why i don´t get a number?

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PHP

$result = mysql_query("SELECT titel, COUNT(titel) AS numbers FROM users WHERE accid = '$showid'") or die (mysql_error());
$row = mysql_fetch_array($result);
echo $row ['numbers'];

$showid is available.
I don´t get an error.
In the database are two entries.
But it always shows 0 *cunfused*

Posted 10-Jan-13 10:54am

Chi Ller

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2 solutions

Solution 1

You either select an aggregate on it's own (select count(*) from table), or an aggregate based on some grouping (select field, count(*) from table group by field). Your query makes no real sense, since you can not select a row and an aggregate in the same query.

Posted 10-Jan-13 11:00am

Zoltán Zörgő

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Chi Ller 10-Jan-13 17:01pm

You mean this should work:
$result = mysql_query("SELECT COUNT(*) AS numbers FROM users WHERE accid = '$showid'") or die (mysql_error());
$row = mysql_fetch_array($result);
echo $row ['numbers'];

Zoltán Zörgő 10-Jan-13 17:02pm

Is should.

Chi Ller 10-Jan-13 17:04pm

But the number is also 0 instead of 2

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Christian Graus · Accepted Answer · 2013-01-10T11:01:00

Solution 2

titel ?

This SQL should not run. If you're doing a count, you need a group by in order to select individual values, to.

SELECT titel, COUNT(titel) AS numbers FROM users WHERE accid = '$showid' group by titel

Also, I think this will look for $showid as a string in your database, are you sure that's what you want ? I think you want this value to look something up from the form, and I don't think it will, as it stands.

Posted 10-Jan-13 11:01am

Christian Graus

Comments

Chi Ller 10-Jan-13 17:03pm

But now it shows nothing
Yes I need accid = '$showid' because different people can use it and for everyone I want to show only his entrys

Christian Graus 10-Jan-13 17:06pm

I think that this will pass the string '$showid' to the SQL, and not pass through any sort of id.

Chi Ller 10-Jan-13 17:08pm

ok you´re right. Without $showid it works. But now how can I just show the guy with the id 10 his number of entries?

Christian Graus 10-Jan-13 17:12pm

I don't do PHP, but there has to be a way to look up that value, then pass it in to the SQL.

Chi Ller 10-Jan-13 17:14pm

ok thank you (: