find distinct rows based on time difference

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SQL-Server-2008R2

Hi,
There is table. I want to fetch distinct record from that based on time difference. Table structure is as follows-

  A       B        C
FLM123  Down    1/8/2014 09:08
FLM124  Down    1/8/2014 11:08
FLM125  Down    1/8/2014 16:08
FLM126  UP      1/8/2014 12:08
FLM127  Bottom  1/8/2014 11:08
FLM128  Level   1/8/2014 10:08
FLM129  Matched 1/8/2014 12:08

Condition=> If Difference between time of two rows defined in column C group by A and B is greater than 4 hrs then eliminate one row from the result.

Result I want-

  A       B        C
FLM123  Down    1/8/2014 09:08
FLM125  Down    1/8/2014 16:08
FLM126  UP      1/8/2014 12:08
FLM127  Bottom  1/8/2014 11:08
FLM128  Level   1/8/2014 10:08
FLM129  Matched 1/8/2014 12:08

How to write a query for this result as I have thousands of record like this.
Please help.

Posted 27-May-14 4:04am

himanshu034

Updated 27-May-14 5:45am

Sergey Alexandrovich Kryukov

v2

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Comments

joshrduncan2012 27-May-14 10:17am

Help you with what? You haven't shown us any effort on your part first. What have you tried? Where are you stuck?

Sunasara Imdadhusen 28-May-14 1:38am

Correct, you should try to that and then ask for help if you really stuck.

Maciej Los 4-Mar-15 15:20pm

"If Difference between time of two rows defined in column C group by A and B is greater than 4 hrs" - in comparison to what record?

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Abdulnazark · Answer 1 · 2015-03-04T03:03:00

Use below query, it will work only Sqlserver 2012 or higher

SQL

SELECT a,b, c, LEAD(c) OVER (ORDER BY a) NextRow,datediff(HOUR,c,isnull(LEAD(c) OVER (ORDER BY a),c)) as TimeDiff
FROM #TestTable

see the link for Lead and Lag function

http://blog.sqlauthority.com/2013/09/22/sql-server-how-to-access-the-previous-row-and-next-row-value-in-select-statement/[^]