A RETURN statement with a return value cannot be used in this context.

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SQL-Server-2005

SQL

create function Age(@date datetime)
return
as
begin
	DECLARE  @tmpdate datetime, @years int, @months int, @days int, @age varchar(12)
--	declare @date datetime
--		set	@date='12/29/04'
	SELECT @tmpdate = @date
	SELECT @years = DATEDIFF(yy, @tmpdate, GETDATE()) - 
		CASE WHEN (MONTH(@date) > MONTH(GETDATE())) OR (MONTH(@date) = MONTH(GETDATE()) AND DAY(@date) > DAY(GETDATE())) THEN 1 ELSE 0 END

	SELECT @tmpdate = DATEADD(yy, @years, @tmpdate)

	SELECT @months = DATEDIFF(m, @tmpdate, GETDATE()) - 
		CASE WHEN DAY(@date) > DAY(GETDATE()) THEN 1 ELSE 0 END

	SELECT @tmpdate = DATEADD(m, @months, @tmpdate)
	SELECT @days = DATEDIFF(d, @tmpdate, GETDATE())
	set @age= Convert(varchar(12),(cast (@years as varchar(2)) + '-'+ cast(@months as varchar(2))+'-'+ cast(@days as varchar(4))),11) 
--	select @age
	return @age
end

I would like to create function which gives the output from the given date and compare it with today and give output date.

Posted 11-Dec-12 20:56pm

Patel Shailendra

Updated 11-Dec-12 20:59pm

André Kraak

v2

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Dain Ucak · Answer 1 · 2012-12-11T21:04:00

you need to improve your query.
change your return statement like returns [datatype]

i changed it

SQL

create function Age(@date datetime)
returns datetime-- your problem was here
as
begin
DECLARE @tmpdate datetime, @years int, @months int, @days int, @age varchar(12)
--  declare @date datetime
--   set    @date='12/29/04'
SELECT @tmpdate = @date
SELECT @years = DATEDIFF(yy, @tmpdate, GETDATE()) -
CASE WHEN (MONTH(@date) > MONTH(GETDATE())) OR (MONTH(@date) = MONTH(GETDATE()) AND DAY(@date) > DAY(GETDATE())) THEN 1 ELSE 0 END

SELECT @tmpdate = DATEADD(yy, @years, @tmpdate)

SELECT @months = DATEDIFF(m, @tmpdate, GETDATE()) -
CASE WHEN DAY(@date) > DAY(GETDATE()) THEN 1 ELSE 0 END

SELECT @tmpdate = DATEADD(m, @months, @tmpdate)
SELECT @days = DATEDIFF(d, @tmpdate, GETDATE())
set @age= Convert(varchar(12),(cast (@years as varchar(2)) + '-'+ cast(@months as varchar(2))+'-'+ cast(@days as varchar(4))),11)
--  select @age
return @age
end

OriginalGriff · Answer 2 · 2012-12-11T21:06:00

Solution 2

You need to declare the return type of your function:

SQL

create function Age(@date datetime)
RETURNS VARCHAR(12)
as

Posted 11-Dec-12 21:06pm

OriginalGriff