My javaScript function is not working in content page

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My javascript function is following

JavaScript

var txtQuickMailSMS, flag = 0;
function ShowRichTextEditor(id) {
     if (flag == "0") {
         txtQuickMailSMS = new nicEditor({ fullPanel: true }).panelInstance(id);
         flag = 1;
     }
     else {
         txtQuickMailSMS.removeInstance(id);
         flag = 0;
         document.getElementById(id).value = "";
     }
    }

It is for convert multiline textbox like RichTextbox which has all the option like word (bold,italic,bgcolor,textcolor)
It is used page without master page. I call that function in body onload like following

HTML

<body  önload="ShowRichTextEditor('txtRemarks');">

But i want to create that page under masterpage. So in content page there are no master page.
So i give following code in content page pageload event

C#

HtmlGenericControl body = this.Master.FindControl("body") as HtmlGenericControl;
body.Attributes.Add("onload", "ShowRichTextEditor('txtRemarks');");

But it is not working. I give instead of
function to alert function , that is worked. But ShowRichTextEditor is not working.

Any one know the solution to solve this problem, please help me...

Posted 10-Apr-13 23:38pm

UshaCbe

Updated 11-Apr-13 0:33am

v5

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Comments

Matej Hlatky 11-Apr-13 6:04am

What is the exact problem?
Does the element with id txtRemarks exist in output HTML?
When generating elements in ASP.NET, you need to pass ClientID property to your client JS code.

1 solution

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Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) · Accepted Answer · 2013-04-11T00:13:00

Solution 1

Problems in code:-
Why have you written function ShowRichTextEditor(id) two times ?
And there is one closing bracket } which is extra.

Suggestion:-
You can use
1. jshint[^] to find out problems in your code.
2. FireBug Error Console window in Firefox to check all the script and css errors.

Try to make your javaScript code error free and then test.

Solution after discussion with OP
Actually the id will not be the same when you use Master Page.
The id will be no more txtRemarks, there will be one prefix added to this id.
You can check the html in browser.

So, the id will be _________txtRemarks.

For this you have to get the client id of that textbox like below...
<%= txtRemarks.ClientID %>

Else you can make that textbox ClientID Mode static, so that id will not change.

Refer -
1. Control.ClientID Property.
2. How do I pass a server control's actual client Id to a javascript function?.

Posted 11-Apr-13 0:13am

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ)

Updated 11-Apr-13 20:07pm

v2

Comments

UshaCbe 11-Apr-13 6:32am

The Bracket is missing When I copied. That's not a problem

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 11-Apr-13 6:36am

Have you used the jslint or Firebug ?
And put a debugger in the function and check what exactly is happening inside the function ?

UshaCbe 11-Apr-13 6:37am

But it is working with the page is without master page. When I used it inthe content page only that is not working.

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 11-Apr-13 7:14am

Ok, I got you now. Actually the id will not be the same when you use Master Page.
The id will be no more txtRemarks, there will be one prefix added to this id.
You can check the html in browser.

So, the id will be _________txtRemarks.

For this you have to get the client id of that textbox like below...
<%= txtRemarks.ClientID %>

Else you can make that textbox ClientID Mode static, so that id will not change.

Refer -
1. Control.ClientID Property.
2. How do I pass a server control's actual client Id to a javascript function?.

UshaCbe 12-Apr-13 0:50am

Hi i checked css used with firebug in that Name txtRemarks.ClientID it is working now thank u
And then I set ClientID mode Static also. Then only it is working. Thank u for your kind reply.

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 12-Apr-13 2:05am

Hi UshaCbe,

My pleasure. It is great to hear that your problem is solved.

And thanks for accepting the answer. I also reached 10K Authority points as you accepted the answer... So many many thanks to you... :)

Regards,
Tadit

UshaCbe 12-Apr-13 4:30am

No mention. your answer is working, So that i accept your answer. That is my duty.

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 12-Apr-13 4:48am

Oh okay okay... :) :) :) Thanks again...