getting Error on Substring in vb.net

Question

1.00/5 (1 vote)

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dim strMyString as string ="ABC POR BCS KOK SSS 6BC"
strMyString=strMyString.Substring(19)
strMyString=strMyString.Substring(2, 1).ToString

I need to find Only B Value which is in middle of Last String i.e 6BC
but i am getting eror on this line
strMyString.Substring(2, 1).ToString

Help me

Posted 5-Apr-14 1:45am

hareshdgr8

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Comments

DipAnikap 5-Apr-14 7:58am

Your string is fixed?

CHill60 5-Apr-14 8:50am

This code works and does not give an error. So presumably the string can vary (see comment from DipAnikap above). Peter Leow has given a good explanation of your problem in Solution 4. But what are you actually trying to achieve? Is it "find the last 'B' in any string" or "find the last occurrence of character X in any string Y"?

4 solutions

Solution 4

Your question is not complete.
If the "6BC" is present in the string, your program will work fine.
But if the "6BC" is absent, then your "strMyString=strMyString.Substring(19)" returns empty string, that is why "strMyString=strMyString.Substring(2, 1).ToString" throws error as there is no index 2.
There is no need to use ToString in the first place, but if you insist, then
ToString and ToString() are the same as in VB.NET you can omit the parentheses on any method that has no argument.

If your intention is to check if there is any "B" exists after index 19, then you can use lastindexof like the following example:

VB

dim strMyString as string ="ABC POR BCS KOK SSS 6aC"
dim index as integer =strMyString.LastIndexOf("B")
'strMyString=strMyString.Substring(2, 1).ToString
If index > 19 Then
    Console.WriteLine("There is B after index 19")
Else
    Console.WriteLine("There is no B after index 19")
End If

Test with B and no B and see how it works.

Posted 5-Apr-14 2:36am

Peter Leow

Updated 5-Apr-14 2:47am

v4

Comments

CHill60 5-Apr-14 8:47am

5'd. As you say, the OPs code as presented here does not throw the exception they mention.

Peter Leow 5-Apr-14 8:51am

Thanks Chill60. OP has something else in mind that was not mentioned in the question. The program as it stands is fine.

Solution 1

I think it should be

VB

strMyString=strMyString.Substring(2, 1).ToString() ' with parentheses

but why are you calling ToString on a string?

Posted 5-Apr-14 2:00am

Richard MacCutchan

Solution 2

Its ToString().
Try strMyString.Substring(2, 1).ToString().

Posted 5-Apr-14 2:03am

Abhinav S

Comments

hareshdgr8 5-Apr-14 8:12am

just converting value to string if its not there is no problem but it give me like starting index cannot be more than end index something like this..

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Schatak · Accepted Answer · 2014-04-05T02:09:00

Solution 3

if you need to find last B, then try to find last stirng as follow:

VB

Dim s As String = "ABC POR BCS KOK SSS 6BC"
        Dim i As Integer = s.LastIndexOf("6"c) + 1
        Dim part As String = s.Substring(i)
        lbl.Text = part

Posted 5-Apr-14 2:09am

Schatak

Updated 5-Apr-14 2:11am

v2