and open it in the studio.

2 solutions

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Maciej Los · Answer 1 · 2020-05-27T09:57:00

Solution 1

Try this:

C#

Process proc = new Process();
proc.StartInfo.FileName = @"c:\myShortcut.lnk";
proc.UseShellExecute = false;
proc.Start();

Posted 27-May-20 9:57am

Maciej Los

Comments

Pete O'Hanlon 28-May-20 3:22am

My 5

Maciej Los 28-May-20 3:59am

Thank you, Pete.

Mesartim · Answer 2 · 2020-05-28T15:57:00

Quote:
Apparently Process cannot distinguish the location of the file if you run the program through a shortcut (.lnk)
Because with the path to the file "C: \ Program Files" in the shortcut (.lnk) in the x64 system
Process will return the value "C: \ Program Files (x86)" and give the error "The specified path does not exist."
what does not appear in the message for the shortcut processInfo.ErrorDialog = true;
img-2020-05-28-08-30-40.png — Yandex.Disk[^]

string program_files_folder = Environment.Is64BitProcess ?
    Environment.GetFolderPath(Environment.SpecialFolder.ProgramFiles) :
    Environment.GetEnvironmentVariable("ProgramW6432");
string programFilesX86 = Environment.GetFolderPath(Environment.SpecialFolder.ProgramFilesX86);